結果
問題 | No.117 組み合わせの数 |
ユーザー | fumiphys |
提出日時 | 2019-04-29 13:58:36 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,329 bytes |
コンパイル時間 | 1,436 ms |
コンパイル使用メモリ | 168,860 KB |
実行使用メモリ | 34,560 KB |
最終ジャッジ日時 | 2024-06-06 15:48:16 |
合計ジャッジ時間 | 2,185 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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コンパイルメッセージ
In function 'long long int comb(long long int, long long int)', inlined from 'int main(int, const char**)' at main.cpp:100:37: main.cpp:54:13: warning: 'k' may be used uninitialized [-Wmaybe-uninitialized] 54 | if(n == 0 && k == 0)return 1; | ~~~~~~~^~~~~~~~~ main.cpp: In function 'int main(int, const char**)': main.cpp:91:11: note: 'k' was declared here 91 | ll n, k; | ^ In function 'long long int comb(long long int, long long int)', inlined from 'int main(int, const char**)' at main.cpp:100:37: main.cpp:54:13: warning: 'n' may be used uninitialized [-Wmaybe-uninitialized] 54 | if(n == 0 && k == 0)return 1; | ~~~~~~~^~~~~~~~~ main.cpp: In function 'int main(int, const char**)': main.cpp:91:8: note: 'n' was declared here 91 | ll n, k; | ^
ソースコード
// includes #include <bits/stdc++.h> // macros #define ll long long int #define pb emplace_back #define mk make_pair #define pq priority_queue #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define FI first #define SE second using namespace std; // types typedef pair<int, int> P; typedef pair<ll, int> Pl; typedef pair<ll, ll> Pll; typedef pair<double, double> Pd; // constants const int inf = 1e9; const ll linf = 1LL << 50; const double EPS = 1e-10; const int mod = 1e9 + 7; // solve template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> T power(T a, T n, T mod) { T res = 1; T tmp = n; T curr = a; while(tmp){ if(tmp % 2 == 1){ res = (T)((ll)res * curr % mod); } curr = (T)((ll)curr * curr % mod); tmp >>= 1; } return res; } ll fac[2000001], inv[2000001]; ll comb(ll n, ll k){ if(n == 0 && k == 0)return 1; if(n < k)return 0; ll res = fac[n]; res = res * inv[k] % mod; res = res * inv[n-k] % mod; return res; } ll permu(ll n, ll k){ if(n < k)return 0; ll res = fac[n]; res = res * inv[n-k] % mod; return res; } ll h(ll n, ll k){ return comb(n + k - 1, k); } int main(int argc, char const* argv[]) { ios_base::sync_with_stdio(false); cin.tie(0); int t; cin >> t; fac[0] = 1; FOR(i, 1, 2000001){ fac[i] = i * fac[i-1] % mod; } inv[2000000] = power<ll>(fac[2000000], mod - 2, mod); for(int i = 1999999; i >= 0; i--){ inv[i] = (i + 1) * inv[i+1] % mod; } rep(i, t){ string s; cin >> s; string t = s.substr(2, sz(s) - 3); ll n, k; for(int j = 0; j < sz(t); j++){ if(t[j] == ','){ n = stol(t.substr(0, j)); k = stol(t.substr(j+1, sz(t) - j - 1)); break; } } if(s[0] == 'C')cout << comb(n, k) << endl; else if(s[0] == 'P')cout << permu(n, k) << endl; else cout << h(n, k) << endl; } return 0; }