結果
問題 | No.665 Bernoulli Bernoulli |
ユーザー |
👑 |
提出日時 | 2019-05-02 06:51:36 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 50 ms / 2,000 ms |
コード長 | 3,680 bytes |
コンパイル時間 | 932 ms |
コンパイル使用メモリ | 121,036 KB |
実行使用メモリ | 29,660 KB |
最終ジャッジ日時 | 2024-06-22 01:05:28 |
合計ジャッジ時間 | 2,621 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 15 |
ソースコード
import std.conv, std.functional, std.range, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.complex, std.container, std.math, std.numeric, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken.to!int; }long readLong() { return readToken.to!long; }real readReal() { return readToken.to!real; }bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;(unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }// a^-1 (mod m)long modInv(long a, long m)in {assert(m > 0, "modInv: m > 0 must hold");}do {long b = m, x = 1, y = 0, t;for (; ; ) {t = a / b;a -= t * b;if (a == 0) {assert(b == 1 || b == -1, "modInv: gcd(a, m) != 1");if (b == -1) {y = -y;}return (y < 0) ? (y + m) : y;}x -= t * y;t = b / a;b -= t * a;if (b == 0) {assert(a == 1 || a == -1, "modInv: gcd(a, m) != 1");if (a == -1) {x = -x;}return (x < 0) ? (x + m) : x;}y -= t * x;}}enum MO = 10L^^9 + 7;enum LIM = 10^^6;long[] inv, fac, invFac;void prepare() {inv = new long[LIM];fac = new long[LIM];invFac = new long[LIM];inv[1] = 1;foreach (i; 2 .. LIM) {inv[i] = MO - ((MO / i) * inv[cast(size_t)(MO % i)]) % MO;}fac[0] = invFac[0] = 1;foreach (i; 1 .. LIM) {fac[i] = (fac[i - 1] * i) % MO;invFac[i] = (invFac[i - 1] * inv[i]) % MO;}}long binom(long n, long k) {if (0 <= k && k <= n) {assert(n < LIM);return fac[cast(size_t)(n)] * invFac[cast(size_t)(k)] % MO * invFac[cast(size_t)(n - k)] % MO;} else {return 0;}}long power(long a, long e) {long x = a % MO, y = 1;for (; e; e >>= 1) {if (e & 1) {y = (y * x) % MO;}x = (x * x) % MO;}return y;}long N;int K;void main() {prepare();try {for (; ; ) {N = readLong();K = readInt();auto f = new long[K + 2];f[0] = 0;foreach (i; 1 .. K + 2) {f[i] = (f[i - 1] + power(i, K)) % MO;}bool zero;long prod = 1;foreach (i; 0 .. K + 2) {const d = (N - i) % MO;if (d == 0) {zero = true;} else {prod *= d;prod %= MO;}}debug {writeln("zero = ", zero, ", prod = ", prod);}long ans;foreach (i; 0 .. K + 2) {const d = (N - i) % MO;long tmp = f[i];if (zero) {tmp *= ((d == 0) ? prod : 0);tmp %= MO;} else {tmp *= prod;tmp %= MO;tmp *= modInv(d, MO);tmp %= MO;}tmp *= invFac[i];tmp %= MO;tmp *= invFac[K + 1 - i];tmp %= MO;tmp *= (((K + 1 - i) % 2 != 0) ? -1 : +1);tmp %= MO;ans += tmp;ans %= MO;}ans = (ans % MO + MO) % MO;writeln(ans);}} catch (EOFException e) {}}