結果
問題 | No.801 エレベーター |
ユーザー |
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提出日時 | 2019-03-17 22:04:06 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 326 ms / 2,000 ms |
コード長 | 5,122 bytes |
コンパイル時間 | 1,943 ms |
コンパイル使用メモリ | 161,480 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-07 23:05:05 |
合計ジャッジ時間 | 8,232 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 26 |
ソースコード
#include <bits/stdc++.h>using namespace std;struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;#define FOR(i, begin, end) for(int i=(begin);i<(end);i++)#define REP(i, n) FOR(i,0,n)#define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--)#define IREP(i, n) IFOR(i,0,n)#define Sort(v) sort(v.begin(), v.end())#define Reverse(v) reverse(v.begin(), v.end())#define all(v) v.begin(),v.end()#define SZ(v) ((int)v.size())#define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x))#define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x))#define Max(a, b) a = max(a, b)#define Min(a, b) a = min(a, b)#define bit(n) (1LL<<(n))#define Ans(f, y, n) if(f) cout << y << endl; else cout << n << endl;#define debug(x) cout << #x << "=" << x << endl;#define vdebug(v) cout << #v << "=" << endl; REP(i, v.size()){ cout << v[i] << ","; } cout << endl;#define mdebug(m) cout << #m << "=" << endl; REP(i, m.size()){ REP(j, m[i].size()){ cout << m[i][j] << ","; } cout << endl;}#define pb push_back#define f first#define s second#define int long long#define INF 1000000000000000000using vec = vector<int>;using mat = vector<vec>;using Pii = pair<int, int>;using PiP = pair<int, Pii>;using PPi = pair<Pii, int>;using bools = vector<bool>;using pairs = vector<Pii>;template<typename T> void readv(vector<T> &a){ REP(i, a.size()) cin >> a[i]; }void readv_m1(vector<int> &a){ REP(i, a.size()){cin >> a[i]; a[i]--;} }//int dx[4] = {1,0,-1,0};//int dy[4] = {0,1,0,-1};int mod = 1000000007;//int mod = 998244353;#define Add(x, y) x = (x + (y)) % mod#define Mult(x, y) x = (x * (y)) % mod/*class Lazy_segment_tree{using data_type = int;public:vector<data_type> dat, lazy;int N;data_type id, id2;//区間演算結果を求めるクエリに関する演算data_type func(data_type u, data_type v){return u + v;}//区間更新に関する演算data_type func2(data_type u, data_type v){return u + v;}//作用素同士の演算data_type func3(data_type u, data_type v){return u + v;}Lazy_segment_tree(int n, data_type id, data_type id2): id(id), id2(id2) {N = 1;while(n > N) N = N << 1;dat = vector<data_type>(2 * N - 1, id);lazy = vector<data_type>(2 * N - 1, id2);}Lazy_segment_tree(int n, data_type id, data_type id2, vector<data_type> v): id(id), id2(id2) {N = 1;while(n > N) N = N << 1;dat = vector<data_type>(2 * N - 1, id);lazy = vector<data_type>(2 * N - 1, id2);REP(i, n) dat[i + N - 1] = v[i];IREP(i, N - 1) dat[i] = func(dat[i * 2 + 1], dat[i * 2 + 2]);}void reset(){fill(all(dat), 0);fill(all(lazy), 0);}//遅延評価void eval(int k, int l, int r){if(lazy[k] != id2){//子ノード数に比例した量の演算をする場合dat[k] = func2(dat[k], lazy[k] * (r - l));//子ノード数に依存しない場合//dat[k] = func2(dat[k], lazy[k]);if(r - l > 1){lazy[k * 2 + 1] = func3(lazy[k * 2 + 1], lazy[k]);lazy[k * 2 + 2] = func3(lazy[k * 2 + 2], lazy[k]);}lazy[k] = id2;}}void update(int a, int b, data_type x, int k, int l, int r){eval(k, l, r);if(b <= l || r <= a) return;if(a <= l && r <= b){lazy[k] = func3(lazy[k], x);eval(k, l, r);}else{update(a, b, x, k * 2 + 1, l, (l + r) / 2);update(a, b, x, k * 2 + 2, (l + r) / 2, r);dat[k] = func(dat[k * 2 + 1], dat[k * 2 + 2]);}}data_type query(int a, int b, int k, int l, int r){if(r <= a || b <= l) return id;eval(k, l, r);if(a <= l && r <= b) return dat[k];else{data_type vl = query(a, b, k * 2 + 1, l, (l + r) / 2);data_type vr = query(a, b, k * 2 + 2, (l + r) / 2, r);return func(vl, vr);}}//[a,b)の区間更新void update(int a, int b, data_type x){update(a, b, x, 0, 0, N);}//[a, b)の演算結果data_type query(int a, int b){return query(a, b, 0, 0, N);}data_type getdat(int k){return query(k, k + 1);}};*/signed main(){int N, M, K; cin >> N >> M >> K;vec L(M), R(M);REP(i, M){cin >> L[i] >> R[i];L[i]--; R[i]--;}vec dp(N, 0), dpsum(N + 1, 0);dp[0] = 1;REP(k, K){dpsum[0] = 0;REP(i, N) dpsum[i + 1] = dpsum[i] + dp[i];fill(all(dp), 0);REP(i, M){int num = dpsum[R[i] + 1] - dpsum[L[i]];dp[L[i]] += num;if(R[i] + 1 < N) dp[R[i] + 1] -= num;}dp[0] %= mod;FOR(i, 1, N) dp[i] = ((dp[i - 1] + dp[i]) % mod + mod) % mod;}cout << dp[N - 1] << endl;return 0;}