結果
| 問題 |
No.837 Noelちゃんと星々2
|
| コンテスト | |
| ユーザー |
ate
|
| 提出日時 | 2019-11-21 20:20:58 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,418 bytes |
| コンパイル時間 | 2,710 ms |
| コンパイル使用メモリ | 206,372 KB |
| 最終ジャッジ日時 | 2025-01-08 04:22:36 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 6 WA * 23 |
ソースコード
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<(n);++i)
using ll = long long;
using pll = pair<ll,ll>;
constexpr ll INF = (1LL<<60);
constexpr ll MOD = (1e9+7);
//constexpr ll MOD = (998244353);
template<class T> bool chmax(T &a,const T &b){if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}return 0;}
void dump(){cout<<endl;}
template<class T,class... Ts> void dump(T&& h, Ts&&... t){cout<<h<<", ";dump(forward<Ts>(t)...);}
template<class T> istream &operator>>(istream&is,vector<T>&v){for(auto &elemnt:v)is>>elemnt;return is;}
template<class T,class U> istream &operator>>(istream&is,pair<T,U>&p){is>>p.first>>p.second;return is;}
template<class T>vector<T> make_vector(size_t a){return vector<T>(a);}
template<class T, class... Ts>auto make_vector(size_t a, Ts... ts){return vector<decltype(make_vector<T>(ts...))>(a, make_vector<T>(ts...));}
void solve1();void solve2();
int main(){
solve1();
return 0;
}
void solve1(){
ll n;
cin>>n;
vector<ll> a(n);
cin>>a;
sort(a.begin(),a.end());
ll base1 = a[n/3];
ll base2 = a[n/3*2];
ll ans = 0;
rep(i,n){
ans += min(abs(base1-a[i]),abs(base2-a[i]));
}
base1 = a[n/3+1];
base2 = a[n/3*2+1];
ll tmp = 0;
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3-1];
base2 = a[n/3*2-1];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3+1];
base2 = a[n/3*2-1];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3-1];
base2 = a[n/3*2+1];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3];
base2 = a[n/3*2-1];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3-1];
base2 = a[n/3*2];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3+1];
base2 = a[n/3*2];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
tmp=0;
base1 = a[n/3];
base2 = a[n/3*2+1];
rep(i,n){
tmp += min(abs(base1-a[i]),abs(base2-a[i]));
}
chmin(ans,tmp);
map<ll,ll>cnt;
rep(i,n)cnt[a[i]]++;
if(cnt.size()==1)cout<<1<<endl;
else if(cnt.size()==2)cout<<0<<endl;
else cout<<ans<<endl;
}
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