結果
問題 | No.803 Very Limited Xor Subset |
ユーザー |
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提出日時 | 2019-03-20 01:03:39 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 3 ms / 2,000 ms |
コード長 | 3,156 bytes |
コンパイル時間 | 915 ms |
コンパイル使用メモリ | 102,880 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-14 16:06:18 |
合計ジャッジ時間 | 2,201 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge6 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 43 |
ソースコード
#include<iostream>#include<vector>#include<algorithm>#include<queue>#include<stack>#include<cstring>#include<utility>#include<cmath>#include<assert.h>#include<set>#include<map>#include<unordered_set>#include<unordered_map>#include<complex>#include<bitset>#define int long longusing namespace std;#define rep(i, n) for(int i=0;i<(n);++i)typedef pair<int, int> pii;const int INF = 1l << 60;#define u_b upper_bound#define l_b lower_boundconst int MAX_ROW = 610;const int MAX_COL = 610;struct BitMatrix {int n, m;bitset<MAX_COL> val[MAX_ROW];BitMatrix(int n = 1, int m = 1) : n(n), m(m) {}inline bitset<MAX_COL> &operator[](int i) { return val[i]; }};int linear_equation(BitMatrix A, vector<int> b) {int rank = 0;rep(i, A.n)A[i][A.m] = b[i];rep(i, A.m) {int pivot = -1;for (int j = rank; j < A.n; ++j) {if (A[j][i]) {pivot = j;break;}}if (pivot != -1) {swap(A[pivot], A[rank]);rep(j, A.n)if (j != rank && A[j][i])A[j] ^= A[rank];++rank;}}for (int i = rank; i < A.n; ++i)if (A[i][A.m])return -1;return rank;}//const int mod = //998244353;const int mod = 1000000007;const int FacN = 0;//使わないなら0constexpr int power(int a, int b) {int res = 1;while (b) {if (b & 1)res *= a;a *= a;res %= mod;a %= mod;b /= 2;}return res;}constexpr int inv(int x) {return power(x, mod - 2);}const struct Fac {int val[FacN];constexpr Fac() : val() {if (FacN == 0)return;val[0] = 1;for (int i = 1; i < FacN; ++i) val[i] = val[i - 1] * i % mod;}const int &operator[](size_t i) const {return val[i];}} fac;const struct FacInv {int val[FacN];constexpr FacInv() : val() {if (FacN == 0)return;val[FacN - 1] = 1;for (int i = 1; i < FacN; ++i)val[FacN - 1] = val[FacN - 1] * i % mod;val[FacN - 1] = inv(val[FacN - 1]);for (int i = FacN - 1; i >= 1; --i)val[i - 1] = val[i] * i % mod;}const int &operator[](size_t i) const {return val[i];}} fac_inv;int Perm(int n, int r) {if (n < r) return 0;return fac[n] * fac_inv[n - r] % mod;}int Comb(int n, int r) {return Perm(n, r) * fac_inv[r] % mod;}//mod,Factorial書き換え//要検証const int DIGIT = 35;signed main() {int N, M, X;cin >> N >> M >> X;vector<int> a(N);rep(i, N) cin >> a[i];BitMatrix A(DIGIT + M, N);vector<int> b(DIGIT + M);rep(d, DIGIT) {rep(i, N) {if (a[i] & (1ll << d))A[d][i] = 1;}if (X & (1ll << d))b[d] = 1;}for (int d = 0; d < M; ++d) {int type, l, r;cin >> type >> l >> r;--l, --r;for (int i = l; i <= r; ++i)A[d + DIGIT][i] = 1;b[d + DIGIT] = type;}int rank = linear_equation(A, b);if (rank == -1)cout << 0 << endl;else cout << power(2, N - rank) << endl;return 0;}