結果
問題 | No.117 組み合わせの数 |
ユーザー | fumiphys |
提出日時 | 2019-09-10 03:25:37 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 124 ms / 5,000 ms |
コード長 | 4,880 bytes |
コンパイル時間 | 1,638 ms |
コンパイル使用メモリ | 171,400 KB |
実行使用メモリ | 34,688 KB |
最終ジャッジ日時 | 2024-07-02 16:11:31 |
合計ジャッジ時間 | 2,473 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ソースコード
// includes #include <bits/stdc++.h> using namespace std; // macros #define pb emplace_back #define mk make_pair #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr) #define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr) #define all(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end()) #define bit(n) (1LL<<(n)) // functions template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} // types using ll = long long int; using P = pair<int, int>; // constants const int inf = 1e9; const ll linf = 1LL << 50; const double EPS = 1e-10; const int mod = 1000000007; const int dx[4] = {-1, 0, 1, 0}; const int dy[4] = {0, -1, 0, 1}; // io struct fast_io{ fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);} } fast_io_; template <typename T> T power(T a, T n, T mod) { T res = 1; T tmp = n; T curr = a; while(tmp){ if(tmp % 2 == 1){ res = (T)(res * curr % mod); } curr = (T)(curr * curr % mod); tmp >>= 1; } return res; } struct Factorial{ int n = 0; static const long long mod_default = 1e9 + 7; long long MOD = mod_default; vector<long long> fac; vector<long long> inv_; explicit Factorial(){} explicit Factorial(int n, long long mod_=mod_default): n(n), MOD(mod_){ assert(MOD > 0 && n < MOD); fac.resize(n + 1); inv_.resize(n + 1); calc_factorial(); calc_inv(); } void calc_factorial(){ fac[0] = 1; for(int i = 1; i <= n; i++){ fac[i] = i * fac[i-1] % MOD; } } void calc_inv(){ inv_[n] = power<long long>(fac[n], MOD - 2, MOD); for(int i = n - 1; i >= 0; i--){ inv_[i] = (i + 1) * inv_[i+1] % MOD; } } long long& operator[](size_t i){ if((int)i > n){ cerr << "list index out of range" << endl; abort(); } return fac[i]; } long long inv(size_t i){ if((int)i > n){ cerr << "list index out of range" << endl; abort(); } return inv_[i]; } long long comb(int n, int k){ if(n < 0 || k < 0 || n < k)return 0; long long res = fac[n]; res = res * inv_[n-k] % MOD; res = res * inv_[k] % MOD; return res; } long long perm(int n, int k){ if(n < 0 || k < 0 || n < k)return 0; long long res = fac[n]; res = res * inv_[n-k] % MOD; return res; } long long h(int n, int k){ if(n == 0 && k == 0)return 1; return comb(n + k - 1, k); } }; int main(int argc, char const* argv[]) { int t; scanf("%d\n", &t); Factorial fac(2000010); rep(i, t){ char c; int n, k; scanf("%c(%d,%d)\n", &c, &n, &k); ll res = 0; if(c == 'C'){ res = fac.comb(n, k); }else if(c == 'P'){ res = fac.perm(n, k); }else{ res = fac.h(n, k); } printf("%lld\n", res); } return 0; }