結果

問題 No.3316 Make 81181819 with only 0,1,or 8
コンテスト
ユーザー lif4635
提出日時 2025-10-31 22:23:19
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 61 ms / 6,000 ms
コード長 2,422 bytes
コンパイル時間 270 ms
コンパイル使用メモリ 82,660 KB
実行使用メモリ 69,348 KB
最終ジャッジ日時 2025-10-31 22:23:22
合計ジャッジ時間 3,086 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff #

# input
import sys
input = sys.stdin.readline
II = lambda : int(input())
MI = lambda : map(int, input().split())
LI = lambda : [int(a) for a in input().split()]
SI = lambda : input().rstrip()
LLI = lambda n : [[int(a) for a in input().split()] for _ in range(n)]
LSI = lambda n : [input().rstrip() for _ in range(n)]
MI_1 = lambda : map(lambda x:int(x)-1, input().split())
LI_1 = lambda : [int(a)-1 for a in input().split()]

mod = 998244353
inf = 1001001001001001001
ordalp = lambda s : ord(s)-65 if s.isupper() else ord(s)-97
ordallalp = lambda s : ord(s)-39 if s.isupper() else ord(s)-97
yes = lambda : print("Yes")
no = lambda : print("No")
yn = lambda flag : print("Yes" if flag else "No")
prinf = lambda ans : print(ans if ans < 1000001001001001001 else -1)
alplow = "abcdefghijklmnopqrstuvwxyz"
alpup = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
alpall = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
URDL = {'U':(-1,0), 'R':(0,1), 'D':(1,0), 'L':(0,-1)}
DIR_4 = [[-1,0],[0,1],[1,0],[0,-1]]
DIR_8 = [[-1,0],[-1,1],[0,1],[1,1],[1,0],[1,-1],[0,-1],[-1,-1]]
DIR_BISHOP = [[-1,1],[1,1],[1,-1],[-1,-1]]
prime60 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59]
sys.set_int_max_str_digits(0)
# sys.setrecursionlimit(10**6)
# import pypyjit
# pypyjit.set_param('max_unroll_recursion=-1')

from collections import defaultdict,deque
from heapq import heappop,heappush
from bisect import bisect_left,bisect_right
DD = defaultdict
BSL = bisect_left
BSR = bisect_right

from itertools import product


def calc(x, n):
    dig = [None] * 100
    for t in product([0, 1, 8], repeat=x):
        dig[sum(t)] = t
    
    def dfs(d, n):
        if d == -1:
            if n == 0:
                return [0] * x
            else:
                return None
        
        p, q = divmod(n, 10 ** d)
        for r in range(p - x, p + 1):
            if r < 0: continue
            if dig[r] == None: continue
            
            nn = q + (p - r) * 10 ** d
            res = dfs(d-1, nn)
            if res != None:
                res = [res[i] + dig[r][i] * 10 ** d for i in range(x)]
                return res
            
        return None
    r = dfs(9, n)
    return r
    


def solve(n):
    for x in range(1, 8):
        r = calc(x, n)
        if r != None:
            print(x)
            for p in r:
                print(p)
            return
        
t = II()
for i in range(t):
    n = 81181819 - II()
    solve(n)
0