結果

問題 No.97 最大の値を求めるくえり
ユーザー はまやんはまやん
提出日時 2017-07-31 15:14:12
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,420 ms / 5,000 ms
コード長 3,809 bytes
コンパイル時間 1,583 ms
コンパイル使用メモリ 171,768 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-10-11 00:08:54
合計ジャッジ時間 6,939 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 19
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ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
//---------------------------------------------------------------------------------------------------
template<int MOD> struct ModInt {
static const int Mod = MOD; unsigned x; ModInt() : x(0) { }
ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
int get() const { return (int)x; }
ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }
ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }
ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;
while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }
return ModInt(u); }
bool operator==(ModInt that) const { return x == that.x; }
bool operator!=(ModInt that) const { return x != that.x; }
ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }
typedef ModInt<100003> mint;
/*---------------------------------------------------------------------------------------------------
           _
     _ ´<_   Welcome to My Coding Space!
     ´_` /  ⌒i
           | |
    /   //  |
  __(__ニ/  _/ .| .|____
     /____/ u 
---------------------------------------------------------------------------------------------------*/
unsigned xor128_x = 123456789, xor128_y = 362436069, xor128_z = 521288629, xor128_w = 88675123;
unsigned xor128() {
unsigned t = xor128_x ^ (xor128_x << 11);
xor128_x = xor128_y; xor128_y = xor128_z; xor128_z = xor128_w;
return xor128_w = xor128_w ^ (xor128_w >> 19) ^ (t ^ (t >> 8));
}
void generateA(int N, int A[]) {
for (int i = 0; i < N; ++i)
A[i] = xor128() % 100003;
}
//---------------------------------------------------------------------------------------------------
int N, Q, A[101010];
int solve1(int q) {
int res = 0;
rep(i, 0, N) res = max(res, (mint(A[i]) * q).get());
return res;
}
int solve2(int q) {
mint x = q;
rrep(i, 100002, 1) {
int y = (mint(i) / x).get();
int k = lower_bound(A, A + N, y) - A;
if (k < N) if (A[k] == y) return i;
}
return -1;
}
//---------------------------------------------------------------------------------------------------
void _main() {
cin >> N >> Q;
generateA(N, A);
sort(A, A + N);
rep(_, 0, Q) {
int q; cin >> q;
int ans = 0;
if (q != 0) {
if (N <= 1010) ans = solve1(q);
else ans = solve2(q);
}
printf("%d\n", ans);
}
}
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