結果
問題 | No.966 引き算をして門松列(その1) |
ユーザー | hitonanode |
提出日時 | 2020-01-13 20:33:33 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 17 ms / 2,000 ms |
コード長 | 4,275 bytes |
コンパイル時間 | 1,479 ms |
コンパイル使用メモリ | 167,776 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-12-21 16:20:22 |
合計ジャッジ時間 | 1,977 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,820 KB |
testcase_01 | AC | 1 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 2 ms
6,820 KB |
testcase_04 | AC | 12 ms
6,816 KB |
testcase_05 | AC | 14 ms
6,820 KB |
testcase_06 | AC | 17 ms
6,820 KB |
ソースコード
#include <bits/stdc++.h>using namespace std;using lint = long long int;using pint = pair<int, int>;using plint = pair<lint, lint>;struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;#define ALL(x) (x).begin(), (x).end()#define SZ(x) ((lint)(x).size())#define POW2(n) (1LL << (n))#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)#define REP(i, n) FOR(i,0,n)#define IREP(i, n) IFOR(i,0,n)template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...);}template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second+ r.second); }template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second- r.second); }template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }///// This part below is only for debug, not used /////template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}";return os; }template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; returnos; }template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;///// END //////*#include <ext/pb_ds/assoc_container.hpp>#include <ext/pb_ds/tree_policy.hpp>#include <ext/pb_ds/tag_and_trait.hpp>using namespace __gnu_pbds; // find_by_order(), order_of_key()template<typename TK> using pbds_set = tree<TK, null_type, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;template<typename TK, typename TV> using pbds_map = tree<TK, TV, less<TK>, rb_tree_tag, tree_order_statistics_node_update>;*/constexpr lint INF = 1e12;lint solve1(lint A, lint B, lint C){// a < b > c にするlint asub = max(A - B + 1, 0LL);lint csub = max(C - B + 1, 0LL);A -= asub;C -= csub;lint cost = asub + csub;if (A == C) cost++, C--;if (A <= 0 or C <= 0) return INF;return cost;}lint solve2(lint A, lint B, lint C){// a > b < c にするif (A == 1 or C == 1) return INF;if (A == 2 and C == 2) return INF;if (A == C) return max(B - (A - 2), 0LL) + 1;else return max(B - min(A, C) + 1, 0LL);}int main(){int T;cin >> T;while (T--) {lint A, B, C;cin >> A >> B >> C;lint ret = min(solve1(A, B, C), solve2(A, B, C));cout << (ret >= INF / 2 ? -1 : ret) << endl;}}