結果

問題 No.866 レベルKの正方形
ユーザー fine
提出日時 2019-08-16 23:50:30
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
実行時間 -
コード長 3,034 bytes
コンパイル時間 2,199 ms
コンパイル使用メモリ 188,168 KB
実行使用メモリ 95,904 KB
最終ジャッジ日時 2024-09-23 02:20:19
合計ジャッジ時間 10,324 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample -- * 3
other AC * 8 TLE * 1 -- * 13
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
struct segtree {
int H, W;
vector<vector<int>> dat;
segtree(){}
segtree(vector<vector<int>> &f) {
H = W = 1;
while(H < (int)f.size()) H <<= 1;
while(W < (int)f[0].size()) W <<= 1;
dat.assign(2*H-1,vector<int>(2*W-1,0));
init(f);
}
void init(vector<vector<int>> &f) {
for (int i = 0; i < (int)f.size(); i++)
for (int j = 0; j < (int)f[0].size(); j++)
dat[i+H-1][j+W-1] = f[i][j];
for (int i = 2*H-2; i > H-2; i--)
for (int j = W-2; j >= 0; j--)
dat[i][j] = (dat[i][2*j+1] | dat[i][2*j+2]);
for (int i = H-2; i >= 0; i--)
for (int j = 0; j < 2*W-1; j++)
dat[i][j] = (dat[2*i+1][j] | dat[2*i+2][j]);
}
int minimum(int li, int lj, int ri, int rj) { return minimum_h(li,lj,ri,rj,0,H,0); }
int minimum_h(int li, int lj, int ri, int rj, int si, int ti, int k) {
if(ri <= si or ti <= li) return 0;
if(li <= si and ti <= ri) return minimum_w(lj,rj,0,W,k,0);
const int mi = (si+ti)/2;
return (minimum_h(li,lj,ri,rj,si,mi,2*k+1) | minimum_h(li,lj,ri,rj,mi,ti,2*k+2));
}
int minimum_w(int lj, int rj, int sj, int tj, int i, int k) {
if(rj <= sj or tj <= lj) return 0;
if(lj <= sj and tj <= rj) return dat[i][k];
const int mj = (sj+tj)/2;
return (minimum_w(lj,rj,sj,mj,i,2*k+1) | minimum_w(lj,rj,mj,tj,i,2*k+2));
}
};
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
int h, w, K;
cin >> h >> w >> K;
vector<string> c(h);
vector< vector<int> > masks(h, vector<int>(w, 0));
for (int i = 0; i < h; i++) {
cin >> c[i];
for (int j = 0; j < w; j++) {
masks[i][j] = (1 << (c[i][j] - 'a'));
}
}
segtree seg(masks);
ll ans = 0;
for (int i = 0; i < h; i++) {
for (int j = 0; j < w; j++) {
int sz = min(i + 1, j + 1);
int ng = 0, ok = sz + 1;
while (ok - ng > 1) {
int mid = (ok + ng) / 2;
int val = seg.minimum(i + 1 - mid, j + 1 - mid, i + 1, j + 1);
if (__builtin_popcount(val) >= K) {
ok = mid;
} else {
ng = mid;
}
}
if (ok <= 0 || ok > sz) continue;
int ng2 = sz + 1, ok2 = -1;
while (ng2 - ok2 > 1) {
int mid = (ok2 + ng2) / 2;
int val = seg.minimum(i + 1 - mid, j + 1 - mid, i + 1, j + 1);
if (__builtin_popcount(val) <= K) {
ok2 = mid;
} else {
ng2 = mid;
}
}
if (ok2 <= 0 || ok2 > sz || ok > ok2) continue;
ans += ok2 - ok + 1;
//cerr << i << " " << j << ": " << ok << " " << ok2 << endl;
}
}
cout << ans << "\n";
return 0;
}
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