結果
問題 | No.837 Noelちゃんと星々2 |
ユーザー | penguinshunya |
提出日時 | 2019-06-14 23:11:53 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,088 bytes |
コンパイル時間 | 2,745 ms |
コンパイル使用メモリ | 212,496 KB |
実行使用メモリ | 8,420 KB |
最終ジャッジ日時 | 2024-11-14 13:27:59 |
合計ジャッジ時間 | 4,068 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | AC | 56 ms
8,232 KB |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | AC | 2 ms
6,816 KB |
testcase_10 | AC | 2 ms
6,816 KB |
testcase_11 | AC | 2 ms
6,820 KB |
testcase_12 | AC | 2 ms
6,820 KB |
testcase_13 | AC | 2 ms
6,816 KB |
testcase_14 | AC | 2 ms
6,816 KB |
testcase_15 | AC | 2 ms
6,820 KB |
testcase_16 | AC | 2 ms
6,816 KB |
testcase_17 | AC | 2 ms
6,820 KB |
testcase_18 | AC | 2 ms
6,816 KB |
testcase_19 | WA | - |
testcase_20 | AC | 2 ms
6,816 KB |
testcase_21 | AC | 2 ms
6,816 KB |
testcase_22 | AC | 2 ms
6,816 KB |
testcase_23 | WA | - |
testcase_24 | AC | 2 ms
6,816 KB |
testcase_25 | WA | - |
testcase_26 | AC | 2 ms
6,816 KB |
testcase_27 | WA | - |
testcase_28 | AC | 2 ms
6,816 KB |
testcase_29 | AC | 2 ms
6,820 KB |
testcase_30 | AC | 2 ms
6,816 KB |
testcase_31 | AC | 2 ms
6,820 KB |
testcase_32 | AC | 2 ms
6,816 KB |
ソースコード
#include <bits/stdc++.h> #define rep(i, n) for (int i = 0; i < int(n); i++) #define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--) #define reps(i, n) for (int i = 1; i <= int(n); i++) #define rreps(i, n) for (int i = int(n); i >= 1; i--) #define repc(i, n) for (int i = 0; i <= int(n); i++) #define rrepc(i, n) for (int i = int(n); i >= 0; i--) #define repi(i, a, b) for (int i = int(a); i < int(b); i++) #define repic(i, a, b) for (int i = int(a); i <= int(b); i++) #define each(x, y) for (auto &x : y) #define all(a) (a).begin(), (a).end() #define bit(b) (1ll << (b)) #define uniq(v) (v).erase(unique(all(v)), (v).end()) using namespace std; using i32 = int; using i64 = long long; using f80 = long double; using vi32 = vector<i32>; using vi64 = vector<i64>; using vf80 = vector<f80>; using vstr = vector<string>; inline void yes() { cout << "Yes" << '\n'; exit(0); } inline void no() { cout << "No" << '\n'; exit(0); } inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); } inline i64 lcm(i64 a, i64 b) { return a / gcd(a, b) * b; } void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; } template <typename T> class pqasc : public priority_queue<T, vector<T>, greater<T>> {}; template <typename T> class pqdesc : public priority_queue<T, vector<T>, less<T>> {}; template <typename T> inline void amax(T &x, T y) { if (x < y) x = y; } template <typename T> inline void amin(T &x, T y) { if (x > y) x = y; } template <typename T> inline T power(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } template <typename T> istream& operator>>(istream &is, vector<T> &v) { for (auto &x : v) is >> x; return is; } template <typename T> ostream& operator<<(ostream &os, const vector<T> &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; } void solve() { int n; cin >> n; vi32 y(n); cin >> y; sort(all(y)); if (y[0] == y[n - 1]) { cout << 1 << '\n'; return; } { unordered_set<int> s; rep(i, n) s.insert(y[i]); if (s.size() == 2) { cout << 0 << '\n'; return; } } int li = 0, ri = n / 2; i64 ltotal = 0, rtotal = 0; { reps(i, n - 1) { rtotal += abs(y[ri] - y[i]); } } i64 ans = ltotal + rtotal; repic(i, 1, n - 2) { ltotal += y[i] - y[li]; rtotal -= y[ri] - y[i]; int ll = i / 2, rr = (n - i - 2) / 2 + i + 1; if (li < ll && y[li] < y[ll]) { int lc = lower_bound(all(y), y[ll]) - y.begin(); int rc = i - (lower_bound(all(y), y[li]) - y.begin()); ltotal += lc * (y[ll] - y[li]); ltotal -= rc * (y[ll] - y[li]); // cerr << lc * (y[ll] - y[li]) << '\n'; } if (ri < rr && y[ri] < y[rr]) { int lc = (lower_bound(all(y), y[ri]) - y.begin()) - i; int rc = y.end() - lower_bound(all(y), y[rr]); rtotal += lc * (y[rr] - y[ri]); rtotal -= rc * (y[rr] - y[ri]); } li = ll; ri = rr; amin(ans, ltotal + rtotal); } cout << ans << '\n'; }