結果

問題 No.886 Direct
ユーザー parukiparuki
提出日時 2019-09-17 18:41:52
言語 C++14
(gcc 13.2.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 3,387 bytes
コンパイル時間 1,530 ms
コンパイル使用メモリ 170,872 KB
実行使用メモリ 26,588 KB
最終ジャッジ日時 2023-09-21 19:49:40
合計ジャッジ時間 13,295 ms
ジャッジサーバーID
(参考情報)
judge13 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,376 KB
testcase_01 AC 1 ms
4,380 KB
testcase_02 AC 1 ms
4,376 KB
testcase_03 WA -
testcase_04 AC 2 ms
4,380 KB
testcase_05 AC 2 ms
4,380 KB
testcase_06 AC 2 ms
4,376 KB
testcase_07 AC 1 ms
4,376 KB
testcase_08 AC 2 ms
4,380 KB
testcase_09 AC 2 ms
4,376 KB
testcase_10 AC 2 ms
4,376 KB
testcase_11 WA -
testcase_12 AC 1 ms
4,380 KB
testcase_13 AC 1 ms
4,380 KB
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
testcase_24 WA -
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
testcase_28 WA -
testcase_29 AC 1,201 ms
26,396 KB
testcase_30 AC 1 ms
4,380 KB
testcase_31 WA -
testcase_32 WA -
testcase_33 WA -
testcase_34 WA -
testcase_35 WA -
権限があれば一括ダウンロードができます

ソースコード

diff #

#define _USE_MATH_DEFINES
#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define MT make_tuple
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
#define RT return
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
using vll = vector<ll>;

template<int MOD>
class ModInt {
public:
    ModInt() :value(0) {}
    ModInt(long long val) :value((int)(val<0 ? MOD + val % MOD : val % MOD)) { }

    ModInt& operator+=(ModInt that) {
        value = value + that.value;
        if (value >= MOD)value -= MOD;
        return *this;
    }
    ModInt& operator-=(ModInt that) {
        value -= that.value;
        if (value<0)value += MOD;
        return *this;
    }
    ModInt& operator*=(ModInt that) {
        value = (int)((long long)value * that.value % MOD);
        return *this;
    }
    ModInt &operator/=(ModInt that) {
        return *this *= that.inverse();
    }
    ModInt operator+(ModInt that) const {
        return ModInt(*this) += that;
    }
    ModInt operator-(ModInt that) const {
        return ModInt(*this) -= that;
    }
    ModInt operator*(ModInt that) const {
        return ModInt(*this) *= that;
    }
    ModInt operator/(ModInt that) const {
        return ModInt(*this) /= that;
    }
    ModInt pow(long long k) const {
        ModInt n = *this, res = 1;
        while (k) {
            if (k & 1)res *= n;
            n *= n;
            k >>= 1;
        }
        return res;
    }
    ModInt inverse() const {
        long long a = value, b = MOD, u = 1, v = 0;
        while (b) {
            long long t = a / b;
            a -= t * b;
            swap(a, b);
            u -= t * v;
            swap(u, v);
        }
        return ModInt(u);
    }
    int toi() const { return value; }

private:
    int value;
};
typedef ModInt<1000000007> mint;
ostream& operator<<(ostream& os, const mint& x) {
    os << x.toi();
    return os;
}

vector<int> factorizer(int n) {
    vector<int> res(n + 1, 1);
    for (int i = 2; i <= n; ++i)if (res[i] == 1) {
        for (int j = i; j <= n; j += i) {
            res[j] = i;
        }
    }
    return res;
}

void solve() {
    int H, W;
    cin >> H >> W;

    auto f = factorizer(H);
    vector<int> used(H + 1);

    mint ans = (H - 1ll)*W + (W - 1ll)*H;
    for (int y = 1; y <= H; ++y) {
        vector<int> ps;
        int val = y;
        while (val != 1) {
            if (used[f[val]] != y) {
                used[f[val]] = y;
                ps.push_back(f[val]);
            }
            val /= f[val];
        }

        mint sum, tum;
        int n = sz(ps);
        rep(S, 1 << n) {
            int cnt = 0, base = 1;
            rep(i, n)if (S >> i & 1) {
                cnt++;
                base *= ps[i];
            }
            sum += (cnt & 1 ? -1 : 1) * W / base;
            tum += (cnt & 1 ? -1 : 1)*(W + (ll)W / base * W) / 2;
        }

        ans += (sum*W - tum) * (H - y) * 2;
    }
    cout << ans << endl;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << fixed << setprecision(15);
    solve();
    return 0;
}
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