結果

問題 No.619 CardShuffle
ユーザー 0x19f
提出日時 2018-01-25 00:45:56
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
AC  
実行時間 895 ms / 3,000 ms
コード長 2,795 bytes
コンパイル時間 1,998 ms
コンパイル使用メモリ 168,304 KB
実行使用メモリ 354,688 KB
最終ジャッジ日時 2024-12-26 08:31:02
合計ジャッジ時間 15,085 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 35
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:25:7: warning: ‘y’ may be used uninitialized in this function [-Wmaybe-uninitialized]
   25 |     a += n - 1;
      |     ~~^~~~~~~~
main.cpp:87:13: note: ‘y’ was declared here
   87 |       ll x, y;
      |             ^
main.cpp:98:40: warning: ‘x’ may be used uninitialized in this function [-Wmaybe-uninitialized]
   98 |       segtree.update(x, *(new node(OP[x], V[x])));
      |                                        ^

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define REP(i, a, n) for(ll i = ((ll) a); i < ((ll) n); i++)
#define MOD 1000000007LL
using namespace std;
typedef long long ll;
/* 0-indexed, [0, n) */
template<typename T> class SegmentTree {
vector<T> vec;
ll n; // size of vector
T e; // unity of monoid
T (*op)(T, T); // binary operator of monoid
public:
SegmentTree(ll _n, T _e, T (*_op)(T, T)) : e(_e), op(_op), n(1) {
while(n < _n) n *= 2;
vec.resize(n * 2 - 1, e);
}
T query(ll a, ll b) { // query for [a, b)
return rquery(a, b, 0, 0, n);
}
void update(ll a, T k) { // update for a-th value
a += n - 1;
vec[a] = k;
while(a > 0) {
a = (a - 1) / 2;
vec[a] = op(vec[a * 2 + 1], vec[a * 2 + 2]);
}
}
private:
T rquery(ll a, ll b, ll k, ll l, ll r) {
if(r <= a || b <= l) return e;
if(a <= l && r <= b) return vec[k];
T vl = rquery(a, b, k * 2 + 1, l, (l + r) / 2);
T vr = rquery(a, b, k * 2 + 2, (l + r) / 2, r);
return op(vl, vr);
}
};
struct node {
ll type;
ll x, y, z;
node(ll x): type(1), x(x) {}
node(ll x, ll y, ll z): type(0), x(x), y(y), z(z) {}
node(char op, ll v) {
if(op == '+') { type = 0; x = 1; y = 0; z = v; }
if(op == '*') { type = 1; x = v; }
}
ll value() {
if(type == 1) return x;
return (y + z) % MOD;
};
};
node op(node p, node q) {
if(p.type == 1 && q.type == 1) return *(new node(p.x * q.x % MOD));
if(p.type == 1 && q.type == 0) return *(new node(p.x * q.x % MOD, q.y, q.z));
if(p.type == 0 && q.type == 1) return *(new node(p.x, p.y, p.z * q.x % MOD));
return *(new node(p.x, (((p.y + ((p.z * q.x) % MOD)) % MOD) + q.y) % MOD, q.z));
}
int main(void) {
ll N;
cin >> N;
vector<char> OP(N);
vector<ll> V(N);
SegmentTree<node> segtree(N, *(new node(1)), op);
REP(i, 0, (N + 1) / 2) {
ll v;
if(i == 0) OP[i] = '+'; else cin >> OP[i];
cin >> V[i];
segtree.update(i, *(new node(OP[i], V[i])));
}
ll Q;
cin >> Q;
vector<char> T(Q);
vector<ll> X(Q), Y(Q);
REP(i, 0, Q) cin >> T[i] >> X[i] >> Y[i], X[i]--, Y[i]--;
REP(i, 0, Q) {
if(T[i] == '!') {
ll x, y;
if(X[i] % 2 == 0 && Y[i] % 2 == 0) {
x = X[i] / 2;
y = Y[i] / 2;
swap(V[x], V[y]);
}
if(X[i] % 2 == 1 && Y[i] % 2 == 1) {
x = X[i] / 2 + 1;
y = Y[i] / 2 + 1;
swap(OP[x], OP[y]);
}
segtree.update(x, *(new node(OP[x], V[x])));
segtree.update(y, *(new node(OP[y], V[y])));
}
if(T[i] == '?') {
ll x = X[i] / 2, y = Y[i] / 2 + 1;
if(OP[x] == '*') segtree.update(x, *(new node('+', V[x])));
node r = segtree.query(x, y);
cout << r.value() << endl;
if(OP[x] == '*') segtree.update(x, *(new node(OP[x], V[x])));
}
}
}
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