#135197 (C++11) No.454 逆2乗和

提出ソース

結果

問題	No.454 逆2乗和
ユーザー	shimomire
提出日時	2016-12-05 01:58:36
言語	C++11 (gcc 11.4.0)
結果	AC
実行時間	798 ms / 2,000 ms
コード長	5,140 bytes
コンパイル時間	1,505 ms
コンパイル使用メモリ	114,296 KB
実行使用メモリ	5,248 KB
最終ジャッジ日時	2024-11-30 02:40:46
合計ジャッジ時間	29,312 ms
ジャッジサーバーID （参考情報）	judge2 / judge4

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	786 ms 5,248 KB
testcase_01	AC	788 ms 5,248 KB
testcase_02	AC	786 ms 5,248 KB
testcase_03	AC	786 ms 5,248 KB
testcase_04	AC	787 ms 5,248 KB
testcase_05	AC	787 ms 5,248 KB
testcase_06	AC	791 ms 5,248 KB
testcase_07	AC	786 ms 5,248 KB
testcase_08	AC	786 ms 5,248 KB
testcase_09	AC	787 ms 5,248 KB
testcase_10	AC	784 ms 5,248 KB
testcase_11	AC	787 ms 5,248 KB
testcase_12	AC	798 ms 5,248 KB
testcase_13	AC	785 ms 5,248 KB
testcase_14	AC	785 ms 5,248 KB
testcase_15	AC	785 ms 5,248 KB
testcase_16	AC	788 ms 5,248 KB
testcase_17	AC	785 ms 5,248 KB
testcase_18	AC	787 ms 5,248 KB
testcase_19	AC	788 ms 5,248 KB
testcase_20	AC	787 ms 5,248 KB
testcase_21	AC	2 ms 5,248 KB
testcase_22	AC	797 ms 5,248 KB
testcase_23	AC	788 ms 5,248 KB
testcase_24	AC	785 ms 5,248 KB
testcase_25	AC	787 ms 5,248 KB
testcase_26	AC	788 ms 5,248 KB
testcase_27	AC	785 ms 5,248 KB
testcase_28	AC	784 ms 5,248 KB
testcase_29	AC	786 ms 5,248 KB
testcase_30	AC	785 ms 5,248 KB
testcase_31	AC	786 ms 5,248 KB
testcase_32	AC	788 ms 5,248 KB
testcase_33	AC	785 ms 5,248 KB

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ソースコード

raw source code

#include <cassert>// c
#include <iostream>// io
#include <iomanip>
#include <fstream>
#include <sstream>
#include <vector>// container
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <stack>
#include <algorithm>// other
#include <complex>
#include <numeric>
#include <functional>
#include <random>
#include <regex>
using namespace std;

typedef long long ll;typedef unsigned long long ull;typedef long double ld;

#define ALL(c) c.begin(),c.end()
#define IN(l,v,r) (l<=v && v < r)
template<class T> void UNIQUE(T& v){v.erase(unique(ALL(v)),v.end());}
//debug
#define DUMP(x) cerr << #x <<" = " << (x)
#define LINE() cerr<< " (L" << __LINE__ << ")"

struct range{
	struct Iter{
		int v,step;
		Iter& operator++(){v+=step;return *this;}
		bool operator!=(Iter& itr){return v<itr.v;}
		int& operator*(){return v;}
	};
	Iter i, n;
	range(int i, int n,int step):i({i,step}), n({n,step}){}
	range(int i, int n):range(i,n,1){}
	range(int n):range(0,n){}
	Iter& begin(){return i;}
	Iter& end(){return n;}
};
struct rrange{
	struct Iter{
		int v,step;
		Iter& operator++(){v-=step;return *this;}
		bool operator!=(Iter& itr){return v>itr.v;}
		int& operator*(){return v;}
	};
	Iter i, n;
	rrange(int i, int n,int step):i({i-1,step}), n({n-1,step}){}
	rrange(int i, int n):rrange(i,n,1){}
	rrange(int n) :rrange(0,n){}
	Iter& begin(){return n;}
	Iter& end(){return i;}
};

//input
template<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){return is>>p.first>>p.second;}
template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){return is >> get<0>(t);}
template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){return is >> get<0>(t) >> get<1>(t);}
template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){return is >>get<0>(t)>>get<1>(t)>>get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){return is >> get<0>(t)>>get<1>(t)>>get<2>(t)>>get<3>(t);}
template<typename T> istream& operator >> (istream& is,vector<T>& as){for(int i:range(as.size()))is >>as[i];return is;}
//output
template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;}
template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){return os<<p.first<<" "<<p.second;}
template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;}
template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){return os << get<0>(t);}
template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){return os << get<0>(t)<<" "<<get<1>(t);}
template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);}
template<typename T> ostream& operator << (ostream& os, const vector<T>& as){for(int i:range(as.size())){if(i!=0)os<<" "; os<<as[i];}return os;}
template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){for(int i:range(as.size())){if(i!=0)os<<endl; os<<as[i];}return os;}

// values
template<typename T> inline T INF(){assert(false);};
template<> inline int INF<int>(){return 1<<28;};
template<> inline ll INF<ll>(){return 1LL<<60;};
template<> inline double INF<double>(){return 1e16;};
template<> inline long double INF<long double>(){return 1e16;};

template<class T> inline T EPS(){assert(false);};
template<> inline int EPS<int>(){return 1;};
template<> inline ll EPS<ll>(){return 1LL;};
template<> inline double EPS<double>(){return 1e-8;};
template<> inline long double EPS<long double>(){return 1e-8;};

// min{2^r | n < 2^r}
template<typename T> inline T upper_pow2(T n){ T res=1;while(res<n)res<<=1;return res;}
// max{d | 2^d  <= n}
template<typename T> inline T msb(T n){ int d=62;while((1LL<<d)>n)d--;return d;}

template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;}


template <typename T,typename Func> T satisfy_maxi(Func P,T l ,T r){
	r+= EPS<T>();
	while(r-l>EPS<T>()){
		T m=(l+r)/2;
		(P(m)?l:r)=m;
	}
	return l;
}

// https://en.wikipedia.org/wiki/Trigamma_function
class Main{
	public:

	long double y(long double x,long double z){
		if(abs(0.0 - x) < 1e-8) return 0;
		if(abs(1.0 - x) < 1e-8) return 1;
		return -powl(x,z-1)*logl(x)/(1-x);
	}
	void run(){
		long double z;cin >> z;
		if(z == 0){
			cout << pow(acos(-1),2)/6 << endl;
			return;
		}
		z+=1.0;

		long double res = 0;int n = 1000000;
		for(long double i:range(n)){
			long double xl = i/n,xr = (i+1)/n;
			res += (xr-xl)*(y(xl,z)+y(xr,z))/2;
	//		cerr << res << endl;
		}
		cout << res << endl;
	}
};

int main(){
	cout <<fixed<<setprecision(20);
	cin.tie(0);
	ios::sync_with_stdio(false);
	Main().run();
	return 0;
}

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結果

テストケース

ソースコード