結果
| 問題 | No.3477 Yet Another LIS Triangle |
| コンテスト | |
| ユーザー |
まぬお
|
| 提出日時 | 2026-03-31 03:29:24 |
| 言語 | PyPy3 (7.3.17) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,509 bytes |
| 記録 | |
| コンパイル時間 | 271 ms |
| コンパイル使用メモリ | 85,424 KB |
| 実行使用メモリ | 92,288 KB |
| 最終ジャッジ日時 | 2026-03-31 03:29:28 |
| 合計ジャッジ時間 | 3,603 ms |
|
ジャッジサーバーID (参考情報) |
judge1_0 / judge2_1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 18 WA * 4 |
ソースコード
from collections import deque, defaultdict, Counter
from bisect import bisect_left, bisect_right
from itertools import permutations, combinations, groupby
from heapq import heappop, heappush
import math, sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
def printl(li, sep=" "): print(sep.join(map(str, li)))
def yn(flag): print(Yes if flag else No)
_int = lambda x: int(x)-1
MOD = 998244353 #10**9+7
INF = 1<<60
Yes, No = "Yes", "No"
def rotate(st, k):
l = st[:k]
r = st[k:]
return r[::-1] + l
for _ in range(int(input())):
N, K = map(int, input().split())
if N == 2:
print(No)
continue
if N == 3:
if K == 2:
print(Yes)
print(6, 4, 5)
print(5, 2, 3)
print(3, 1, 6)
else:
print(No)
continue
if N == K or K == 1:
print(No)
elif K == 2:
print(Yes)
A = [1] + rotate([i for i in range(N+2, 2*N)], 0) + [N]
B = [N] + rotate([i for i in range(2*N+2, 3*N)], 0) + [2*N]
C = [2*N] + rotate([i for i in range(2, N)], 2) + [1]
printl(A)
printl(B)
printl(C)
else:
print(Yes)
A = [i+1 for i in range(N)]
A = [A[0]] + rotate(A[1:-1], K-2) + [A[-1]]
B = [i+N for i in range(N)]
B = [B[0]] + rotate(B[1:-1], K-2) + [B[-1]]
C = [i-1+2*N for i in range(N-1)] + [1]
C = [C[0]] + rotate(C[1:-1], K-1) + [C[-1]]
printl(A)
printl(B)
printl(C)
まぬお