結果

問題 No.465 PPPPPPPPPPPPPPPPAPPPPPPPP
ユーザー koyumeishikoyumeishi
提出日時 2016-12-16 03:15:03
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 7,242 bytes
コンパイル時間 1,455 ms
コンパイル使用メモリ 126,184 KB
実行使用メモリ 82,468 KB
最終ジャッジ日時 2024-05-07 15:54:39
合計ジャッジ時間 5,238 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
10,752 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 2 ms
5,376 KB
testcase_05 AC 13 ms
5,376 KB
testcase_06 AC 59 ms
9,792 KB
testcase_07 AC 10 ms
5,376 KB
testcase_08 AC 42 ms
9,708 KB
testcase_09 TLE -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
32_ratsliveonnoevilstar.txt -- -
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <iostream>
#include <vector>
#include <cstdio>
#include <sstream>
#include <map>
#include <string>
#include <algorithm>
#include <queue>
#include <cmath>
#include <functional>
#include <set>
#include <ctime>
#include <random>
#include <chrono>
#include <cassert>
#include <tuple>
#include <utility>
using namespace std;

namespace {
  using Integer = long long; //__int128;
  template<class T, class S> istream& operator >> (istream& is, pair<T,S>& p){return is >> p.first >> p.second;}
  template<class T> istream& operator >> (istream& is, vector<T>& vec){for(T& val: vec) is >> val; return is;}
  template<class T> istream& operator ,  (istream& is, T& val){ return is >> val;}
  template<class T, class S> ostream& operator << (ostream& os, const pair<T,S>& p){return os << p.first << " " << p.second;}
  template<class T> ostream& operator << (ostream& os, const vector<T>& vec){for(size_t i=0; i<vec.size(); i++) os << vec[i] << (i==vec.size()-1?"":" "); return os;}
  template<class T> ostream& operator ,  (ostream& os, const T& val){ return os << " " << val;}

  template<class H> void print(const H& head){ cout << head; }
  template<class H, class ... T> void print(const H& head, const T& ... tail){ cout << head << " "; print(tail...); }
  template<class ... T> void println(const T& ... values){ print(values...); cout << endl; }

  template<class H> void eprint(const H& head){ cerr << head; }
  template<class H, class ... T> void eprint(const H& head, const T& ... tail){ cerr << head << " "; eprint(tail...); }
  template<class ... T> void eprintln(const T& ... values){ eprint(values...); cerr << endl; }

  class range{ Integer start_, end_, step_; public: struct range_iterator{ Integer val, step_; range_iterator(Integer v, Integer step) : val(v), step_(step) {} Integer operator * (){return val;} void operator ++ (){val += step_;} bool operator != (range_iterator& x){return step_ > 0 ? val < x.val : val > x.val;} }; range(Integer len) : start_(0), end_(len), step_(1) {} range(Integer start, Integer end) : start_(start), end_(end), step_(1) {} range(Integer start, Integer end, Integer step) : start_(start), end_(end), step_(step) {} range_iterator begin(){ return range_iterator(start_, step_); } range_iterator   end(){ return range_iterator(  end_, step_); } };

  inline string operator "" _s (const char* str, size_t size){ return move(string(str)); }
  constexpr Integer my_pow(Integer x, Integer k, Integer z=1){return k==0 ? z : k==1 ? z*x : (k&1) ? my_pow(x*x,k>>1,z*x) : my_pow(x*x,k>>1,z);}
  constexpr Integer my_pow_mod(Integer x, Integer k, Integer M, Integer z=1){return k==0 ? z%M : k==1 ? z*x%M : (k&1) ? my_pow_mod(x*x%M,k>>1,M,z*x%M) : my_pow_mod(x*x%M,k>>1,M,z);}
  constexpr unsigned long long operator "" _ten (unsigned long long value){ return my_pow(10,value); }

  inline int k_bit(Integer x, int k){return (x>>k)&1;} //0-indexed

  mt19937 mt(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count());

  template<class T> string join(const vector<T>& v, const string& sep){ stringstream ss; for(size_t i=0; i<v.size(); i++){ if(i>0) ss << sep; ss << v[i]; } return ss.str(); }

  inline string operator * (string s, int k){ string ret; while(k){ if(k&1) ret += s; s += s; k >>= 1; } return ret; }
}
constexpr long long mod = 9_ten + 7;

