結果
| 問題 | No.3505 Sum of Prod of Root |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-04-18 00:35:49 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.89.0) |
| 結果 |
AC
|
| 実行時間 | 293 ms / 2,000 ms |
| コード長 | 7,759 bytes |
| 記録 | |
| コンパイル時間 | 2,608 ms |
| コンパイル使用メモリ | 230,772 KB |
| 実行使用メモリ | 43,428 KB |
| 最終ジャッジ日時 | 2026-04-18 00:36:02 |
| 合計ジャッジ時間 | 4,990 ms |
|
ジャッジサーバーID (参考情報) |
judge3_0 / judge2_0 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 13 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
//入力が必ず-mod<=a<modの時.
template<const int mod> //mod<2^30.
struct modint{ //mod変更が不可能.
public:
long long v;
static void setmod(int m){} //飾り.
static constexpr long long getmod(){return mod;}
modint():v(0){}
template<typename T>
modint(T a):v(a){if(v < 0) v += mod;}
long long val()const{return v;}
modint &operator=(const modint &b) = default;
modint &operator+()const{return (*this);}
modint operator-()const{return modint(0)-(*this);}
modint operator+(const modint b)const{return modint(v)+=b;}
modint operator-(const modint b)const{return modint(v)-=b;}
modint operator*(const modint b)const{return modint(v)*=b;}
modint operator/(const modint b)const{return modint(v)/=b;}
modint &operator+=(const modint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
modint &operator-=(const modint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
modint &operator*=(const modint b){v = v*b.v%mod; return *this;}
modint &operator/=(modint b){ //b!=0 mod素数が必須.
assert(b.v != 0);
(*this) *= b.pow(mod-2);
return *this;
}
modint pow(long long n)const{
modint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
modint inv()const{return pow(mod-2);} //素数mod必須.
modint &operator++(){*this += 1; return *this;}
modint &operator--(){*this -= 1; return *this;}
modint operator++(int){modint ret = *this; *this += 1; return ret;}
modint operator--(int){modint ret = *this; *this -= 1; return ret;}
friend bool operator==(const modint a,const modint b){return a.v==b.v;}
friend bool operator!=(const modint a,const modint b){return a.v!=b.v;}
friend bool operator<(const modint a,const modint b){return a.v<b.v;}
friend bool operator<=(const modint a,const modint b){return a.v<=b.v;}
friend bool operator>=(const modint a,const modint b){return a.v>=b.v;}
friend bool operator>(const modint a,const modint b){return a.v>b.v;}
friend ostream &operator<<(ostream &os,const modint a){return os<<a.v;}
friend istream &operator>>(istream &is,modint &a){ //入力はmodをとってくれる.
long long x; is >> x; x %= mod;
a = modint(x); return is;
}
};
using mint = modint<998244353>; const long long mod = 998244353;
template<typename T>
bool chmin(T &a,T b){ //a>bならa=bに更新してtrue.
if(a > b){a = b; return true;}
else return false;
}
template<typename T>
bool chmax(T &a,T b){ //a<bならa=bに更新してtrue.
if(a < b){a = b; return true;}
else return false;
}
template<typename T>
T safemod(T a,T m){a %= m,a += m;return a>=m?a-m:a;} //return x = a mod m.
template<typename T>
T floor(T a,T b){ //return a/b切り下げ.
if(b < 0) a *= -1,b *= -1;
return a<0?(a+1)/b-1:a/b;
}
template<typename T>
T ceil(T a,T b){ //return a/b切り上げ.
if(b < 0) a *= -1,b *= -1;
return a>0?(a-1)/b+1:a/b;
}
template<typename T>
pair<T,T> invgcd(T a,T b){
//return {gcd(a,b),x} (xa≡g(mod b))
a = safemod(a,b);
if(a == 0) return {b,0};
T x = 0,y = 1,memob = b;
while(a){
T q = b/a;
b -= a*q;
swap(x,y); y -= q*x;
swap(a,b);
}
if(x < 0) x += memob/b;
return {b,x};
}
template<typename T>
bool isABmoreC(T a,T b,T c){ //a*b=cはfalse
if(c%b) return a>=ceil(c,b);
else return a>ceil(c,b);
}
template<typename T>
bool isABmoreC2(T a,T b,T c){return a>=ceil(c,b);} //a*b=cはtrue.
template<typename T>
bool isABlessC(T a,T b,T c){ //a*b=cはfalse.
if(c%b) return a<=floor(c,b);
else return a<floor(c,b);
}
template<typename T>
bool isABlessC2(T a,T b,T c){return a<=floor(c,b);} //a*b=cはtrue.
template<typename T>
T Kthpower(T a,int k){ //return a^k オーバーフローは考慮しない.
