結果

問題 No.765 ukuku 2
ユーザー nebukuro09
提出日時 2018-12-13 14:06:35
言語 D
(dmd 2.109.1)
結果
AC  
実行時間 418 ms / 3,000 ms
コード長 2,464 bytes
コンパイル時間 818 ms
コンパイル使用メモリ 117,708 KB
実行使用メモリ 10,344 KB
最終ジャッジ日時 2024-06-13 02:19:27
合計ジャッジ時間 8,637 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 48
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ソースコード

diff #
プレゼンテーションモードにする

import std.stdio, std.array, std.string, std.conv, std.algorithm;
import std.typecons, std.range, std.random, std.math, std.container;
import std.numeric, std.bigint, core.bitop, core.stdc.string;
const long MOD = 10^^9 + 9;
const long BASE = 31;
void main() {
auto S = readln.chomp;
auto N = S.length.to!int;
auto T = S.to!(dchar[]).reverse.to!string;
if (is_kaibun(S)) {
writeln(N-1);
return;
}
auto P = new long[](N+1);
auto P_INV = new long[](N+1);
P[0] = P_INV[0] = 1;
foreach (i; 0..N) P[i+1] = P[i] * BASE % MOD;
foreach (i; 0..N) P_INV[i] = powmod(P[i], MOD-2, MOD);
auto rh = new long[](N+1);
rh[N] = 0;
foreach (i; 0..N) rh[i+1] = (rh[i] + (S[i] - 'a') * P[i]) % MOD;
auto hr = new long[](N+1);
hr[N] = 0;
foreach (i; 0..N) hr[i+1] = (hr[i] + (T[i] - 'a') * P[i]) % MOD;
long hash_substr(int l, int r) { // [l, r]
return ((rh[r+1] - rh[l]) * P_INV[l] % MOD + MOD) % MOD;
}
long hash_reverse(int l, int r) {
int nl = N - r - 1;
int nr = N - l - 1;
return ((hr[nr+1] - hr[nl]) * P_INV[nl] % MOD + MOD) % MOD;
}
int bin_search(int r1, int l2) {
if (r1 < 0 || l2 >= N)
return -1;
int hi = min(r1+1, N-l2);
int lo = -1;
while (hi - lo > 1) {
int mid = (hi + lo) / 2;
int l1 = r1 - mid;
int r2 = l2 + mid;
if (hash_substr(l1, r1) == hash_reverse(l2, r2))
lo = mid;
else
hi = mid;
}
return lo;
}
int ans = 0;
foreach (i; 0..N) { // S[i]
int len1 = bin_search(i-1, i+1) + 1;
int r1 = i - len1 - 1;
int l2 = i + len1 + 1;
int len2 = max(bin_search(r1-1, l2), bin_search(r1, l2+1)) + 1;
ans = max(ans, len1 * 2 + len2 * 2 + 1);
}
foreach (i; 0..N-1) { // S[i..i+1]
int len1 = bin_search(i, i+1) + 1;
int r1 = i - len1;
int l2 = i + len1 + 1;
int len2 = max(bin_search(r1-1, l2), bin_search(r1, l2+1)) + 1;
ans = max(ans, len1 * 2 + len2 * 2);
}
ans.writeln;
}
bool is_kaibun(string s) {
return iota(s.length/2).map!(i => s[i] == s[s.length.to!int-i-1]).all;
}
long powmod(long a, long x, long m) {
long ret = 1;
while (x) {
if (x % 2) ret = ret * a % m;
a = a * a % m;
x /= 2;
}
return ret;
}
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