結果

問題 No.765 ukuku 2
ユーザー paruki
提出日時 2018-12-25 09:40:47
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 245 ms / 3,000 ms
コード長 2,651 bytes
コンパイル時間 1,833 ms
コンパイル使用メモリ 174,104 KB
実行使用メモリ 16,256 KB
最終ジャッジ日時 2024-10-01 13:15:09
合計ジャッジ時間 7,700 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 48
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#define _USE_MATH_DEFINES
#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define MT make_tuple
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
#define RT return
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
using vll = vector<ll>;
struct RollingHash {
static const int C = 31, C2 = 29, P = 1000000007, P2 = 1000000009;
int _n;
vector<long long> pw, pw2, hs, hs2;
RollingHash() {}
RollingHash(const string &st)
:_n((int)st.size()), pw(_n + 1), pw2(_n + 1), hs(_n + 1), hs2(_n + 1)
{
pw[0] = pw2[0] = 1;
rep(i, _n) {
pw[i + 1] = (pw[i] * C) % P;
pw2[i + 1] = (pw2[i] * C2) % P2;
hs[i + 1] = (C*hs[i] + st[i]) % P;
hs2[i + 1] = (C2*hs2[i] + st[i]) % P2;
}
}
// [l, r)
pii getHash(int l, int r) {
int res, res2;
res = (hs[r] - hs[l] * pw[r - l]) % P;
res2 = (hs2[r] - hs2[l] * pw2[r - l]) % P2;
if (res < 0)res += P;
if (res2 < 0)res2 += P2;
return mp(res, res2);
}
};
string S;
int N;
void solve() {
cin >> S;
N = sz(S);
auto T = S;
reverse(all(T));
RollingHash hsh(S), rev(T);
auto f = [&](int ml, int mr, int x) {
auto p = hsh.getHash(ml - x, ml);
auto q = rev.getHash(N - (mr + x), N - mr);
return p == q;
};
int ans = 0;
rep(ml, N) FOR(mr, ml, ml + 2) {
int ok = 0, ng = min(ml, N - mr) + 1;
while (ng - ok > 1) {
int x = (ok + ng) / 2;
(f(ml, mr, x) ? ok : ng) = x;
}
int l = ml - ok, r = mr + ok;
if (r - l == N)continue;
smax(ans, r - l);
if (l > 1) {
ok = 0, ng = min(l - 1, N - r) + 1;
while (ng - ok > 1) {
int x = (ok + ng) / 2;
(f(l - 1, r, x) ? ok : ng) = x;
}
smax(ans, r - l + ok * 2);
}
if (r < N) {
ok = 0, ng = min(l, N - (r + 1)) + 1;
while (ng - ok > 1) {
int x = (ok + ng) / 2;
(f(l, r + 1, x) ? ok : ng) = x;
}
smax(ans, r - l + ok * 2);
}
}
cout << ans << endl;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(15);
solve();
return 0;
}
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