結果

問題 No.619 CardShuffle
ユーザー はまやんはまやんはまやんはまやん
提出日時 2017-12-25 21:45:54
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 125 ms / 3,000 ms
コード長 4,962 bytes
コンパイル時間 1,894 ms
コンパイル使用メモリ 179,884 KB
実行使用メモリ 7,860 KB
最終ジャッジ日時 2024-12-22 23:16:14
合計ジャッジ時間 5,436 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
//---------------------------------------------------------------------------------------------------
template<int MOD> struct ModInt {
static const int Mod = MOD; unsigned x; ModInt() : x(0) { }
ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
int get() const { return (int)x; }
ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }
ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }
ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;
while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }
return ModInt(u); }
bool operator==(ModInt that) const { return x == that.x; }
bool operator!=(ModInt that) const { return x != that.x; }
ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }
typedef ModInt<1000000007> mint;
struct func {
mint a, b, c; int f;
func(mint a = 1, mint b = 0, mint c = 0, int f = 0) : a(a), b(b), c(c), f(f) {}
};
func operator*(func x, func y) {
// op1
if (x.f and y.f) return func(x.a, x.b + x.c * y.a + y.b, y.c, 1);
// op2
if (x.f) return func(x.a, x.b, x.c * y.a, 1);
// op3
if (y.f) return func(x.a * y.a, y.b, y.c, 1);
// op4
if (!x.f and !y.f) return func(x.a * y.a, 0, 0, 0);
assert(0);
}
//-----------------------------------------------------------------
template<class V, int NV> struct SegTree { // [L,R)
V comp(V l, V r) {
return l * r;
};
vector<V> val; SegTree() { val = vector<V>(NV * 2); }
V get(int x, int y, int l = 0, int r = NV, int k = 1) { // x<=i<y
if (r <= x || y <= l) return V();
if (x <= l && r <= y) return val[k];
auto A = get(x, y, l, (l + r) / 2, k * 2);
auto B = get(x, y, (l + r) / 2, r, k * 2 + 1);
return comp(A,B);
}
void update(int i, V v) { i += NV; val[i] = v; while (i>1) i >>= 1, val[i] = comp(val[i * 2],val[i * 2 + 1]); }
};
SegTree<func, 1 << 17> st;
/*---------------------------------------------------------------------------------------------------
           _
     _ ´<_   Welcome to My Coding Space!
     ´_` /  ⌒i
           | |
    /   //  |
  __(__ニ/  _/ .| .|____
     /____/ u 
---------------------------------------------------------------------------------------------------*/
int N; int A[101010]; char B[101010]; int Q;
//---------------------------------------------------------------------------------------------------
void update(int i) {
if (B[i] == '*') st.update(i, func(A[i], 0, 0, 0));
else st.update(i, func(1, 0, A[i], 1));
}
//---------------------------------------------------------------------------------------------------
void _main() {
cin >> N;
cin >> A[0]; B[0] = '+';
rep(i, 0, N / 2) cin >> B[i + 1] >> A[i + 1];
rep(i, 0, N / 2 + 1) update(i);
cin >> Q;
rep(q, 0, Q) {
string s; int x, y; cin >> s >> x >> y;
if (s == "!") {
if (x % 2 == 1) {
x /= 2; y /= 2;
swap(A[x], A[y]);
update(x);
update(y);
} else {
x /= 2; y /= 2;
swap(B[x], B[y]);
update(x);
update(y);
}
}
else {
x /= 2; y /= 2;
func f;
if (B[x] == '*') {
B[x] = '+';
update(x);
f = st.get(x, y + 1);
B[x] = '*';
update(x);
} else f = st.get(x, y + 1);
mint ans = f.b + f.c;
printf("%d\n", ans.get());
}
}
}
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