#449367 (C++14) No.1220 yukipoker

• 問題: No.1220 yukipoker
• ユーザー: Jiro_tech15
• 提出日時: 2020-03-26 17:55:25
• 言語: C++14 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 278 ms / 2,000 ms
• コード長: 1,965 bytes
• コンパイル時間: 886 ms
• コンパイル使用メモリ: 100,572 KB
• 実行使用メモリ: 5,584 KB
• 最終ジャッジ日時: 2024-11-22 04:45:06
• 合計ジャッジ時間: 4,113 ms
• ジャッジサーバーID （参考情報）: judge5 / judge3

ファイルパターン	結果
sample	AC * 1
other	AC * 25

ソースコード

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#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
#include <string>
#include <math.h>
#include <iomanip>
#include <limits>
#include <list>
#include <queue>
#include <tuple>
#include <map>
#include <stack>
#include <set>
#include <bitset>
#include <functional>
using namespace std;
#define fast_io ios_base::sync_with_stdio (false) ; cin.tie(0) ; cout.tie(0) ;
#define ll long long int
#define rep(i,n) for(int i=0; i<(int)(n); i++)
#define reps(i,n) for(int i=1; i<=(int)(n); i++)
#define REP(i,n) for(int i=n-1; i>=0; i--)
#define REPS(i,n) for(int i=n; i>0; i--)
#define MOD (long long int)(1e9+7)
#define INF (int)(1123456789)
#define LINF (long long int)(112345678901234567)
#define chmax(a, b) a = (((a)<(b)) ? (b) : (a))
#define chmin(a, b) a = (((a)>(b)) ? (b) : (a))
#define all(v) v.begin(), v.end()
typedef pair<int, int> Pii;
typedef pair<ll, ll> Pll;
//x * 10^y
//xは7桁
struct Num{
  ll x,y;
  Num(ll _x, ll _y){
    x = _x;
    y = _y;
  }
  Num operator*(Num obj){
    ll X = x * obj.x;
    ll Y = y + obj.y;
    while(X >= 1e7){
      X /= 10;
      Y++;
    }
    return {X, Y};
  }
};
Num npow(Num a, ll b){
  if(b==0) return Num(1, 0);
  else if(b%2==0){Num memo = npow(a, b/2); return memo*memo;}
  else return npow(a,b-1) * a;
}
vector<Num> kaijo_memo;
Num kaijo(ll n){
  if(kaijo_memo.size() > n) return kaijo_memo[n];
  if(kaijo_memo.size() == 0) kaijo_memo.push_back({1, 0});
  while(kaijo_memo.size() <= n) kaijo_memo.push_back(kaijo_memo[kaijo_memo.size()-1] * Num(kaijo_memo.size(), 0));
  return kaijo_memo[n];
}
int main(void){
  //Flush
  //M * N! / (N-K)!
  //Straight
  //(N-K+1) * K! * M^K
  //S/F
  //K! * (N-K+1)! * M^(k-1) / N!
  ll q;cin>>q;
  rep(i,q){
    ll n,m,k;cin>>n>>m>>k;
    Num S = kaijo(k) * kaijo(n-k+1) * npow({m,0}, k-1);
    Num F = kaijo(n);
    if(S.y < F.y || (S.y == F.y && S.x < F.x)){
      cout<<"Straight"<<endl;
    }else{
      cout<<"Flush"<<endl;
    }
  }
}
 
 
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