結果
問題 | No.641 Team Contest Estimation |
ユーザー | firiexp |
提出日時 | 2020-03-26 11:16:09 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
CE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,590 bytes |
コンパイル時間 | 688 ms |
コンパイル使用メモリ | 86,084 KB |
最終ジャッジ日時 | 2024-11-14 22:13:01 |
合計ジャッジ時間 | 1,540 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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コンパイルエラー時のメッセージ・ソースコードは、提出者また管理者しか表示できないようにしております。(リジャッジ後のコンパイルエラーは公開されます)
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
コンパイルメッセージ
main.cpp:18:39: error: '::numeric_limits' has not been declared 18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ^~~~~~~~~~~~~~ main.cpp:18:55: error: expected primary-expression before '>' token 18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ^ main.cpp:18:61: error: no matching function for call to 'max()' 18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ~~~~~^~ In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/string:50, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/locale_classes.h:40, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/ios_base.h:41, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ios:42, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:38, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/iostream:39, from main.cpp:1: /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note: candidate: 'template<class _Tp> constexpr const _Tp& std::max(const _Tp&, const _Tp&)' 254 | max(const _Tp& __a, const _Tp& __b) | ^~~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:254:5: note: template argument deduction/substitution failed: main.cpp:18:61: note: candidate expects 2 arguments, 0 provided 18 | template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; | ~~~~~^~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/bits/stl_algobase.h:300:5: note: candidate: 'templat
ソースコード
#include <iostream> #include <algorithm> #include <iomanip> #include <map> #include <set> #include <queue> #include <stack> #include <numeric> #include <bitset> #include <cmath> static const int MOD = 1000000009; using ll = long long; using u32 = unsigned; using u64 = unsigned long long; using namespace std; template<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208; template<u32 M = 1000000007> struct modint{ u32 val; modint(): val(0){} template<typename T> modint(T t){t %= (T)M; if(t < 0) t += (T)M; val = t;} modint pow(ll k) const { modint res(1), x(val); while(k){ if(k&1) res *= x; x *= x; k >>= 1; } return res; } template<typename T> modint& operator=(T t){t %= (T)M; if(t < 0) t += (T)M; val = t; return *this;} modint inv() const {return pow(M-2);} modint& operator+=(modint a){val += a.val; if(val >= M) val -= M; return *this;} modint& operator-=(modint a){if(val < a.val) val += M-a.val; else val -= a.val; return *this;} modint& operator*=(modint a){val = (u64)val*a.val%M; return *this;} modint& operator/=(modint a){return (*this) *= a.inv();} modint operator+(modint a) const {return modint(val) +=a;} modint operator-(modint a) const {return modint(val) -=a;} modint operator*(modint a) const {return modint(val) *=a;} modint operator/(modint a) const {return modint(val) /=a;} modint operator-(){return modint(M-val);} bool operator==(const modint a) const {return val == a.val;} bool operator!=(const modint a) const {return val != a.val;} bool operator<(const modint a) const {return val < a.val;} }; using mint = modint<MOD>; int main() { int n, k; cin >> n >> k; vector<int> cnt1(k); for (int i = 0; i < n; ++i) { ll x; scanf("%lld", &x); for (int j = 0; j < k; ++j) { if(x & (1LL << j)){ cnt1[j]++; } } } mint Ex, Exx, tmp = 1; mint A = mint(2).pow(k)-mint(1); Ex = mint(n)*A*mint(500000005); Exx = A*A; for (int i = 0; i < k; ++i) { Exx -= tmp*tmp; tmp += tmp; } Exx *= mint(n)*mint(n)*mint(750000007); tmp = 1; mint tmp2; for (int i = 0; i < k; ++i) { tmp2 += tmp*tmp*(mint(cnt1[i]).pow(2)+mint(n-cnt1[i]).pow(2)); tmp += tmp; } Exx += tmp2*mint(500000005); mint ans1 = Ex*(mint(2).pow(k)); mint ans2 = (Exx-Ex*Ex)*(mint(4).pow(k)); cout << ans1.val << "\n"; cout << ans2.val << "\n"; return 0; }