結果
問題 | No.728 ギブ and テイク |
ユーザー |
|
提出日時 | 2019-03-29 23:24:51 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,589 bytes |
コンパイル時間 | 1,286 ms |
コンパイル使用メモリ | 122,904 KB |
実行使用メモリ | 27,860 KB |
最終ジャッジ日時 | 2024-11-07 01:30:55 |
合計ジャッジ時間 | 6,217 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 WA * 9 |
ソースコード
// includes#include <cstdio>#include <cstdint>#include <iostream>#include <iomanip>#include <string>#include <queue>#include <stack>#include <vector>#include <set>#include <map>#include <unordered_map>#include <algorithm>#include <utility>#include <functional>#include <cmath>#include <climits>#include <bitset>#include <list>#include <random>// macros#define ll long long int#define pb emplace_back#define mk make_pair#define pq priority_queue#define FOR(i, a, b) for(int i=(a);i<(b);++i)#define rep(i, n) FOR(i, 0, n)#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)#define all(x) (x).begin(),(x).end()#define sz(x) ((int)(x).size())#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())using namespace std;// typestypedef pair<int, int> P;typedef pair<ll, int> Pl;typedef pair<ll, ll> Pll;typedef pair<double, double> Pd;// constantsconst int inf = 1e9;const ll linf = 1LL << 50;const double EPS = 1e-10;const int mod = 1e9 + 7;// solvetemplate <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}template<typename T>struct BIT_{int n;vector<T> bit;BIT_(int n_){n = n_;bit = vector<T>(n+1, 0);}void add(int a, T w){for(int x = a; x < n; x |= (x + 1)){bit[x] += w;}}T sum(int a){T res = 0;for(int x = a; x >= 0; x = (x & (x + 1)) - 1){res += bit[x];}return res;}};typedef struct BIT_<int> BITI;typedef struct BIT_<long long> BITL;struct house{ll x, l, r;house(){ }house(ll x, ll l, ll r): x(x), l(l), r(r){}bool operator<(const house &right) const{return x < right.x;}};int main(int argc, char const* argv[]){ios_base::sync_with_stdio(false);cin.tie(0);int n;cin >> n;vector<ll> a(n), l(n), r(n);rep(i, n)cin >> a[i];rep(i, n)cin >> l[i] >> r[i];vector<house> h(n);rep(i, n)h[i] = house(a[i], l[i], r[i]);vector<Pl> vec(2 * n);rep(i, n){vec[2 * i] = mk(a[i], - i - 1);vec[2 * i + 1] = mk(a[i] + r[i], i + 1);}sort(all(vec));int res = 0;BITI bt(n);for(int i = 0; i < 2 * n; i++){if(vec[i].second < 0){int index = - vec[i].second - 1;int k = lower_bound(all(h), house(h[index].x - h[index].l, -1, -1)) - h.begin();if(index > 0)res += bt.sum(index - 1) - (k > 0 ? bt.sum(k-1): 0);bt.add(index, 1);}else{int index = vec[i].second - 1;bt.add(index, - 1);}}cout << res << endl;return 0;}