結果
| 問題 |
No.914 Omiyage
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2019-10-25 21:58:32 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 4,849 bytes |
| コンパイル時間 | 748 ms |
| コンパイル使用メモリ | 95,344 KB |
| 実行使用メモリ | 6,944 KB |
| 最終ジャッジ日時 | 2024-09-24 16:27:52 |
| 合計ジャッジ時間 | 1,453 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 18 |
ソースコード
#define DEBUG 1
#include <algorithm>
#include <cmath>
#include <cstring>
#include <deque>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using vll = vector<ll>;
using vvll = vector<vll>;
using pll = pair<ll, ll>;
using tll = tuple<ll, ll, ll>;
#define all(v) (v).begin(), (v).end()
#define for1(i, n) for (ll i = 0; i < (n); i++)
#define for2(i, m, n) for (ll i = (m); i < (n); i++)
#define for3(i, m, n, d) for (ll i = (m); i < (n); i += (d))
#define rfor2(i, m, n) for (ll i = (m); i > (n); i--)
#define rfor3(i, m, n, d) for (ll i = (m); i > (n); i += (d))
#define INF 1111111111111111111LL
#define MOD 1000000007LL // 10**9 + 7
#define print(...) print_1(__VA_ARGS__)
#define in(...) in_1(__VA_ARGS__)
#if DEBUG
#define dump(...) dump_1(#__VA_ARGS__, __VA_ARGS__)
#else
#define dump(...)
#endif
template <typename Head>
void dump_1(const char* str, Head&& h)
{
cerr << str << ": " << h << '\n';
}
template <typename Head, typename... Tail>
void dump_1(const char* str, Head&& h, Tail&&... t)
{
while (*str != ',') {
cerr << *str++;
}
cerr << ": " << h << ' ';
dump_1(str + 1, t...);
}
template <typename T1, typename T2>
ostream& operator<<(ostream& os, const pair<T1, T2>& v)
{
os << '(' << v.first << ", " << v.second << ')';
return os;
}
template <typename T1, typename T2, typename T3>
ostream& operator<<(ostream& os, const tuple<T1, T2, T3>& v)
{
os << '(' << get<0>(v) << ", " << get<1>(v) << ", " << get<2>(v) << ')';
return os;
}
template <typename T>
ostream& operator<<(ostream& os, const vector<T>& v)
{
for (auto it = v.begin(); it != v.end(); it++) {
if (it != v.begin()) {
os << ' ';
}
os << *it;
}
return os;
}
template <typename T>
ostream& operator<<(ostream& os, const set<T>& v)
{
for (auto it = v.begin(); it != v.end(); it++) {
if (it != v.begin()) {
os << ' ';
}
os << *it;
}
return os;
}
template <typename T>
ostream& operator<<(ostream& os, const multiset<T>& v)
{
for (auto it = v.begin(); it != v.end(); it++) {
if (it != v.begin()) {
os << ' ';
}
os << *it;
}
return os;
}
template <typename T1, typename T2>
ostream& operator<<(ostream& os, const map<T1, T2>& v)
{
os << '{';
for (auto it = v.begin(); it != v.end(); it++) {
if (it != v.begin()) {
os << ", ";
}
os << it->first << ':' << it->second;
}
os << '}';
return os;
}
void Yes(void) { cout << "Yes\n"; }
void No(void) { cout << "No\n"; }
void YES(void) { cout << "YES\n"; }
void NO(void) { cout << "NO\n"; }
template <typename T>
bool chmax(T& a, const T& b)
{
if (a < b) {
a = b;
return true;
}
return false;
}
template <typename T>
bool chmin(T& a, const T& b)
{
if (a > b) {
a = b;
return true;
}
return false;
}
template <typename T>
void vin(vector<T>& v, ll len)
{
for1 (i, len) {
cin >> v[i];
}
}
template <typename Head>
void in_1(Head& h)
{
cin >> h;
}
template <typename Head, typename... Tail>
void in_1(Head& h, Tail&... t)
{
cin >> h;
in_1(t...);
}
template <typename Head>
void print_1(Head&& h)
{
cout << h << '\n';
}
template <typename Head, typename... Tail>
void print_1(Head&& h, Tail&&... t)
{
cout << h << ' ';
print_1(t...);
}
//---------------------------------------------------------
ll A[11][11];
ll dp[51][501];
void solve()
{
ll N, M, K;
in(N, M, K);
for1 (n, N) {
for1 (m, M) {
in(A[n][m]);
}
}
ll sum = 0;
for1 (n, N) {
ll cheap = INF;
for1 (m, M) {
chmin(cheap, A[n][m]);
}
sum += cheap;
}
if (sum > K) {
print(-1);
return;
}
// dp[a][b] a国旅行して、b円残っている
dp[0][K] = 1;
for1 (n, N) {
// for2 (k, 0, K + 1) {
// dp[n + 1][k] = dp[n][k];
//}
for1 (m, M) {
for2 (k, A[n][m], K + 1) {
if (dp[n][k] != 0) {
// dump(n, m, k, A[n][m]);
dp[n + 1][k - A[n][m]] = 1;
}
}
}
/*
for2 (k, 0, K + 1) {
cout << dp[n + 1][k] << " ";
}
cout << endl;
*/
}
for1 (k, K + 1) {
if (dp[N][k] != 0) {
print(k);
return;
}
}
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout << fixed << setprecision(16);
cerr << fixed << setprecision(16);
solve();
}