結果
問題 | No.406 鴨等間隔の法則 |
ユーザー | penguinshunya |
提出日時 | 2019-07-12 04:56:16 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 50 ms / 2,000 ms |
コード長 | 2,801 bytes |
コンパイル時間 | 2,152 ms |
コンパイル使用メモリ | 210,588 KB |
実行使用メモリ | 8,320 KB |
最終ジャッジ日時 | 2024-07-07 12:39:21 |
合計ジャッジ時間 | 3,944 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 16 ms
5,504 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 37 ms
7,808 KB |
testcase_05 | AC | 13 ms
5,376 KB |
testcase_06 | AC | 14 ms
5,376 KB |
testcase_07 | AC | 15 ms
5,376 KB |
testcase_08 | AC | 39 ms
7,808 KB |
testcase_09 | AC | 42 ms
8,320 KB |
testcase_10 | AC | 15 ms
5,376 KB |
testcase_11 | AC | 31 ms
7,048 KB |
testcase_12 | AC | 20 ms
5,888 KB |
testcase_13 | AC | 18 ms
5,728 KB |
testcase_14 | AC | 42 ms
7,424 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 4 ms
5,376 KB |
testcase_17 | AC | 3 ms
5,376 KB |
testcase_18 | AC | 3 ms
5,376 KB |
testcase_19 | AC | 5 ms
5,376 KB |
testcase_20 | AC | 6 ms
5,376 KB |
testcase_21 | AC | 6 ms
5,376 KB |
testcase_22 | AC | 11 ms
5,376 KB |
testcase_23 | AC | 23 ms
6,016 KB |
testcase_24 | AC | 36 ms
6,824 KB |
testcase_25 | AC | 43 ms
8,320 KB |
testcase_26 | AC | 48 ms
8,192 KB |
testcase_27 | AC | 13 ms
5,376 KB |
testcase_28 | AC | 36 ms
8,192 KB |
testcase_29 | AC | 50 ms
8,320 KB |
testcase_30 | AC | 50 ms
8,192 KB |
testcase_31 | AC | 39 ms
7,936 KB |
ソースコード
#include <bits/stdc++.h> #define rep(i, n) for (int i = 0; i < int(n); i++) #define rrep(i, n) for (int i = int(n) - 1; i >= 0; i--) #define reps(i, n) for (int i = 1; i <= int(n); i++) #define rreps(i, n) for (int i = int(n); i >= 1; i--) #define repc(i, n) for (int i = 0; i <= int(n); i++) #define rrepc(i, n) for (int i = int(n); i >= 0; i--) #define repi(i, a, b) for (int i = int(a); i < int(b); i++) #define repic(i, a, b) for (int i = int(a); i <= int(b); i++) #define repp(i, n) rep(i, n) #define reppp(i, n) repp(i, n) #define rrepp(i, n) rrep(i, n) #define repss(i, n) reps(i, n) #define repcc(i, n) repc(i, n) #define repii(i, a, b) repi(i, a, b) #define each(x, y) for (auto &x : y) #define all(a) (a).begin(), (a).end() #define bit(b) (1ll << (b)) using namespace std; using i32 = int; using i64 = long long; using u64 = unsigned long long; using f80 = long double; using vi32 = vector<i32>; using vi64 = vector<i64>; using vu64 = vector<u64>; using vf80 = vector<f80>; using vstr = vector<string>; inline void yes() { cout << "Yes" << '\n'; exit(0); } inline void no() { cout << "No" << '\n'; exit(0); } inline i64 gcd(i64 a, i64 b) { if (min(a, b) == 0) return max(a, b); if (a % b == 0) return b; return gcd(b, a % b); } inline i64 lcm(i64 a, i64 b) { return a / gcd(a, b) * b; } inline u64 xorshift() { static u64 x = 88172645463325252ull; x = x ^ (x << 7); return x = x ^ (x >> 9); } void solve(); int main() { ios::sync_with_stdio(0); cin.tie(0); cout << fixed << setprecision(16); solve(); return 0; } template <typename T> class pqasc : public priority_queue<T, vector<T>, greater<T>> {}; template <typename T> class pqdesc : public priority_queue<T, vector<T>, less<T>> {}; template <typename T> inline void amax(T &x, T y) { if (x < y) x = y; } template <typename T> inline void amin(T &x, T y) { if (x > y) x = y; } template <typename T> inline T power(T x, i64 n, T e = 1) { T r = e; while (n > 0) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } template <typename T> istream& operator>>(istream &is, vector<T> &v) { each(x, v) is >> x; return is; } template <typename T> ostream& operator<<(ostream &os, vector<T> &v) { rep(i, v.size()) { if (i) os << ' '; os << v[i]; } return os; } template <typename T, typename S> istream& operator>>(istream &is, pair<T, S> &p) { is >> p.first >> p.second; return is; } template <typename T, typename S> ostream& operator<<(ostream &os, pair<T, S> &p) { os << p.first << ' ' << p.second; return os; } void solve() { int n; cin >> n; vi32 x(n); cin >> x; set<int> se; rep(i, n) se.insert(x[i]); if (se.size() != n) { cout << "NO" << '\n'; return; } sort(all(x)); int diff = x[1] - x[0]; rep(i, n - 1) if (x[i + 1] - x[i] != diff) { cout << "NO" << '\n'; exit(0); } cout << "YES" << '\n'; }