結果
問題 | No.117 組み合わせの数 |
ユーザー | 👑 testestest |
提出日時 | 2016-12-05 12:09:48 |
言語 | C90 (gcc 11.4.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 246 bytes |
コンパイル時間 | 196 ms |
コンパイル使用メモリ | 21,888 KB |
実行使用メモリ | 17,152 KB |
最終ジャッジ日時 | 2024-05-05 20:17:38 |
合計ジャッジ時間 | 738 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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コンパイルメッセージ
main.c:2:1: warning: data definition has no type or storage class 2 | P=1e9+7,x,c,r; | ^ main.c:2:1: warning: type defaults to ‘int’ in declaration of ‘P’ [-Wimplicit-int] main.c:2:9: warning: type defaults to ‘int’ in declaration of ‘x’ [-Wimplicit-int] 2 | P=1e9+7,x,c,r; | ^ main.c:2:11: warning: type defaults to ‘int’ in declaration of ‘c’ [-Wimplicit-int] 2 | P=1e9+7,x,c,r; | ^ main.c:2:13: warning: type defaults to ‘int’ in declaration of ‘r’ [-Wimplicit-int] 2 | P=1e9+7,x,c,r; | ^ main.c:3:1: warning: return type defaults to ‘int’ [-Wimplicit-int] 3 | p(long a,int i){x=i?p(a*a%P,i/2)*(i%2?a:1)%P:1;} | ^ main.c:4:1: warning: return type defaults to ‘int’ [-Wimplicit-int] 4 | main(n){ | ^~~~ main.c: In function ‘main’: main.c:4:1: warning: type of ‘n’ defaults to ‘int’ [-Wimplicit-int] main.c:5:13: warning: implicit declaration of function ‘gets’ [-Wimplicit-function-declaration] 5 | for(gets(f),*f=n;r++<2e6;f[r]=f[r-1]*r%P); | ^~~~ main.c:6:17: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration] 6 | for(;x=~scanf(" %c(%d,%d)",&c,&n,&r);printf("%d\n",n<r?0:f[n]*p(f[n-r]*(c%5?f[r]:1)%P,P-2)%P))c&8&&(n+=r)&&n--; | ^~~~~ main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ +++ |+#include <stdio.h> 1 | long f[1<<21]; main.c:6:17: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch] 6 | for(;x=~scanf(" %c(%d,%d)",&c,&n,&r);printf("%d\n",n<r?0:f[n]*p(f[n-r]*(c%5?f[r]:1)%P,P-2)%P))c&8&&(n+=r)&&n--; | ^~~~~ main.c:6:17: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’ main.c:6:26: warning: format ‘%c’ expects argument of type ‘char *’, but argument 2 has type ‘int *’ [-Wfor
ソースコード
long f[1<<21]; P=1e9+7,x,c,r; p(long a,int i){x=i?p(a*a%P,i/2)*(i%2?a:1)%P:1;} main(n){ for(gets(f),*f=n;r++<2e6;f[r]=f[r-1]*r%P); for(;x=~scanf(" %c(%d,%d)",&c,&n,&r);printf("%d\n",n<r?0:f[n]*p(f[n-r]*(c%5?f[r]:1)%P,P-2)%P))c&8&&(n+=r)&&n--; }