結果
問題 | No.803 Very Limited Xor Subset |
ユーザー |
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提出日時 | 2019-03-17 22:40:02 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 6 ms / 2,000 ms |
コード長 | 3,125 bytes |
コンパイル時間 | 1,525 ms |
コンパイル使用メモリ | 166,784 KB |
実行使用メモリ | 5,512 KB |
最終ジャッジ日時 | 2024-07-08 00:52:27 |
合計ジャッジ時間 | 2,837 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 43 |
ソースコード
#include <bits/stdc++.h>using namespace std;struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;#define FOR(i, begin, end) for(int i=(begin);i<(end);i++)#define REP(i, n) FOR(i,0,n)#define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--)#define IREP(i, n) IFOR(i,0,n)#define Sort(v) sort(v.begin(), v.end())#define Reverse(v) reverse(v.begin(), v.end())#define all(v) v.begin(),v.end()#define SZ(v) ((int)v.size())#define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x))#define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x))#define Max(a, b) a = max(a, b)#define Min(a, b) a = min(a, b)#define bit(n) (1LL<<(n))#define Ans(f, y, n) if(f) cout << y << endl; else cout << n << endl;#define debug(x) cout << #x << "=" << x << endl;#define vdebug(v) cout << #v << "=" << endl; REP(i, v.size()){ cout << v[i] << ","; } cout << endl;#define mdebug(m) cout << #m << "=" << endl; REP(i, m.size()){ REP(j, m[i].size()){ cout << m[i][j] << ","; } cout << endl;}#define pb push_back#define f first#define s second#define int long long#define INF 1000000000000000000using vec = vector<int>;using mat = vector<vec>;using Pii = pair<int, int>;using PiP = pair<int, Pii>;using PPi = pair<Pii, int>;using bools = vector<bool>;using pairs = vector<Pii>;template<typename T> void readv(vector<T> &a){ REP(i, a.size()) cin >> a[i]; }void readv_m1(vector<int> &a){ REP(i, a.size()){cin >> a[i]; a[i]--;} }//int dx[4] = {1,0,-1,0};//int dy[4] = {0,1,0,-1};int mod = 1000000007;//int mod = 998244353;#define Add(x, y) x = (x + (y)) % mod#define Mult(x, y) x = (x * (y)) % modint modpow(int x, int n, int m){int a = 1;IREP(i, 64){a = (a * a) % m;if(((n >> i) & 1) == 1) a = (a * x) % m;}return a;}int BinaryMat_calcrank(mat A){int n = A.size(), m = A[0].size();int r = 0, j = 0;REP(i, n){bool f = false;while(!f && j < m){FOR(i2, i, n){if(A[i2][j]){A[i].swap(A[i2]);r++;f = true;break;}}if(f){FOR(i2, i + 1, n) if(A[i2][j]){FOR(j2, j, m) A[i2][j2] ^= A[i][j2];}}j++;}}return r;}signed main(){int N, M, X; cin >> N >> M >> X;vec A(N); readv(A);vec t(M), l(M), r(M);REP(i, M){cin >> t[i] >> l[i] >> r[i];l[i]--; r[i]--;}int b = 30;mat U(b + M, vec(N, 0));vec v(b + M, 0);REP(i, N){REP(j, b) if((A[i] >> j) & 1) U[j][i] = 1;}REP(j, b) if((X >> j) & 1) v[j] = 1;REP(i, M){FOR(j, l[i], r[i] + 1) U[b + i][j] = 1;v[b + i] = t[i];}int f1 = N - BinaryMat_calcrank(U);//mdebug(U);//debug(f1);REP(i, b + M) U[i].pb(v[i]);int f2 = N - BinaryMat_calcrank(U);Ans(f1 == f2, modpow(2, f1, mod), 0);return 0;}