結果
| 問題 | No.8036 Restricted Lucas (Easy) |
| コンテスト | |
| ユーザー |
okaduki
|
| 提出日時 | 2018-04-01 23:23:28 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 3 ms / 2,000 ms |
| コード長 | 1,783 bytes |
| コンパイル時間 | 853 ms |
| コンパイル使用メモリ | 80,548 KB |
| 実行使用メモリ | 5,376 KB |
| 最終ジャッジ日時 | 2024-06-26 06:07:11 |
| 合計ジャッジ時間 | 1,349 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 6 |
ソースコード
#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
using VI = vector<int>;
using VVI = vector<VI>;
using PII = pair<int, int>;
using LL = long long;
using VL = vector<LL>;
using VVL = vector<VL>;
using PLL = pair<LL, LL>;
using VS = vector<string>;
#define ALL(a) begin((a)),end((a))
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define EB emplace_back
#define MP make_pair
#define SZ(a) int((a).size())
#define SORT(c) sort(ALL((c)))
#define RSORT(c) sort(RALL((c)))
#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))
LL MOD;
int zero;
LL one;
LL two;
LL three;
LL four;
LL five;
LL six;
LL seven;
LL eight;
LL nine;
LL ten;
#define FOR(i,a,b) for(LL i=(a);i<(b);++i)
#define REP(i,n) FOR(i,zero,n)
LL mod(LL a){
return div(a, MOD).rem;
}
LL mul(LL a, LL b){
return mod(multiplies<LL>()(a,b));
}
VVL mul(const VVL& a, const VVL& b){
VVL tmp(two, VL(two));
REP(i,two) REP(j,two) REP(k,two){
tmp[i][j] += mul(a[i][k], b[k][j]);
if(tmp[i][j] >= MOD)
tmp[i][j] -= MOD;
}
return tmp;
}
LL solve(LL n){
VVL xs = {{one,one},{one,zero}};
VVL p = {{one,zero},{zero,one}};
while(n > zero){
if(n&one){
p = mul(p, xs);
}
xs = mul(xs, xs);
n >>= one;
}
return mod(p[one][zero]+(p[one][one]<<one));
}
int main(){
++one;
two = one;
++two;
three = two;
++three;
four = three;
++four;
five = four;
++five;
six = five;
++six;
seven = six;
++seven;
eight = seven;
++eight;
nine = eight;
++nine;
ten = nine;
++ten;
MOD = ten;
MOD = multiplies<LL>()(MOD, MOD);
MOD = multiplies<LL>()(MOD, MOD);
MOD = multiplies<LL>()(MOD, MOD);
MOD = multiplies<LL>()(MOD, ten) + seven;
int T;
cin >> T;
while(T--){
LL n;
cin >> n;
cout << solve(n) << endl;
}
}
okaduki