結果
| 問題 |
No.7 プライムナンバーゲーム
|
| コンテスト | |
| ユーザー |
akusyounin2412
|
| 提出日時 | 2018-03-24 21:58:38 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,980 bytes |
| コンパイル時間 | 1,371 ms |
| コンパイル使用メモリ | 118,012 KB |
| 実行使用メモリ | 7,492 KB |
| 最終ジャッジ日時 | 2024-06-25 03:16:53 |
| 合計ジャッジ時間 | 2,103 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 9 WA * 8 |
ソースコード
# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
constexpr long long MOD = 1000000000 + 7;
constexpr long long INF = std::numeric_limits<long long>::max();
const double PI = acos(-1);
#define fir first
#define sec second
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, s, t, q, sum, last[10], ans, cnt, a[200010],b[200010], dp[200010];
struct Edge { LL to, cost,mon; };
string str;
bool f[200010];
void YN(bool f) {
if (f)
cout << "YES" << endl;
else
cout << "NO" << endl;
}
void yn(bool f) {
if (f)
cout << "Yes" << endl;
else
cout << "No" << endl;
}
vector<Edge>vec[100000];
LL ff(LL x) {
if (dp[x] != 0)return dp[x];
if (x / 10 > 0) {
LL ss = 0, num = x;
while (num > 0) {
ss += num % 10;
num /= 10;
}
dp[x] = ff(ss);
}
else dp[x] = x;
return dp[x];
}
int main() {
cin >> n;
f[1] = 1;
for (int i = 2; i*i <= n; i++) {
if (!f[i])
for (int j = 2; j*i <= n; j++) {
f[i*j] = 1;
}
}
n -= 3;
while (n>1) {
Mfor(i, n+1)
if (!f[i]) {
n -= i;
break;
}
ans++;
}
cout << (ans % 2 ? "Win" : "Lose") << endl;
return 0;
}
akusyounin2412