結果
問題 | No.1086 桁和の桁和2 |
ユーザー | QCFium |
提出日時 | 2020-01-21 20:07:20 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,931 bytes |
コンパイル時間 | 1,602 ms |
コンパイル使用メモリ | 170,040 KB |
実行使用メモリ | 5,632 KB |
最終ジャッジ日時 | 2024-07-02 23:36:40 |
合計ジャッジ時間 | 6,982 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 146 ms
5,504 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 91 ms
5,376 KB |
testcase_11 | AC | 26 ms
5,376 KB |
testcase_12 | AC | 6 ms
5,376 KB |
testcase_13 | AC | 115 ms
5,376 KB |
testcase_14 | AC | 73 ms
5,376 KB |
testcase_15 | AC | 28 ms
5,376 KB |
testcase_16 | AC | 157 ms
5,376 KB |
testcase_17 | AC | 15 ms
5,376 KB |
testcase_18 | WA | - |
testcase_19 | AC | 178 ms
5,376 KB |
testcase_20 | AC | 24 ms
5,376 KB |
testcase_21 | AC | 153 ms
5,376 KB |
testcase_22 | AC | 217 ms
5,632 KB |
testcase_23 | AC | 133 ms
5,376 KB |
testcase_24 | AC | 93 ms
5,376 KB |
testcase_25 | AC | 183 ms
5,376 KB |
testcase_26 | AC | 149 ms
5,376 KB |
testcase_27 | AC | 109 ms
5,376 KB |
testcase_28 | AC | 90 ms
5,376 KB |
testcase_29 | WA | - |
testcase_30 | AC | 224 ms
5,504 KB |
testcase_31 | AC | 223 ms
5,504 KB |
testcase_32 | WA | - |
testcase_33 | AC | 223 ms
5,504 KB |
testcase_34 | AC | 224 ms
5,504 KB |
testcase_35 | AC | 145 ms
5,504 KB |
ソースコード
#include <bits/stdc++.h> int ri() { int n; scanf("%d", &n); return n; } #define MOD 1000000007 template<int mod> struct ModInt{ int x; ModInt():x(0){} ModInt(long long y):x(y>=0?y%mod:(mod-(-y)%mod)%mod){} ModInt &operator+=(const ModInt &p){ if((x+=p.x)>=mod)x-=mod; return *this; } ModInt &operator-=(const ModInt &p){ if((x+=mod-p.x)>=mod)x-=mod; return *this; } ModInt &operator*=(const ModInt &p){ x=(int)(1LL*x*p.x%mod); return *this; } ModInt &operator/=(const ModInt &p){ *this*=p.inverse(); return *this; } ModInt &operator^=(long long p){ ModInt res = 1; for (; p; p >>= 1) { if (p & 1) res *= *this; *this *= *this; } return *this = res; } ModInt operator-()const{return ModInt(-x);} ModInt operator+(const ModInt &p)const{return ModInt(*this)+=p;} ModInt operator-(const ModInt &p)const{return ModInt(*this)-=p;} ModInt operator*(const ModInt &p)const{return ModInt(*this)*=p;} ModInt operator/(const ModInt &p)const{return ModInt(*this)/=p;} ModInt operator^(long long p)const{return ModInt(*this)^=p;} bool operator==(const ModInt &p)const{return x==p.x;} bool operator!=(const ModInt &p)const{return x!=p.x;} explicit operator int() const { return x; } // added by QCFium ModInt operator=(const int p) {x = p; return ModInt(*this);} // added by QCFium ModInt inverse()const{ int a=x,b=mod,u=1,v=0,t; while(b>0){ t=a/b; a-=t*b; std::swap(a,b); u-=t*v; std::swap(u,v); } return ModInt(u); } friend std::ostream &operator<<(std::ostream &os,const ModInt<mod> &p){ return os<<p.x; } friend std::istream &operator>>(std::istream &is,ModInt<mod> &a){ long long x; is>>x; a=ModInt<mod>(x); return (is); } }; typedef ModInt<MOD> mint; struct MComb { std::vector<mint> fact; std::vector<mint> inversed; MComb(int n) { // O(n+log(mod)) fact = std::vector<mint>(n+1,1); for (int i = 1; i <= n; i++) fact[i] = fact[i-1]*mint(i); inversed = std::vector<mint>(n+1); inversed[n] = fact[n] ^ (MOD-2); for (int i = n - 1; i >= 0; i--) inversed[i]=inversed[i+1]*mint(i+1); } mint ncr(int n, int r) { return (fact[n] * inversed[r] * inversed[n-r]); } mint npr(int n, int r) { return (fact[n] * inversed[n-r]); } mint nhr(int n, int r) { assert(n+r-1 < (int)fact.size()); return ncr(n+r-1, r); } }; int main() { int n = ri(); int64_t l[n], r[n]; int d[n]; for (auto &i : l) std::cin >> i; for (auto &i : r) std::cin >> i; for (auto &i : d) i = ri(); int i = 0; for (; i < n; i++) if (d[i]) break; if (i == n) puts("1"), exit(0); for (int j = i; j < n; j++) if (!d[j]) puts("0"), exit(0); for (int j = n - 1; j > i; j--) d[j] = (d[j] + 9 - d[j - 1]) % 9; d[i] %= 9; // WA... I guess mint res = 1; for (int j = i; j < n; j++) res *= (((mint(10) ^ r[j]) - (mint(10) ^ l[j])) / 9 + !d[j]); if (!*std::max_element(d + i, d + n)) res -= 1; std::cout << res << std::endl; return 0; }