結果
問題 | No.97 最大の値を求めるくえり |
ユーザー |
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提出日時 | 2017-07-31 15:14:12 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,420 ms / 5,000 ms |
コード長 | 3,809 bytes |
コンパイル時間 | 1,583 ms |
コンパイル使用メモリ | 171,768 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-11 00:08:54 |
合計ジャッジ時間 | 6,939 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 19 |
ソースコード
#include<bits/stdc++.h>#define rep(i,a,b) for(int i=a;i<b;i++)#define rrep(i,a,b) for(int i=a;i>=b;i--)#define fore(i,a) for(auto &i:a)#pragma GCC optimize ("-O3")using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }//---------------------------------------------------------------------------------------------------template<int MOD> struct ModInt {static const int Mod = MOD; unsigned x; ModInt() : x(0) { }ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }return ModInt(u); }bool operator==(ModInt that) const { return x == that.x; }bool operator!=(ModInt that) const { return x != that.x; }ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }};template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }typedef ModInt<100003> mint;/*---------------------------------------------------------------------------------------------------∧_∧∧_∧ (´<_` ) Welcome to My Coding Space!( ´_ゝ`) / ⌒i/ \ | |/ / ̄ ̄ ̄ ̄/ |__(__ニつ/ _/ .| .|____\/____/ (u ⊃---------------------------------------------------------------------------------------------------*/unsigned xor128_x = 123456789, xor128_y = 362436069, xor128_z = 521288629, xor128_w = 88675123;unsigned xor128() {unsigned t = xor128_x ^ (xor128_x << 11);xor128_x = xor128_y; xor128_y = xor128_z; xor128_z = xor128_w;return xor128_w = xor128_w ^ (xor128_w >> 19) ^ (t ^ (t >> 8));}void generateA(int N, int A[]) {for (int i = 0; i < N; ++i)A[i] = xor128() % 100003;}//---------------------------------------------------------------------------------------------------int N, Q, A[101010];int solve1(int q) {int res = 0;rep(i, 0, N) res = max(res, (mint(A[i]) * q).get());return res;}int solve2(int q) {mint x = q;rrep(i, 100002, 1) {int y = (mint(i) / x).get();int k = lower_bound(A, A + N, y) - A;if (k < N) if (A[k] == y) return i;}return -1;}//---------------------------------------------------------------------------------------------------void _main() {cin >> N >> Q;generateA(N, A);sort(A, A + N);rep(_, 0, Q) {int q; cin >> q;int ans = 0;if (q != 0) {if (N <= 1010) ans = solve1(q);else ans = solve2(q);}printf("%d\n", ans);}}