結果
問題 | No.911 ラッキーソート |
ユーザー |
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提出日時 | 2019-10-20 13:38:41 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 58 ms / 2,000 ms |
コード長 | 4,557 bytes |
コンパイル時間 | 1,612 ms |
コンパイル使用メモリ | 171,384 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-02 17:25:54 |
合計ジャッジ時間 | 6,654 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 46 |
ソースコード
#include <bits/stdc++.h>using namespace std;using lint = long long int;using pint = pair<int, int>;using plint = pair<lint, lint>;struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;#define ALL(x) (x).begin(), (x).end()#define SZ(x) ((lint)(x).size())#define POW2(n) (1LL << (n))#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)#define REP(i, n) FOR(i,0,n)#define IREP(i, n) IFOR(i,0,n)template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }///// This part below is only for debug, not used /////template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; returnos; }template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}";return os; }template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; returnos; }template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;///// END //////*#include <ext/pb_ds/assoc_container.hpp>#include <ext/pb_ds/tree_policy.hpp>#include <ext/pb_ds/tag_and_trait.hpp>using namespace __gnu_pbds; // find_by_order(), order_of_key()template<typename TK> using pbds_set = tree<TK, null_type, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;template<typename TK, typename TV> using pbds_map = tree<TK, TV, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;*/int N;vector<lint> A;constexpr int D = 61;lint solve(lint R){if (R < 0) return 0;vector<int> ON(D), OFF(D);REP(i, N - 1){IREP(d, D){int a = !!(A[i] & POW2(d));int b = !!(A[i + 1] & POW2(d));if (a == b) continue;if (a < b) OFF[d] = 1;if (a > b) ON[d] = 1;break;}}lint n0 = 0, n1 = 1;IREP(d, D){if (ON[d] and OFF[d]) return 0;if (ON[d] or OFF[d]){if (OFF[d] and (R & POW2(d))){n0 += n1;n1 = 0;}if (ON[d] and !(R & POW2(d))){n1 = 0;}continue;}if (R & POW2(d)){n0 = n0 * 2 + n1;}else{n0 *= 2;}}return n0 + n1;}int main(){lint L, R;cin >> N >> L >> R;A.resize(N);cin >> A;cout << solve(R) - solve(L - 1) << endl;}