結果

問題 No.942 プレゼント配り
ユーザー hitonanodehitonanode
提出日時 2019-12-05 12:32:14
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 3,936 bytes
コンパイル時間 1,727 ms
コンパイル使用メモリ 172,656 KB
実行使用メモリ 7,880 KB
最終ジャッジ日時 2024-05-09 23:42:02
合計ジャッジ時間 3,558 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 18 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 1 ms
5,376 KB
testcase_04 AC 19 ms
5,376 KB
testcase_05 AC 18 ms
5,376 KB
testcase_06 AC 5 ms
7,880 KB
testcase_07 AC 2 ms
5,376 KB
testcase_08 AC 15 ms
5,376 KB
testcase_09 AC 17 ms
5,376 KB
testcase_10 AC 2 ms
5,376 KB
testcase_11 AC 2 ms
5,376 KB
testcase_12 AC 2 ms
5,376 KB
testcase_13 AC 2 ms
5,376 KB
testcase_14 AC 16 ms
5,376 KB
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 AC 2 ms
5,376 KB
testcase_19 AC 2 ms
5,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
#define FI first
#define SE second
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))


int main()
{
    lint N, K;
    cin >> N >> K;
    if (N * (N + 1) / 2 % K)
    {
    	puts("No");
    	return 0;
    }
    vector<vector<int>> ret(K);
    int now = 1;
    int rem = N / K;
    if (K == 1)
    {
        puts("Yes");
        FOR(i, 1, N + 1) printf("%d ", i);
        puts("");
        return 0;
    }
    while (rem)
    {
    	if (rem % 2)
    	{
    		if (N % 2 == 0 or rem == 1)
    		{
    			puts("No");
    			return 0;
    		}
    		REP(i, K) ret[i].emplace_back(now++);
    		REP(i, K) ret[(i + K / 2) % K].emplace_back(now++);
    		REP(i, K) ret[(K * 2 - 1 - i * 2) % K].emplace_back(now++);
    		rem -= 3;
    	}
    	else {
    		REP(i, K) ret[i].emplace_back(now++);
    		IREP(i, K) ret[i].emplace_back(now++);
    		rem -= 2;
    	}
	}
    puts("Yes");
    for (auto vec : ret)
    {
    	for (auto x : vec)
    	{
    		printf("%d ", x);
    	}
    	puts("");
    }
}
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