結果

問題 No.911 ラッキーソート
ユーザー Sumitacchan
提出日時 2019-10-28 21:15:20
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 74 ms / 2,000 ms
コード長 3,519 bytes
コンパイル時間 1,669 ms
コンパイル使用メモリ 174,448 KB
実行使用メモリ 6,528 KB
最終ジャッジ日時 2024-09-14 21:19:00
合計ジャッジ時間 5,071 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 46
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
/*#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<typename T> using gpp_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T, typename L> using gpp_map = tree<T, L, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T> using gpp_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;*/
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin);i<(end);i++)
#define REP(i, n) FOR(i,0,n)
#define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--)
#define IREP(i, n) IFOR(i,0,n)
#define Sort(v) sort(v.begin(), v.end())
#define Reverse(v) reverse(v.begin(), v.end())
#define all(v) v.begin(),v.end()
#define SZ(v) ((int)v.size())
#define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x))
#define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x))
#define Max(a, b) a = max(a, b)
#define Min(a, b) a = min(a, b)
#define bit(n) (1LL<<(n))
#define bit_exist(x, n) ((x >> n) & 1)
#define debug(x) cout << #x << "=" << x << endl;
#define vdebug(v) cout << #v << "=" << endl; REP(i_debug, v.size()){ cout << v[i_debug] << ","; } cout << endl;
#define mdebug(m) cout << #m << "=" << endl; REP(i_debug, m.size()){ REP(j_debug, m[i_debug].size()){ cout << m[i_debug][j_debug] << ","; } cout << 
    endl;}
#define pb push_back
#define f first
#define s second
#define int long long
#define INF 1000000000000000000
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for (auto &x : v) is >> x; return is; }
template<typename T> ostream &operator<<(ostream &os, vector<T> &v){ for(int i = 0; i < v.size(); i++) { cout << v[i]; if(i != v.size() - 1) cout << 
    endl; }; return os; }
template<typename T> void Out(T x) { cout << x << endl; }
template<typename T1, typename T2> void Ans(bool f, T1 y, T2 n) { if(f) Out(y); else Out(n); }
using vec = vector<int>;
using mat = vector<vec>;
using Pii = pair<int, int>;
using PiP = pair<int, Pii>;
using PPi = pair<Pii, int>;
using bools = vector<bool>;
using pairs = vector<Pii>;
//int dx[4] = {1,0,-1,0};
//int dy[4] = {0,1,0,-1};
//char d[4] = {'D','R','U','L'};
const int mod = 1000000007;
//const int mod = 998244353;
//#define Add(x, y) x = (x + (y)) % mod
//#define Mult(x, y) x = (x * (y)) % mod
int calcans(mat c, int R){
    int ans = 0, tmp = 0;
    mat dp(62, vec(2, 0));
    dp[61][0] = 1;
    IREP(k, 61){
        int b0 = (R >> k) & 1;
        for(int b: c[k]){
            dp[k][1] += dp[k + 1][1];
            if(b == b0) dp[k][0] += dp[k + 1][0];
            else if(b < b0) dp[k][1] += dp[k + 1][0];
        }
    }
    return dp[0][1] + dp[0][0];
}
signed main(){
    int N, L, R; cin >> N >> L >> R;
    vec A(N); cin >> A;
    mat c(61);
    vec a(N);
    IREP(k, 61){
        REP(b, 2){
            bool f = true;
            REP(i, N) a[i] = (A[i] >> k) ^ b;
            REP(i, N - 1) if(a[i] > a[i + 1]){
                f = false;
                break;
            }
            if(f) c[k].pb(b);
        }
        if(SZ(c[k]) == 0){
            Out(0);
            return 0;
        }else if(c[k][0] == 1){
            REP(i, N) A[i] ^= bit(k);
        }
    }
    int ans = calcans(c, R);
    if(L > 0) ans -= calcans(c, L - 1);
    Out(ans);
    return 0;
}
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