// #include <bitset>
// using bits = bitset<500001>;

struct unko_bit{
  using integer = unsigned long long;
  constexpr static int bit_size = 64;
  constexpr static int len = (500001+bit_size-1)/bit_size;
  integer value[len];
  void set(int k, int x){
    if(x) value[k/bit_size] |= integer(1) << (k%bit_size);
    else  value[k/bit_size] &= ~(integer(1) << (k%bit_size));
  }

  int count(unko_bit& x, int shift){
    int ss = shift/bit_size;
    int dd = shift%bit_size;
    int ret = 0;
    for(int i=ss; i<len; ++i){
      //if(value[i-ss] == 0) continue;
      integer tmp = 0;
      tmp |= value[i-ss] & (x.value[i] << dd);

      if(dd && i-ss+1<len){
        tmp |= value[i-ss+1] & (x.value[i] >> (bit_size-dd));
      }
      ret += __builtin_popcount(tmp);
    }
    return ret;
  }
};
using bits = unko_bit;


class palindromic_tree{
 public:
  struct node{
    map<char, int> e;
    int suf;
    int len;

    int depth;
  };

  const string& s;
  vector<node> t;
  vector<int> s_pos;

  void constract(){
    int pos = 1;
    for(int i=0; i<s.size(); s_pos[i++] = pos){
      while(1){
        if( i-t[pos].len-1 >= 0 && s[i-t[pos].len-1] == s[i]) break;
        pos = t[pos].suf;
      }
      if(t[pos].e.count(s[i])){
        pos = t[pos].e[s[i]];
        continue;
      }

      int nx = t.size();
      t.push_back(node{{}, -1, t[pos].len+2, 1});
      t[pos].e[s[i]] = nx;

      if(t[nx].len == 1){
        t[nx].suf = 1;
        pos = nx;
        t[pos].depth = t[t[pos].suf].depth+1;
        continue;
      }

      while(1){
        pos = t[pos].suf;
        if( i-t[pos].len-1 >= 0 && s[i-t[pos].len-1] == s[i]){
          t[nx].suf = t[pos].e[s[i]];
          break;
        }
      }
      pos = nx;
      t[pos].depth = t[t[pos].suf].depth+1;
    }
  }

  void init(){
    t[0].suf = 0;
    t[0].len = -1;
    t[0].depth = 0;

    t[1].suf = 0;
    t[1].len = 0;
    t[0].depth = 1;
  }

  palindromic_tree(const string& s_) : s(s_), t(2), s_pos(s_.size()){
    init();
    constract();
  }
};

long long dfs(palindromic_tree& p, int i, vector<bits*>& aho, int n, bits& head){
  int pos = p.s_pos[i];

  long long ret = 0;
  while(pos > 1){
    if(aho[pos] != nullptr){
      //ret += (head&((*aho[pos])<<(n-1-i))).count();
      ret += head.count(*aho[pos], n-1-i);
      //assert(false);
      break;
    }

    int len = p.t[ pos ].len;
    int suf = p.t[ pos ].suf;
    assert(pos != suf);

    int left = i-len;
    if(left >= 0){
      if(left - p.t[ p.s_pos[left] ].len == -1) ret++;
    }
    pos = suf;
  }
  return ret;
}

const int block = 600;

void dfs2(palindromic_tree& p, vector<vector<int>>& G, int pos, bits& s, vector<bits*>& aho, int d){
  if(pos>1) s.set( p.t[pos].len, 1 );
  if(pos>1) if( d % block == 0){
    aho[pos] = new bits(s);
  }
  for(int nx : G[pos]){
    if(nx == pos)continue;
    dfs2(p,G, nx, s, aho, d+1);
  }
  if(pos>1) s.set( p.t[pos].len , 0 );
}


int main(){
  string s;
  cin >> s;

  set<char> unko(s.begin(), s.end());
  if(unko.size() == 1){
    long long n = s.size() - 3;
    println( n*(n+1)*(n+2)/6 );
    return 0;
  }

  palindromic_tree p(s);

  bits head;
  for(int i=0; i<s.size(); i++){
    if( p.t[p.s_pos[i]].len == i+1 ) head.set(s.size()-1-i,1);
  }
  vector<vector<int>> G(p.t.size());
  for(int i=0; i<p.t.size(); i++){
    G[ p.t[i].suf ].push_back( i );
  }
  vector<bits*> aho(p.t.size(), nullptr);
  bits tmp;
  dfs2(p,G,0,tmp, aho, 0);

  vector<long long> dp(s.size()+1, 0);
  for(int i=1; i<s.size()-2; i++){
    dp[i] = dfs(p, i, aho, s.size(), head);
  }

  for(int i=1; i<s.size(); i++){
    dp[i] += dp[i-1];
  }

  long long ans = 0;
  int pos = p.s_pos[ s.size()-1 ];
  int i = s.size()-1;
  while(pos > 1){
    int len = p.t[pos].len;
    int suf = p.t[pos].suf;
    int left = i-len-1;

    if( left >= 0 ){
      ans += dp[left];
    }

    pos = suf;
  }

  println(ans);

  return 0;
}
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