結果

問題 No.800 四平方定理
ユーザー hitonanodehitonanode
提出日時 2019-03-17 21:23:58
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 3,281 bytes
コンパイル時間 1,699 ms
コンパイル使用メモリ 174,380 KB
実行使用メモリ 171,556 KB
最終ジャッジ日時 2024-07-07 20:06:36
合計ジャッジ時間 25,139 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 8 ms
6,820 KB
testcase_01 AC 14 ms
6,944 KB
testcase_02 AC 12 ms
6,940 KB
testcase_03 AC 12 ms
6,944 KB
testcase_04 AC 9 ms
6,940 KB
testcase_05 AC 12 ms
6,940 KB
testcase_06 AC 17 ms
6,940 KB
testcase_07 AC 13 ms
6,944 KB
testcase_08 AC 19 ms
6,940 KB
testcase_09 AC 15 ms
6,940 KB
testcase_10 AC 852 ms
58,764 KB
testcase_11 AC 1,168 ms
82,656 KB
testcase_12 AC 1,174 ms
82,708 KB
testcase_13 AC 1,106 ms
82,596 KB
testcase_14 AC 1,265 ms
82,640 KB
testcase_15 AC 1,262 ms
82,588 KB
testcase_16 AC 1,305 ms
82,700 KB
testcase_17 AC 1,256 ms
82,748 KB
testcase_18 AC 1,256 ms
82,572 KB
testcase_19 AC 1,311 ms
82,700 KB
testcase_20 AC 2 ms
5,376 KB
testcase_21 AC 2 ms
5,376 KB
testcase_22 AC 1,273 ms
82,576 KB
testcase_23 TLE -
testcase_24 TLE -
testcase_25 TLE -
testcase_26 AC 2 ms
6,944 KB
testcase_27 AC 1 ms
6,940 KB
testcase_28 TLE -
testcase_29 TLE -
testcase_30 TLE -
testcase_31 TLE -
testcase_32 TLE -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
#define FI first
#define SE second
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))

int N, D;

int main()
{
    cin >> N >> D;
    unordered_map<int, int> xy;
    FOR(i, 1, N + 1) FOR(j, 1, N + 1) xy[i * i + j * j]++;

    lint ans = 0;
    FOR(w, 1, N + 1) FOR(z, 1, N + 1) ans += xy[D + w * w - z * z];
    cout << ans << endl;
}
0