結果

問題 No.876 Range Compress Query
ユーザー fumiphysfumiphys
提出日時 2019-09-06 21:42:43
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 290 ms / 2,000 ms
コード長 7,586 bytes
コンパイル時間 2,439 ms
コンパイル使用メモリ 183,036 KB
実行使用メモリ 9,956 KB
最終ジャッジ日時 2024-06-24 17:18:45
合計ジャッジ時間 5,193 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge5
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 3 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 3 ms
5,376 KB
testcase_04 AC 3 ms
5,376 KB
testcase_05 AC 3 ms
5,376 KB
testcase_06 AC 3 ms
5,376 KB
testcase_07 AC 4 ms
5,376 KB
testcase_08 AC 3 ms
5,376 KB
testcase_09 AC 2 ms
5,376 KB
testcase_10 AC 3 ms
5,376 KB
testcase_11 AC 290 ms
9,460 KB
testcase_12 AC 227 ms
9,456 KB
testcase_13 AC 226 ms
9,564 KB
testcase_14 AC 269 ms
9,564 KB
testcase_15 AC 184 ms
9,672 KB
testcase_16 AC 261 ms
9,904 KB
testcase_17 AC 257 ms
9,956 KB
testcase_18 AC 282 ms
9,776 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

// includes
#include <bits/stdc++.h>
using namespace std;

// macros
#define pb emplace_back
#define mk make_pair
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define bit(n) (1LL<<(n))
// functions
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
//  types
using ll = long long int;
using P = pair<int, int>;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1000000007;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// io
struct fast_io{
  fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);}
} fast_io_;

template<typename T, typename E>
struct LazySegmentTree_ {
  function<T(T, T)> f; // aggregation
  function<E(E, E)> h; // update lazy element
  function<T(T, E, int)> p; // update element with lazy element
  int n;
  T def;
  E l_def;
  vector<T> vec;
  vector<E> lazy;
  LazySegmentTree_(){}
  LazySegmentTree_(int n_, function<T(T, T)> f, T def,
                   function<E(E, E)> h, E l_def, function<T(T, E, int)> p,
                   vector<T> v=vector<T>()): f(f), def(def), h(h), l_def(l_def), p(p){

    // initialize vector
    n = 1;
    while(n < n_){
      n *= 2;
    }
    vec = vector<T>(2*n-1, def);
    lazy = vector<E>(2*n-1, l_def);

    // initialize segment tree
    for(int i = 0; i < v.size(); i++){
      vec[i + n - 1] = v[i];
    }
    for(int i = n - 2; i >= 0; i--){
      vec[i] = f(vec[2*i+1], vec[2*i+2]);
    }
  }
  void eval(int k, int len){
    if(lazy[k] != l_def){
      if(k < n - 1){
        lazy[2*k+1] = h(lazy[2*k+1], lazy[k]);
        lazy[2*k+2] = h(lazy[2*k+2], lazy[k]);
      }
      vec[k] = p(vec[k], lazy[k], len);
      lazy[k] = l_def;
    }
  }
  E update(int a, int b, const E &val, int k, int l, int r){
    eval(k, r - l);
    if(r <= a || b <= l){
      return vec[k];
    }else if(a <= l && r <= b){
      lazy[k] = h(lazy[k], val);
      eval(k, r - l);
      return vec[k];
    }else{
      return vec[k] = f(update(a, b, val, 2*k+1, l, (l+r)/2),
                        update(a, b, val, 2*k+2, (l+r)/2, r));
    }
  }
  E update(int a, int b, E val){
    return update(a, b, val, 0, 0, n);
  }
  // [l, r) -> [a, b) (at k)
  T query(int a, int b, int k, int l, int r){
    eval(k, r - l);
    if(r <= a || b <= l)return def;
    if(a <= l && r <= b)return vec[k];
    T ld = query(a, b, 2*k+1, l, (l+r)/2);
    T rd = query(a, b, 2*k+2, (l+r)/2, r);
    return f(ld, rd);
  }
  T query(int a, int b){
    return query(a, b, 0, 0, n);
  }
};

template<typename T, typename E>
using LazySegmentTree = struct LazySegmentTree_<T, E>;
using LazySegmentTreeI = LazySegmentTree<int, int>;
using LazySegmentTreeL = LazySegmentTree<long long, long long>;

template<typename T, typename E>
struct SegmentTree_ {
  function<T(T, T)> f; // aggregate function
  function<T(T, E)> g; // update function
  int n;
  T def;
  vector<T> vec;
  SegmentTree_(){}
  SegmentTree_(int n_, function<T(T, T)> f, function<T(T, E)> g, T def, vector<T> v=vector<T>()): f(f), g(g), def(def){

    // initialize vector
    n = 1;
    while(n < n_){
      n *= 2;
    }
    vec = vector<T>(2*n -1, def);

    // initialize segment tree
    for(int i = 0; i < v.size(); i++){
      vec[i + n - 1] = v[i];
    }
    for(int i = n - 2; i >= 0; i--){
      vec[i] = f(vec[2*i+1], vec[2*i+2]);
    }
  }
  void update(int k, const E &val){
    k = k + n - 1;
    vec[k] = g(vec[k], val);
    while(k > 0){
      k = (k - 1) / 2;
      vec[k] = f(vec[2*k+1], vec[2*k+2]);
    }
  }
  // [l, r) -> [a, b) (at k)
  T query(int a, int b, int k, int l, int r){
    if(r <= a || b <= l)return def;
    if(a <= l && r <= b)return vec[k];
    T ld = query(a, b, 2*k+1, l, (l+r)/2);
    T rd = query(a, b, 2*k+2, (l+r)/2, r);
    return f(ld, rd);
  }
  T query(int a, int b){
    return query(a, b, 0, 0, n);
  }
};

template<typename T, typename E>
using SegmentTree = struct SegmentTree_<T, E>;
using SegmentTreeI = SegmentTree<int, int>;
using SegmentTreeL = SegmentTree<long long, long long>;


int main(int argc, char const* argv[])
{
  int n, q;
  cin >> n >> q;
  vector<ll> a(n);
  cin >> a;
  using Pll = pair<ll, ll>;
  vector<int> v(n - 1, 1);
  rep(i, n)if(a[i] == a[i+1])v[i] = 0;
  LazySegmentTreeL seg = LazySegmentTreeL(n, [](ll a, ll b){return a + b;},
                                          0, [](ll a, ll b){return a + b;},
                                          0, [](ll a, ll b, int c){return a + b * c;},
                                          a);

  SegmentTreeI seg2 = SegmentTreeI(n - 1, [](int a, int b){return a + b;},
                                   [](int a, int b){return b;},
                                   0, v);
  rep(i, q){
    int c;
    cin >> c;
    if(c == 1){
      int l, r;
      ll x;
      cin >> l >> r >> x, l--, r--;
      seg.update(l, r + 1, x);
      if(l > 0){
        ll al = seg.query(l, l + 1);
        ll al1 = seg.query(l - 1, l);
        int k = (al == al1 ? 0: 1);
        seg2.update(l - 1, k);
      }
      if(r < n - 1){
        ll ar = seg.query(r, r + 1);
        ll ar1 = seg.query(r + 1, r + 2);
        int k = (ar == ar1 ? 0: 1);
        seg2.update(r, k);
      }
    }else{
      int l, r;
      cin >> l >> r, l--, r--;
      int p = seg2.query(l, r);
      cout << p + 1 << endl;
    }
  }
  return 0;
}
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