結果

問題 No.117 組み合わせの数
ユーザー nebukuro09
提出日時 2019-08-23 11:07:06
言語 D
(dmd 2.109.1)
結果
AC  
実行時間 128 ms / 5,000 ms
コード長 2,554 bytes
コンパイル時間 1,547 ms
コンパイル使用メモリ 149,784 KB
実行使用メモリ 12,668 KB
最終ジャッジ日時 2024-06-22 02:23:18
合計ジャッジ時間 2,473 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
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ファイルパターン 結果
other AC * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import std.stdio, std.array, std.string, std.conv, std.algorithm;
import std.typecons, std.range, std.random, std.math, std.container;
import std.numeric, std.bigint, core.bitop, core.stdc.stdio;
immutable long MAX = 2*10^^6+1;
immutable uint MOD = 10^^9 + 7;
alias mint = ModInt!MOD;
void main() {
auto f = new mint[](MAX);
f[0] = f[1] = mint(1);
foreach(i; 2..MAX) {
f[i] = f[i-1] * i;
}
int T, N, K;
char CPH;
scanf("%d\n", &T);
foreach(i; 0..T) {
scanf("%c(%d,%d)\n", &CPH, &N, &K);
if (CPH == 'C') {
if (N < K) {writeln(0); continue;}
writeln(f[N] / f[N-K] / f[K]);
}
else if (CPH == 'P') {
if (N < K) {writeln(0); continue;}
writeln(f[N] / f[N-K]);
}
else {
if (N == 0 && K == 0) {writeln(1); continue;}
if (N == 0) {writeln(0); continue;}
writeln(f[N+K-1] / f[N-1] / f[K]);
}
}
}
struct ModInt(uint mod) {
import std.conv : to;
uint n;
this(int n) {
this.n = (n % mod + mod) % mod;
}
this(long n) {
this.n = (n % mod + mod) % mod;
}
private this(uint n) {
this.n = n;
}
string toString() {
return to!string(this.n);
}
private uint normilize(uint n) const {
return n < mod ? n : n - mod;
}
private ModInt pow(uint n, long x) const {
long ret = 1;
long a = n;
while (x) {
if (x & 1) ret = ret * a % mod;
a = a * a % mod;
x >>= 1;
}
return ModInt(to!ulong(ret));
}
ModInt opBinary(string op : "+")(ModInt rhs) const {
return ModInt(normilize(n + rhs.n));
}
ModInt opBinary(string op : "-")(ModInt rhs) const {
return ModInt(normilize(n + mod - rhs.n));
}
ModInt opBinary(string op : "*")(ModInt rhs) const {
return ModInt(to!uint(to!long(n) * rhs.n % mod));
}
ModInt opBinary(string op : "/")(ModInt rhs) const {
return this * pow(rhs.n, mod-2);
}
ModInt opBinary(string op : "^^")(ModInt rhs) const {
return pow(this.n, rhs.n);
}
ModInt opBinary(string op, T)(T rhs) {
ModInt mod_rhs = ModInt(rhs);
return opBinary!op(mod_rhs);
}
ModInt opOpAssign(string op)(ModInt rhs) {
return mixin ("this=this"~op~"rhs");
}
ModInt opOpAssign(string op, T)(T rhs) {
ModInt mod_rhs = ModInt(rhs);
return mixin ("this=this"~op~"mod_rhs");
}
}
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