結果
問題 | No.610 区間賞(Section Award) |
ユーザー |
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提出日時 | 2017-12-10 12:42:04 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 62 ms / 2,000 ms |
コード長 | 2,494 bytes |
コンパイル時間 | 816 ms |
コンパイル使用メモリ | 98,376 KB |
実行使用メモリ | 12,796 KB |
最終ジャッジ日時 | 2024-11-30 11:16:33 |
合計ジャッジ時間 | 3,835 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 50 |
ソースコード
#include <algorithm>#include <climits>#include <cmath>#include <cstdio>#include <cstdlib>#include <ctime>#include <iostream>#include <sstream>#include <functional>#include <map>#include <string>#include <cstring>#include <vector>#include <queue>#include <stack>#include <deque>#include <set>#include <list>#include <numeric>using namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair<ll,ll> P;const double PI = 3.14159265358979323846;const double EPS = 1e-12;const ll INF = 1LL<<29;const ll mod = 1e9+7;#define rep(i,n) for(int (i)=0;(i)<(ll)(n);++(i))#define repd(i,n,d) for(ll (i)=0;(i)<(ll)(n);(i)+=(d))#define all(v) (v).begin(), (v).end()#define pb(x) push_back(x)#define mp(x,y) make_pair((x),(y))#define mset(m,v) memset((m),(v),sizeof(m))#define chmin(X,Y) ((X)>(Y)?X=(Y),true:false)#define chmax(X,Y) ((X)<(Y)?X=(Y),true:false)#define fst first#define snd second#define UNIQUE(x) (x).erase(unique(all(x)),(x).end())template<class T> ostream &operator<<(ostream &os, const vector<T> &v){int n=v.size();rep(i,n)os<<v[i]<<(i==n-1?"":" ");return os;}#define N 200010int a[N], b[N], c[N], c2[N];ll data[2*N], datb[2*N], seg_n;void init(int n){seg_n = 1;while(seg_n<n) seg_n<<=1;rep(i, 2*seg_n-1) data[i] = 0;rep(i, 2*seg_n-1) datb[i] = 0;}// v[a]+=x; v[a+1]+=x;...; v[b-1]+=x;void add(int a, int b, ll x, int k, int l, int r){if(r <= a || b <= l) return;if(a <= l && r <= b){data[k] += x;} else {datb[k] += (min(b, r) - max(a, l))*x;add(a, b, x, k*2+1, l, (l+r)/2);add(a, b, x, k*2+2, (l+r)/2, r);}}// sum(v[a], v[a+1],..., v[b-1])// to use: sum(a, b, 0, 0, seg_n);ll sum(int a, int b, int k, int l, int r){if(r <= a || b <= l) return 0;if(a <= l && r <= b) return data[k]*(r-l) + datb[k];ll res = (min(b, r) - max(a, l))*data[k];res += sum(a, b, k*2+1, l, (l+r)/2) + sum(a, b, k*2+2, (l+r)/2, r);return res;}int main(){int n; scanf("%d", &n);rep(i, n) scanf("%d", a+i);rep(i, n) scanf("%d", b+i);rep(i, n) c[i] = a[i];rep(i, n) c2[a[i]] = i;//rep(i, n) a[i] = i;rep(i, n) b[i] = c2[b[i]];vector<int> res; res.reserve(n);init(n);rep(i, n){//cerr<<b[i]<<endl;if(sum(b[i], b[i]+1, 0, 0, seg_n)==0) res.push_back(c[b[i]]);//cerr<<b[i]<<" "<<sum(b[i], b[i]+1, 0, 0, seg_n)<<endl;add(0, b[i]+1, 1, 0, 0, seg_n);//cerr<<b[i]<<" "<<sum(b[i], b[i]+1, 0, 0, seg_n)<<endl;}sort(all(res));for(auto x: res) printf("%d\n", x);return 0;}