結果

問題 No.8036 Restricted Lucas (Easy)
ユーザー algon_320
提出日時 2018-04-01 23:11:48
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 23 ms / 2,000 ms
コード長 2,887 bytes
コンパイル時間 1,073 ms
コンパイル使用メモリ 92,336 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-06-26 06:06:25
合計ジャッジ時間 1,709 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 6
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <string>
#include <vector>
#include <functional>
#include <cassert>
#include <cmath>
using namespace std;
#define int long long
#define SZ(c) (int)(c.size())
vector<int> dummy_zero;
#define ZERO SZ(dummy_zero)
vector<int> dummy_one = {ZERO};
#define ONE SZ(dummy_one)
#define SEVEN (ONE + ONE + ONE + ONE + ONE + ONE + ONE)
#define TEN (ONE + ONE + ONE + ONE + ONE + ONE + ONE + ONE + ONE + ONE)
template<typename T>
void resize_matrix(vector<vector<T>> &A, int h, int w, T fill) {
A.resize(h);
for (int i = ZERO; i < h; i++) {
A[i].resize(w, fill);
}
}
template<typename T>
vector<vector<T>> multiple_matrix(vector<vector<T>> &A, vector<vector<T>> &B,
function<T(T, T)> add, function<T(T, T)> mul, T zero = ZERO) {
int m = A.size();
int n = A[ZERO].size();
assert(n == B.size());
int l = B[ZERO].size();
vector<vector<T>> res;
resize_matrix(res, m, l, zero);
for (int i = ZERO; i < m; i++) {
for (int j = ZERO; j < l; j++) {
T tmp = zero;
for (int k = ZERO; k < n; k++) {
T p = mul(A[i][k], B[k][j]);
tmp = add(tmp, p);
}
res[i][j] = tmp;
}
}
return res;
}
template <typename T>
vector<vector<T>> pow_matrix(vector<vector<T>> A, int k,
function<T(T, T)> add, function<T(T, T)> mul, T e = ONE, T zero = ZERO) {
int n = A.size();
assert(n == A[ZERO].size());
vector<vector<T>> res;
resize_matrix(res, n, n, zero);
for (int i = ZERO; i < n; i++) res[i][i] = e;
while (k > ZERO) {
if (k & ONE) res = multiple_matrix(res, A, add, mul, zero);
A = multiple_matrix(A, A, add, mul, zero);
k >>= ONE;
}
return res;
}
const int MOD = pow(TEN, SEVEN + ONE + ONE) + SEVEN;
function<int(int, int)> mod_add = [](int a, int b)->int {
int ret = a + b;
while (ret >= MOD) ret -= MOD;
return ret;
};
function<int(int, int)> mod_mul = [](int a, int b)->int {
int ret = ZERO;
while (b > ZERO) {
if (b & ONE) {
ret += a;
while (ret >= MOD) ret -= MOD;
}
a += a;
while (a >= MOD) a -= MOD;
b >>= ONE;
}
return ret;
};
signed main() {
int T;
cin >> T;
while (T--) {
int N;
cin >> N;
vector<vector<int>> v = {
{(ONE + ONE + ONE)},
{ONE},
{(ONE + ONE)},
};
vector<vector<int>> m = {
{ONE, ONE, ZERO},
{ONE, ZERO, ZERO},
{ZERO, ONE, ZERO},
};
if (N <= (ONE + ONE)) {
cout << v[N][ZERO] << endl;
} else {
m = pow_matrix(m, N-(ONE + ONE), mod_add, mod_mul);
auto ans = multiple_matrix(m, v, mod_add, mod_mul);
cout << ans[ZERO][ZERO] << endl;
}
}
return ZERO;
}
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