結果
問題 | No.823 Many Shifts Easy |
ユーザー | hitonanode |
提出日時 | 2019-04-26 21:43:53 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 6 ms / 2,000 ms |
コード長 | 4,465 bytes |
コンパイル時間 | 1,766 ms |
コンパイル使用メモリ | 172,900 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-11-25 02:55:38 |
合計ジャッジ時間 | 2,306 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 5 ms
6,816 KB |
testcase_04 | AC | 2 ms
6,816 KB |
testcase_05 | AC | 4 ms
6,820 KB |
testcase_06 | AC | 5 ms
6,816 KB |
testcase_07 | AC | 2 ms
6,816 KB |
testcase_08 | AC | 6 ms
6,816 KB |
testcase_09 | AC | 2 ms
6,820 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; using lint = long long int; using pint = pair<int, int>; using plint = pair<lint, lint>; struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++) #define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--) #define REP(i, n) FOR(i,0,n) #define IREP(i, n) IFOR(i,0,n) template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; } template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; } template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; } template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); } template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); } template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; } template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; } template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); } template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); } #define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl; #define FI first #define SE second #define ALL(x) (x).begin(), (x).end() #define SZ(x) ((lint)(x).size()) #define POW2(n) (1LL << (n)) constexpr lint MOD = 1000000007; vector<lint> fac, facInv, inv; void facInit(int nmax) { fac = facInv = inv = vector<lint>(nmax + 1, 1); for (int i = 2; i <= nmax; i++) { fac[i] = fac[i-1] * i % MOD; inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD; facInv[i] = facInv[i-1] * inv[i] % MOD; } } lint nCr(int n, int r) { if (n<r || r<0) return 0; if (n >= (int)fac.size()) facInit(n); return (fac[n] * facInv[r] % MOD) * facInv[n-r] % MOD; } lint nPr(int n, int r) { if (n<r || r<0) return 0; if (n >= (int)fac.size()) facInit(n); return fac[n] * facInv[n-r] % MOD; } lint power(lint x, lint n, lint mod=MOD) { lint ans = 1; while (n>0) { if (n & 1) (ans *= x) %= mod; (x *= x) %= mod; n >>= 1; } return ans; } lint doublefac(lint n) { if (n < 0) return 0; lint k = (n + 1) / 2; if (n & 1) return fac[k * 2] * power(facInv[2], k) % MOD * power(fac[k], MOD - 2) % MOD; else return fac[k] * power(facInv[2], k) % MOD; } int main() { lint N, K; cin >> N >> K; facInit(N); lint su1 = N % MOD * (N + 1) % MOD * inv[2] % MOD; dbg(su1); lint ret1 = nPr(N - 1, K) * su1 % MOD; lint su2 = N % MOD * (N - 1) % MOD * inv[2] % MOD; dbg(su2); lint ret2 = nPr(N - 2, K - 2) * (K - 1) % MOD * K % MOD * inv[2] % MOD * su2; dbg(ret1); dbg(ret2); cout << (ret1 + ret2) % MOD << endl; }