結果

問題 No.877 Range ReLU Query
ユーザー ningenMeningenMe
提出日時 2019-09-06 22:23:15
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 402 ms / 2,000 ms
コード長 5,192 bytes
コンパイル時間 2,358 ms
コンパイル使用メモリ 179,668 KB
実行使用メモリ 15,292 KB
最終ジャッジ日時 2024-04-25 22:03:33
合計ジャッジ時間 7,407 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge3
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,812 KB
testcase_01 AC 4 ms
6,940 KB
testcase_02 AC 3 ms
6,944 KB
testcase_03 AC 4 ms
6,940 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 3 ms
6,940 KB
testcase_06 AC 3 ms
6,940 KB
testcase_07 AC 2 ms
6,944 KB
testcase_08 AC 4 ms
6,940 KB
testcase_09 AC 2 ms
6,940 KB
testcase_10 AC 4 ms
6,940 KB
testcase_11 AC 390 ms
14,588 KB
testcase_12 AC 337 ms
13,712 KB
testcase_13 AC 273 ms
10,480 KB
testcase_14 AC 287 ms
10,784 KB
testcase_15 AC 402 ms
14,848 KB
testcase_16 AC 382 ms
14,592 KB
testcase_17 AC 389 ms
14,736 KB
testcase_18 AC 387 ms
14,580 KB
testcase_19 AC 348 ms
15,292 KB
testcase_20 AC 389 ms
15,160 KB
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ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;

#define REP(i,n) for(long long i = 0; i < (n); i++)
#define FOR(i, m, n) for(long long i = (m);i < (n); ++i)
#define ALL(obj) (obj).begin(),(obj).end()
#define SPEED cin.tie(0);ios::sync_with_stdio(false);

template<class T> using V = vector<T>;
template<class T, class U> using P = pair<T, U>;
template<class T> using PQ = priority_queue<T>;
template<class T> using PQR = priority_queue<T,vector<T>,greater<T>>;

constexpr long long MOD = (long long)1e9 + 7;
constexpr long long MOD2 = 998244353;
constexpr long long HIGHINF = (long long)1e18;
constexpr long long LOWINF = (long long)1e15;
constexpr long double PI = 3.1415926535897932384626433;

template <class T> vector<T> make_v(size_t N,T init){return vector<T>(N,init);}
template <class... T> auto make_v(size_t N,T... t){return vector<decltype(make_v(t...))>(N,make_v(t...));}
template <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}
template <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << "{"; for (auto &x : obj) o << " {" << x.first << " : " << x.second << "}" << ","; o << " }"; return o;}
template <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
template <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << "{"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? ", " : "") << obj[i]; o << "}"; return o;}
template <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << "{" << obj.first << ", " << obj.second << "}"; return o;}
template <template <class tmp>  class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << "{"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? ", " : "") << *itr; o << "}"; return o;}
void print(void) {cout << endl;}
template <class Head> void print(Head&& head) {cout << head;print();}
template <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << " ";print(forward<Tail>(tail)...);}
template <class T> void chmax(T& a, const T b){a=max(a,b);}
template <class T> void chmin(T& a, const T b){a=min(a,b);}
void YN(bool flg) {cout << (flg ? "YES" : "NO") << endl;}
void Yn(bool flg) {cout << (flg ? "Yes" : "No") << endl;}
void yn(bool flg) {cout << (flg ? "yes" : "no") << endl;}

template<class T> class Segment_Tree_Range_Sum_Query {
	size_t N,M;
	T ini;
	vector<T> node;

public:
	Segment_Tree_Range_Sum_Query(const vector<T> & ar, const T ini) : M(ar.size()), ini(ini) {
		for (N = 1; N < M; N *= 2);
		node.resize(2 * N - 1, ini);
		for (int i = 0; i < M; ++i) node[i + N - 1] = ar[i];
		for (int i = N - 2; i >= 0; --i) node[i] = node[2 * i + 1]+node[2 * i + 2];
	}
 
	Segment_Tree_Range_Sum_Query(const size_t M, const T ini) : M(M), ini(ini) {
		for (N = 1; N < M; N *= 2);
		node.resize(2 * N - 1, ini);
	}
	
	void update(size_t idx, const T var) {
		idx += (N - 1);
		node[idx] += var;
		while (idx > 0) {
			idx = (idx - 1) / 2;
			node[idx] = node[2 * idx + 1]+node[2 * idx + 2];
		}
	}
 
	T getvar(const int a, const int b, int k = 0, int l = 0, int r = -1) {
		if (r < 0) r = N;
		if (r <= a || b <= l) return ini;
		if (a <= l && r <= b) return node[k];
		T vl = getvar(a, b, 2 * k + 1, l, (l + r) / 2);
		T vr = getvar(a, b, 2 * k + 2, (l + r) / 2, r);
		return vl+vr;
	}
	
	T operator[](size_t idx) {
		return node[idx + N - 1];
	}

	T operator[](pair<size_t, size_t> p) {
		return getvar(p.first, p.second);
	}

 
	void print(){
		cout << "{ " << getvar(0,1);
		for(int i = 1; i < M; ++i) cout << ", " << getvar(i,i+1);
		cout << " }" << endl;
	}
};


//Seat Pressure O(NlogN)
template<class T> vector<int> Zarts(const vector<T> & ar, int cnt = 0) {
    vector<T> res;
    map<T, int> mp;
    for (auto &e : ar) mp[e] = 0;
    for (auto &e : mp) e.second = cnt++;
    for (auto &e : ar) res.push_back(mp[e]);
    return res;
}


int main() {
    int N,Q; cin >> N >> Q;
    vector<ll> a(N),q(Q),l(Q),r(Q),x(Q);
    for(int i = 0; i < N; ++i) cin >> a[i];
    for(int i = 0; i < Q; ++i) cin >> q[i] >> l[i] >> r[i] >> x[i];
    vector<pair<ll,int>> ord;
    priority_queue<pair<ll,int>> pq;
    for(int i = 0; i < N; ++i) pq.push({a[i],i});
    for(int i = 0; i < Q; ++i) ord.push_back({x[i],i});
    sort(ALL(ord));
    vector<ll> ans(Q);
    Segment_Tree_Range_Sum_Query<ll> seg1(N,0),seg2(N,0);
    for(int i = Q-1; 0 <= i; --i) {
        int j = ord[i].second;
        while(pq.size() && pq.top().first>=x[j]){
            int k = pq.top().second;
            pq.pop();
            seg1.update(k,a[k]);
            seg2.update(k,1);            
        }
        l[j]--; r[j]--;
        ans[j] = seg1.getvar(l[j],r[j]+1) - seg2.getvar(l[j],r[j]+1)*x[j]; 
    }
    for(int i = 0; i < Q; ++i) cout << ans[i] << endl;
    
    
    return 0;
}
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