結果
問題 | No.948 Bomb vs Dush |
ユーザー | Laika |
提出日時 | 2019-12-12 02:27:49 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 2,066 bytes |
コンパイル時間 | 1,641 ms |
コンパイル使用メモリ | 165,316 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-06-24 08:16:06 |
合計ジャッジ時間 | 2,786 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 38 |
ソースコード
#include <bits/stdc++.h> using namespace std; #define rep(i, n) for(int i = 0; i < (n); ++i) #define per(i, n) for(int i = (n)-1; i >= 0; --i) #define eee(a) (cerr << (#a) << ": " << (a) << endl); #define ppp(a) (cout << (a) << endl); #define cop(a) for(auto x:(a)){cout << x << endl;} using ll = long long; using pint = pair<int, int>; using pll = pair<ll, ll>; using mint = map<int, int>; int dx[4] = {1, 0, -1, 0}; int dy[4] = {0, 1, 0, -1}; constexpr char sp = ' '; constexpr char cmm = ','; constexpr int MOD = 1e9+7; constexpr int INF = 1e9; constexpr ll LINF = 1e18; constexpr double phi = (1+sqrt(5))/2; constexpr double pi = 3.14159265358979323846264338327950288; ll mod(ll a, ll b){return (a%b+b)%b;} ll gcd(ll a, ll b){return b?gcd(b,a%b):a;} ll lcm(ll a, ll b){return a*b/gcd(a,b);} inline void Yes(){puts("Yes");} inline void No(){puts("No");} inline void Judge(bool b){b?Yes():No();} inline void YES(){puts("YES");} inline void NO(){puts("NO");} inline void JUDGE(bool b){b?YES():NO();} inline ll powmod(ll b, ll e){ll r=1;while(e>0){if(e&1)r=(r%MOD)*(b%MOD)%MOD;b=(b%MOD)*(b%MOD)%MOD;e>>=1;}return r;} inline double distance(ll x1, ll y1, ll x2, ll y2){return sqrt((x1-x2)*(x1-x2) + (y1-y2)*(y1-y2));} inline double d2r(double d){return d*pi/180;} inline double r2d(double r){return r*180/pi;} template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T1, typename T2> ostream& operator<<(ostream& s, const pair<T1, T2>& p) {return s << "(" << p.first << ", " << p.second << ")";} template<typename T> ostream& operator<<(ostream& s, const vector<T>& v) { s<<'[';for(size_t i=0;i<v.size();++i){s << v[i];if(i < v.size()-1) s << ", ";}s<<']';return s; } int main(){ double r, R; scanf("%lf%lf", &r, &R); double theta = 2*pi-acos(1-r*r/R/R*2); printf("%.10lf\n", theta); double area = ((R+r)*(R+r)-(R-r)*(R-r))*(theta/2) + r*r*pi; printf("%.10lf\n", area); return 0; }