結果
問題 | No.876 Range Compress Query |
ユーザー | fumiphys |
提出日時 | 2019-09-06 21:41:18 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 7,601 bytes |
コンパイル時間 | 2,145 ms |
コンパイル使用メモリ | 182,404 KB |
実行使用メモリ | 9,956 KB |
最終ジャッジ日時 | 2024-06-24 17:17:19 |
合計ジャッジ時間 | 5,578 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | WA | - |
testcase_02 | AC | 2 ms
6,944 KB |
testcase_03 | WA | - |
testcase_04 | AC | 2 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 4 ms
6,940 KB |
testcase_07 | WA | - |
testcase_08 | AC | 3 ms
6,940 KB |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | AC | 311 ms
9,716 KB |
testcase_12 | AC | 259 ms
9,460 KB |
testcase_13 | AC | 252 ms
9,436 KB |
testcase_14 | AC | 299 ms
9,572 KB |
testcase_15 | AC | 199 ms
9,672 KB |
testcase_16 | AC | 298 ms
9,664 KB |
testcase_17 | AC | 292 ms
9,956 KB |
testcase_18 | AC | 317 ms
9,904 KB |
ソースコード
// includes #include <bits/stdc++.h> using namespace std; // macros #define pb emplace_back #define mk make_pair #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr) #define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define bit(n) (1LL<<(n)) // functions template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} // types using ll = long long int; using P = pair<int, int>; // constants const int inf = 1e9; const ll linf = 1LL << 50; const double EPS = 1e-10; const int mod = 1000000007; const int dx[4] = {-1, 0, 1, 0}; const int dy[4] = {0, -1, 0, 1}; // io struct fast_io{ fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);} } fast_io_; template<typename T, typename E> struct LazySegmentTree_ { function<T(T, T)> f; // aggregation function<E(E, E)> h; // update lazy element function<T(T, E, int)> p; // update element with lazy element int n; T def; E l_def; vector<T> vec; vector<E> lazy; LazySegmentTree_(){} LazySegmentTree_(int n_, function<T(T, T)> f, T def, function<E(E, E)> h, E l_def, function<T(T, E, int)> p, vector<T> v=vector<T>()): f(f), def(def), h(h), l_def(l_def), p(p){ // initialize vector n = 1; while(n < n_){ n *= 2; } vec = vector<T>(2*n-1, def); lazy = vector<E>(2*n-1, l_def); // initialize segment tree for(int i = 0; i < v.size(); i++){ vec[i + n - 1] = v[i]; } for(int i = n - 2; i >= 0; i--){ vec[i] = f(vec[2*i+1], vec[2*i+2]); } } void eval(int k, int len){ if(lazy[k] != l_def){ if(k < n - 1){ lazy[2*k+1] = h(lazy[2*k+1], lazy[k]); lazy[2*k+2] = h(lazy[2*k+2], lazy[k]); } vec[k] = p(vec[k], lazy[k], len); lazy[k] = l_def; } } E update(int a, int b, const E &val, int k, int l, int r){ eval(k, r - l); if(r <= a || b <= l){ return vec[k]; }else if(a <= l && r <= b){ lazy[k] = h(lazy[k], val); eval(k, r - l); return vec[k]; }else{ return vec[k] = f(update(a, b, val, 2*k+1, l, (l+r)/2), update(a, b, val, 2*k+2, (l+r)/2, r)); } } E update(int a, int b, E val){ return update(a, b, val, 0, 0, n); } // [l, r) -> [a, b) (at k) T query(int a, int b, int k, int l, int r){ eval(k, r - l); if(r <= a || b <= l)return def; if(a <= l && r <= b)return vec[k]; T ld = query(a, b, 2*k+1, l, (l+r)/2); T rd = query(a, b, 2*k+2, (l+r)/2, r); return f(ld, rd); } T query(int a, int b){ return query(a, b, 0, 0, n); } }; template<typename T, typename E> using LazySegmentTree = struct LazySegmentTree_<T, E>; using LazySegmentTreeI = LazySegmentTree<int, int>; using LazySegmentTreeL = LazySegmentTree<long long, long long>; template<typename T, typename E> struct SegmentTree_ { function<T(T, T)> f; // aggregate function function<T(T, E)> g; // update function int n; T def; vector<T> vec; SegmentTree_(){} SegmentTree_(int n_, function<T(T, T)> f, function<T(T, E)> g, T def, vector<T> v=vector<T>()): f(f), g(g), def(def){ // initialize vector n = 1; while(n < n_){ n *= 2; } vec = vector<T>(2*n -1, def); // initialize segment tree for(int i = 0; i < v.size(); i++){ vec[i + n - 1] = v[i]; } for(int i = n - 2; i >= 0; i--){ vec[i] = f(vec[2*i+1], vec[2*i+2]); } } void update(int k, const E &val){ k = k + n - 1; vec[k] = g(vec[k], val); while(k > 0){ k = (k - 1) / 2; vec[k] = f(vec[2*k+1], vec[2*k+2]); } } // [l, r) -> [a, b) (at k) T query(int a, int b, int k, int l, int r){ if(r <= a || b <= l)return def; if(a <= l && r <= b)return vec[k]; T ld = query(a, b, 2*k+1, l, (l+r)/2); T rd = query(a, b, 2*k+2, (l+r)/2, r); return f(ld, rd); } T query(int a, int b){ return query(a, b, 0, 0, n); } }; template<typename T, typename E> using SegmentTree = struct SegmentTree_<T, E>; using SegmentTreeI = SegmentTree<int, int>; using SegmentTreeL = SegmentTree<long long, long long>; int main(int argc, char const* argv[]) { int n, q; cin >> n >> q; vector<ll> a(n); cin >> a; using Pll = pair<ll, ll>; vector<int> v(n - 1, 1); rep(i, n)if(a[i] == a[i+1])v[i] = 0; LazySegmentTreeL seg = LazySegmentTreeL(n, [](ll a, ll b){return a + b;}, 0, [](ll a, ll b){return a + b;}, 0, [](ll a, ll b, int c){return a + b * c;}, vector<ll>(n, 0)); SegmentTreeI seg2 = SegmentTreeI(n - 1, [](int a, int b){return a + b;}, [](int a, int b){return b;}, 0, v); rep(i, q){ int c; cin >> c; if(c == 1){ int l, r; ll x; cin >> l >> r >> x, l--, r--; seg.update(l, r + 1, x); if(l > 0){ ll al = seg.query(l, l + 1); ll al1 = seg.query(l - 1, l); int k = (al == al1 ? 0: 1); seg2.update(l - 1, k); } if(r < n - 1){ ll ar = seg.query(r, r + 1); ll ar1 = seg.query(r + 1, r + 2); int k = (ar == ar1 ? 0: 1); seg2.update(r, k); } }else{ int l, r; cin >> l >> r, l--, r--; int p = seg2.query(l, r); cout << p + 1 << endl; } } return 0; }