結果
| 問題 | No.3763 Compress Pancakes |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-10-09 22:41:50 |
| 言語 | PyPy3 (7.3.23 + ACL) |
| 結果 |
WA
不安定
|
| 実行時間 | - |
| コード長 | 7,192 bytes |
| 記録 | |
| コンパイル時間 | 64 ms |
| コンパイル使用メモリ | 82,604 KB |
| 実行使用メモリ | 234,932 KB |
| 最終ジャッジ日時 | 2026-10-09 22:42:07 |
| 合計ジャッジ時間 | 12,396 ms |
|
ジャッジサーバーID (参考情報) |
judge1_0 / judge5_0 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 WA * 1 |
| other | AC * 16 WA * 13 |
ソースコード
"""Point updates and range products for an arbitrary monoid.
Use this when values change one position at a time and a half-open interval
must be folded with an associative operation. ``max_right`` and ``min_left``
also find the first boundary where a monotone predicate stops holding.
"""
class SegTree:
__slots__ = ("n", "size", "log", "data", "op", "identity")
def __init__(self, op, identity, values):
if isinstance(values, int):
n = values
values = [identity] * n
else:
values = list(values)
n = len(values)
size = 1 << (n - 1).bit_length() if n else 1
data = [identity] * (size << 1)
data[size : size + n] = values
for node in range(size - 1, 0, -1):
data[node] = op(data[node << 1], data[node << 1 | 1])
self.n = n
self.size = size
self.log = size.bit_length() - 1
self.data = data
self.op = op
self.identity = identity
def set(self, index, value):
node = index + self.size
data = self.data
data[node] = value
op = self.op
node >>= 1
while node:
data[node] = op(data[node << 1], data[node << 1 | 1])
node >>= 1
def add(self, index, value):
"""indexの現在値をop(value, current)で置き換える。O(log N)。"""
node = index + self.size
data = self.data
op = self.op
data[node] = op(value, data[node])
node >>= 1
while node:
data[node] = op(data[node << 1], data[node << 1 | 1])
node >>= 1
def get(self, index):
return self.data[index + self.size]
def tolist(self):
"""現在の要素列をlistで返す。O(N)。"""
return self.data[self.size:self.size + self.n]
def __str__(self):
return str(self.tolist())
def __repr__(self):
return "SegTree(%r)" % self.tolist()
def prod(self, left, right):
left += self.size
right += self.size
first = self.identity
second = self.identity
data = self.data
op = self.op
while left < right:
if left & 1:
first = op(first, data[left])
left += 1
if right & 1:
right -= 1
second = op(data[right], second)
left >>= 1
right >>= 1
return op(first, second)
query = prod
def all_prod(self):
return self.data[1]
def max_right(self, left, predicate):
if left == self.n:
return self.n
left += self.size
value = self.identity
data = self.data
op = self.op
while True:
while not left & 1:
left >>= 1
merged = op(value, data[left])
if not predicate(merged):
while left < self.size:
left <<= 1
merged = op(value, data[left])
if predicate(merged):
value = merged
left += 1
return min(left - self.size, self.n)
value = merged
left += 1
if left & -left == left:
break
return self.n
def min_left(self, right, predicate):
if right == 0:
return 0
right += self.size
value = self.identity
data = self.data
op = self.op
while True:
right -= 1
while right > 1 and right & 1:
right >>= 1
merged = op(data[right], value)
if not predicate(merged):
while right < self.size:
right = right << 1 | 1
merged = op(data[right], value)
if predicate(merged):
value = merged
right -= 1
return max(0, right + 1 - self.size)
value = merged
if right & -right == right:
break
return 0
def __getitem__(self, index):
return self.get(index)
# haru: pypy
import sys
input = sys.stdin.readline
II = lambda : int(input())
MI = lambda : map(int, input().split())
LI = lambda : [int(a) for a in input().split()]
SI = lambda : input().rstrip()
LLI = lambda n : [[int(a) for a in input().split()] for _ in range(n)]
LSI = lambda n : [input().rstrip() for _ in range(n)]
MI_1 = lambda : map(lambda x:int(x)-1, input().split())
LI_1 = lambda : [int(a)-1 for a in input().split()]
mod = 998244353
inf = 1001001001001001001
ordalp = lambda s : ord(s)-65 if s.isupper() else ord(s)-97
ordallalp = lambda s : ord(s)-39 if s.isupper() else ord(s)-97
yes = lambda : print("Yes")
no = lambda : print("No")
yn = lambda flag : print("Yes" if flag else "No")
prinf = lambda ans : print(ans if ans < 1000001001001001001 else -1)
alplow = "abcdefghijklmnopqrstuvwxyz"
alpup = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
alpall = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
URDL = {'U':(-1,0), 'R':(0,1), 'D':(1,0), 'L':(0,-1)}
DIR_4 = [[-1,0],[0,1],[1,0],[0,-1]]
DIR_8 = [[-1,0],[-1,1],[0,1],[1,1],[1,0],[1,-1],[0,-1],[-1,-1]]
DIR_BISHOP = [[-1,1],[1,1],[1,-1],[-1,-1]]
prime60 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59]
sys.set_int_max_str_digits(0)
# sys.setrecursionlimit(10**6)
# import pypyjit
# pypyjit.set_param('max_unroll_recursion=-1')
from collections import defaultdict,deque
from heapq import heappop,heappush
from bisect import bisect_left,bisect_right
DD = defaultdict
BSL = bisect_left
BSR = bisect_right
"""
この必要十分はしっていて
すべてについて S / ai が 2 べきかつ
prefix / ai とかだっけか
---
モノイドですか? -> まじでわからん笑
区間内で要請したいこと
ひとつめ
- 区間和
- もっとも大きい値
- それ以下がすべてべきである bool
ふたつめ
- ? mod ? がたされれば一致するか?
- 2 つ目は最大値のハズ
"""
def op(x, y):
if x[0] == -1:
return y
if y[0] == -1:
return x
r0 = x[0] + y[0]
r2 = 0
r3 = -1
if x[1] == y[1]:
r1 = x[1]
r2 = 1
if x[3] == y[3]:
r3 = x[3]
elif x[1] < y[1]:
r1 = y[1]
d = y[1]//x[1]
if y[1] % x[1] == 0 and (d).bit_count() == 1:
r2 = 1
if (y[3] - x[0] - x[3]) % x[1] == 0:
r3 = (y[3] - x[0]) % x[1]
else:
r1 = x[1]
if x[1] % y[1] == 0 and (x[1]//y[1]).bit_count() == 1:
r2 = 1
if (y[3] - x[0] - x[3]) % y[1] == 0:
r3 = x[3]
# print(x, y, (r0, r1, r2, r3))
return (r0, r1, r2, r3)
n, q = MI()
a = LI()
seg = SegTree(op, (-1, -1, -1, -1), [(x, x, 1, 0) for x in a])
for i in range(q):
t, k, x = MI()
k -= 1
if t == 1:
seg.set(k, (x, x, 1, 0))
else:
ans = seg.prod(k, x)
if ans[0] % ans[1] == 0 and ans[2] and ans[3] == 0:
print("Yes")
else:
print("No")
# print(seg, ans, [seg[i][0] for i in range(k, x)])