結果
問題 |
No.482 あなたの名は
|
ユーザー |
![]() |
提出日時 | 2017-02-18 00:04:30 |
言語 | Haskell (9.10.1) |
結果 |
AC
|
実行時間 | 1,272 ms / 2,000 ms |
コード長 | 2,159 bytes |
コンパイル時間 | 5,021 ms |
コンパイル使用メモリ | 180,984 KB |
実行使用メモリ | 213,376 KB |
最終ジャッジ日時 | 2024-12-26 22:20:37 |
合計ジャッジ時間 | 25,468 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 28 |
コンパイルメッセージ
Loaded package environment from /home/judge/.ghc/x86_64-linux-9.8.2/environments/default [1 of 2] Compiling Main ( Main.hs, Main.o ) [2 of 2] Linking a.out
ソースコード
{-# LANGUAGE OverloadedStrings #-} module Main where import Data.Maybe import qualified Data.ByteString.Char8 as C import Control.Monad(forM_) import Data.Int import Data.List import Data.Array yes :: C.ByteString yes = "YES" no :: C.ByteString no = "NO" getInts :: IO [Int] getInts = do ss <- C.getLine return $ map (fst . fromJust . C.readInt) $ C.words ss getIntss :: Int -> IO [[Int]] getIntss 0 = return [] getIntss n = do xs <- getInts xss <- getIntss (n - 1) return $ xs : xss -- end standard template -- -- begin tree template -- data Tree a = Node (Tree a) a (Tree a) initTree :: a -> Tree a initTree x = Node (initTree x) x (initTree x) update' :: Int -> (a -> a) -> Tree a -> Tree a update' 0 f (Node l x r) = Node l (f x) r update' i f (Node l x r) | mod i 2 == 1 = Node l' x r | otherwise = Node l x r' where i' = div i 2 l' = (update' i' f l) r' = (update' (i' - 1) f r) at :: Tree a -> Int -> a at (Node _ x _) 0 = x at (Node l _ r) i | mod i 2 == 1 = at l i' | otherwise = at r (i' - 1) where i' = div i 2 -- end tree template -- main :: IO () main = do [n,k] <- getInts xs <- getInts let ss = solve n k xs C.putStrLn ss solve :: Int -> Int -> [Int] -> C.ByteString -- solve n k xs = C.pack $ show diff solve n k xs = if diff <= k && mod diff 2 == mod k 2 then yes else no where xs' = listArray (1,n) xs visited = initTree False (_, count) = f n xs' visited 0 diff = count f :: Int -> Array Int Int -> Tree Bool -> Int -> (Tree Bool, Int) f 0 xs visited count = (visited, count) f i xs visited count = if visited `at` i == True then f (i - 1) xs visited count else f (i - 1) xs visited' (count + count') where (visited', count') = g i i xs visited 0 g :: Int -> Int -> Array Int Int -> Tree Bool -> Int -> (Tree Bool, Int) g s i xs visited count = if (xs ! i) == s then (visited', count) else g s (xs ! i) xs visited' (count + 1) where visited' = update' i (const True) visited