T ret = 1;
while(k){
if(k&1) ret *= a;
a *= a; k >>= 1;
}
return ret;
}
template<typename T>
pair<T,bool> Kthpower2(T a,int k){ //return {a^k,オーバーした?} オーバーフローは考慮する.
T ret = 1,maxv = numeric_limits<T>::max();
while(k){
if(k&1){
if(isABmoreC(ret,a,maxv)) return {-1,true};
ret *= a;
}
if(k == 1) break;
if(isABmoreC(a,a,maxv)) return {-1,true};
a *= a; k >>= 1;
}
return {ret,false};
}
template<typename T>
T Kthroot(T a,int k){ //return floor(a^(1/k));
assert(k > 0 && a >= 0);
if(k == 1 || a <= 1) return a;
T ret = pow(a,1.0/k);
while(true){
auto [check,over] = Kthpower2(ret+1,k);
if(over || check > a) break;
ret++;
}
while(true){
auto [check,over] = Kthpower2(ret,k);
if(!over && check <= a) break;
ret--;
}
return ret;
}
template<typename T>
T powmod(T a,T b,T m){//a^b(mod m)を返す.
assert(b >= 0);
__int128_t ret = 1,p = a;
while(b){
if(b&1) ret = ret*p%m;
p = p*p%m; b >>= 1;
}
return T(ret);
}
template<typename T>
T divmod(T a,T b,T m){//a/b(mod m)を返す 素数mod必須.
return (T)((__int128_t)a*powmod(b,m-2,m)%m);
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int Limit = 1001001; //Limit->必要なサイズ fac->x! facinv->1/x! inv->1/x.
vector<mint> fac(Limit+1,1),facinv(Limit+1);
{
int mod = mint::getmod(),invstart = min(mod-1,Limit);
for(int i=1; i<=Limit; i++) fac.at(i) = fac.at(i-1)*i;
facinv.at(invstart) = fac.at(invstart).inv();
for(int i=invstart-1; i>=0; i--) facinv.at(i) = facinv.at(i+1)*(i+1);
}
vector<mint> inv(Limit+1); for(int i=1; i<=Limit; i++) inv.at(i) = fac.at(i-1)*facinv.at(i); //必要なら解放.
const mint div2 = mint(1)/2,div6 = mint(1)/6,div30 = mint(1)/30;
auto range1 = [&](long long l,long long r) -> mint {
if(l > r) return 0;
mint b = r%mod,a = (l-1)%mod;
return b*(b+1)*div2-a*(a+1)*div2;
};
auto f = [&](long long x,int k) -> mint {
mint v = x%mod;
if(k == 2) return v*(v+1)*(v*2+1)*div6;
if(k == 3) return (v*(v+1)*div2).pow(2);
if(k == 4) return div30*v*(v+1)*(v*2+1)*(v*v*3+v*3-1);
cout << "AkaneKawaii" << endl;
assert(false);
};
auto range2 = [&](long long l,long long r) -> mint {
if(l > r) return 0;
mint ret = f(r,4)*2+f(r,3)*3+f(r,2);
ret -= f(l-1,4)*2+f(l-1,3)*3+f(l-1,2);
return ret;
};
long long N; cin >> N;
vector<pair<long long,long long>> sepa;
for(int k=3; ; k++){
long long v = 2;
for(; ; v++){
auto [l,over] = Kthpower2(v,k);
if(over || l > N) break;
if(l < 0){
cout << "stop" << endl;
}
sepa.push_back({l,k});
}
if(v == 2) break;
}
sepa.push_back({1,-1}),sepa.push_back({N+1,-1});
sort(sepa.begin(),sepa.end());
sepa.erase(unique(sepa.begin(),sepa.end()),sepa.end());
mint answer = 0,mul = 1;
vector<int> P(64,1);
for(int i=1; i<sepa.size(); i++){
auto [l,p] = sepa.at(i-1);
auto [r,ign] = sepa.at(i);
if(p != -1) mul *= inv.at(P.at(p)++),mul *= P.at(p);
if(l == r) continue;
r--;
long long l2 = Kthroot(l,2),r2 = Kthroot(r,2);
answer += range2(l2+1,r2-1)*mul;
if(l2 == r2) answer += mul*range1(l,r)*l2;
else answer += mul*(range1(l,(l2+1)*(l2+1)-1)*l2+range1(r2*r2,r)*r2);
}
cout << answer << endl;
}