結果

問題 No.142 単なる配列の操作に関する実装問題
ユーザー fumiphys
提出日時 2019-09-15 20:40:51
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2,415 ms / 5,000 ms
コード長 5,419 bytes
コンパイル時間 1,415 ms
コンパイル使用メモリ 174,516 KB
実行使用メモリ 23,124 KB
最終ジャッジ日時 2024-07-06 22:50:42
合計ジャッジ時間 9,979 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
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ファイルパターン 結果
other AC * 5
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ソースコード

diff #
プレゼンテーションモードにする

// includes
#include <bits/stdc++.h>
using namespace std;
// macros
#define pb emplace_back
#define mk make_pair
#define FOR(i, a, b) for(int i=(a);i<(b);++i)
#define rep(i, n) FOR(i, 0, n)
#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)
#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)
#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define bit(n) (1LL<<(n))
// functions
template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}
template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}
template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}
template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size
    ())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr =
    itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr;
    auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto
    titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os <<
    *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << " " << p.second; return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os <<
    itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end();
    ++itr){ os << itr->first << ":" << itr->second; auto titr = itr; if(++titr != mp.end())os << " "; } return os;}
// types
using ll = long long int;
using P = pair<int, int>;
// constants
const int inf = 1e9;
const ll linf = 1LL << 50;
const double EPS = 1e-10;
const int mod = 1000000007;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, -1, 0, 1};
// io
struct fast_io{
fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);}
} fast_io_;
const int b = 60;
ll val[100010];
vector<ll> V;
int U;
void add(int s, int t, int u, int v){
if(v - u + 1 <= 2 * b){
for(int i = u; i <= v; i++){
int j = s + i - u;
int I = i / b;
int J = j / b;
V[I-U/b] ^= (bit(b - 1 - i % b) * ((val[J] >> (b - 1 - j % b)) & 1));
}
return;
}
V.clear();
U = u;
for(int i = u / b; i <= v / b; i++){
V.pb(val[i]);
}
int l = 0, r = 0;
for(int i = u / b + 1; i < v / b; i++){
l = i * b, r = l + b - 1;
int ld = s + l - u, rd = s + r - u;
ll tmp = 0;
tmp += (val[ld / b] & (bit(b - ld % b) - 1)) << (ld % b);
if(ld % b){
tmp += (val[rd / b] >> (b - 1 - rd % b));
}
V[i-u/b] ^= tmp;
}
l = u, r = (u / b) * b + b - 1;
add(s, s + r - l, l, r);
l = (v / b) * b, r = v;
add(t - r + l, t, l, r);
for(int i = u / b; i <= v / b; i++){
val[i] = V[i-u/b];
}
}
int main(int argc, char const* argv[])
{
int n;
ll S, x, y, z;
cin >> n >> S >> x >> y >> z;
vector<ll> a(n);
a[0] = S;
FOR(i, 1, n){
a[i] = (x * a[i-1] + y) % z;
}
for(int i = 0; i < n; i += b){
int I = i / b;
for(int j = 0; j < b; j++){
if(i + j >= n)break;
val[I] += bit(b-1-j) * (a[i+j] & 1);
}
}
rep(i, n)a[i] %= 2;
int q;
cin >> q;
rep(i_, q){
int s, t, u, v;
cin >> s >> t >> u >> v, s--, t--, u--, v--;
/*for(int i = 0; i < n; i+=b){
int I = i / b;
for(int j = 0; j < b; j++){
if(i + j >= n)break;
cout << ((val[I] & bit(b-1-j)) ? 1: 0);
}
}
cout << endl;
for(int i = 0; i < n; i++){
cout << a[i];
}
cout << endl;*/
if(v - u + 1 <= 2 * b){
V.clear();
U = u;
for(int i = u / b; i <= v / b; i++){
V.pb(val[i]);
}
}
add(s, t, u, v);
if(v - u + 1 <= 2 * b){
for(int i = u / b; i <= v / b; i++){
val[i] = V[i-u/b];
}
}
/*vector<ll> c = a;
for(int i = u; i <= v; i++){
c[i] = (c[i] + a[s+i-u]) % 2;
}
swap(c, a);
for(int i = 0; i < n; i++){
if(u <= i && i <= v)cout << "-";
else cout << " ";
}
cout << endl;
for(int i = 0; i < n; i++){
if(s <= i && i <= t)cout << "-";
else cout << " ";
}
cout << endl;*/
// cout << s << " " << t << " " << u << " " << v << endl;
}
string s = "";
for(int i = 0; i < n; i+=b){
int I = i / b;
for(int j = 0; j < b; j++){
if(i + j >= n)break;
s += (val[I] & bit(b-1-j)) ? 'O': 'E';
}
}
cout << s << endl;
return 0;
}
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