結果

問題 No.891 隣接3項間の漸化式
ユーザー hamrayhamray
提出日時 2020-03-30 23:46:47
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 5,162 bytes
コンパイル時間 1,459 ms
コンパイル使用メモリ 167,676 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-23 07:13:08
合計ジャッジ時間 2,568 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 39
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
//typedef
//-------------------------#include <bits/stdc++.h>
const double pi = 3.141592653589793238462643383279;
using namespace std;
//conversion
//------------------------------------------
inline int toInt(string s)
{
int v;
istringstream sin(s);
sin >> v;
return v;
}
template <class T>
inline string toString(T x)
{
ostringstream sout;
sout << x;
return sout.str();
}
inline int readInt()
{
int x;
scanf("%d", &x);
return x;
}
//typedef
//------------------------------------------
typedef vector<int> VI;
typedef vector<VI> VVI;
typedef vector<string> VS;
typedef pair<int, int> PII;
typedef pair<long long, long long> PLL;
typedef pair<int, PII> TIII;
typedef long long LL;
typedef unsigned long long ULL;
typedef vector<LL> VLL;
typedef vector<VLL> VVLL;
//container util
//------------------------------------------
#define ALL(a) (a).begin(), (a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define PB push_back
#define MP make_pair
#define SZ(a) int((a).size())
#define SQ(a) ((a) * (a))
#define EACH(i, c) for (typeof((c).begin()) i = (c).begin(); i != (c).end(); ++i)
#define EXIST(s, e) ((s).find(e) != (s).end())
#define SORT(c) sort((c).begin(), (c).end())
//repetition
//------------------------------------------
#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)
#define REP(i, n) FOR(i, 0, n)
#define MOD 1000000007
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define trav(a, x) for (auto &a : x)
#define all(x) x.begin(), x.end()
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
const double EPS = 1E-8;
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
class UnionFind
{
public:
vector<int> par;
vector<int> siz;
UnionFind(int sz_) : par(sz_), siz(sz_, 1)
{
for (ll i = 0; i < sz_; ++i)
par[i] = i;
}
void init(int sz_)
{
par.resize(sz_);
siz.assign(sz_, 1LL);
for (ll i = 0; i < sz_; ++i)
par[i] = i;
}
int root(int x)
{
while (par[x] != x)
{
x = par[x] = par[par[x]];
}
return x;
}
bool merge(int x, int y)
{
x = root(x);
y = root(y);
if (x == y)
return false;
if (siz[x] < siz[y])
swap(x, y);
siz[x] += siz[y];
par[y] = x;
return true;
}
bool issame(int x, int y)
{
return root(x) == root(y);
}
int size(int x)
{
return siz[root(x)];
}
};
ll modPow(ll x, ll n, ll mod = MOD)
{
ll res = 1;
while (n)
{
if (n & 1)
res = (res * x) % mod;
res %= mod;
x = x * x % mod;
n >>= 1;
}
return res;
}
#define SIEVE_SIZE 5000000 + 10
bool sieve[SIEVE_SIZE];
void makeSieve()
{
for (int i = 0; i < SIEVE_SIZE; ++i)
sieve[i] = true;
sieve[0] = sieve[1] = false;
for (int i = 2; i * i < SIEVE_SIZE; ++i)
if (sieve[i])
for (int j = 2; i * j < SIEVE_SIZE; ++j)
sieve[i * j] = false;
}
bool isprime(ll n)
{
if (n == 0 || n == 1)
return false;
for (ll i = 2; i * i <= n; ++i)
if (n % i == 0)
return false;
return true;
}
const int MAX = 2000010;
long long fac[MAX], finv[MAX], inv[MAX];
//
void COMinit()
{
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for (int i = 2; i < MAX; i++)
{
fac[i] = fac[i - 1] * i % MOD;
inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
finv[i] = finv[i - 1] * inv[i] % MOD;
}
}
//
long long COM(int n, int k)
{
if (n < k)
return 0;
if (n < 0 || k < 0)
return 0;
return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}
long long extGCD(long long a, long long b, long long &x, long long &y)
{
if (b == 0)
{
x = 1;
y = 0;
return a;
}
long long d = extGCD(b, a % b, y, x);
y -= a / b * x;
return d;
}
// mod (a = -11 OK)
inline long long mod(long long a, long long m)
{
return (a % m + m) % m;
}
// ( a m )
long long modinv(long long a, long long m)
{
long long x, y;
extGCD(a, m, x, y);
return mod(x, m); // x % m x
}
ll GCD(ll a, ll b)
{
if (b == 0)
return a;
return GCD(b, a % b);
}
typedef vector<ll> vec;
typedef vector<vec> mat;
mat mul(mat &A, mat &B)
{
mat C(A.size(), vec((int)B[0].size()));
for (int i = 0; i < A.size(); ++i)
{
for (int k = 0; k < B.size(); ++k)
{
for (int j = 0; j < B[0].size(); ++j)
{
C[i][j] = (C[i][j] + A[i][k] * B[k][j] % MOD) % MOD;
}
}
}
return C;
}
mat matPow(mat A, ll n)
{
mat B(A.size(), vec((int)A.size()));
for (int i = 0; i < A.size(); ++i)
{
B[i][i] = 1;
}
while (n > 0)
{
if (n & 1)
B = mul(B, A);
A = mul(A, A);
n >>= 1;
}
return B;
}
int main()
{
cin.tie(0);
ios::sync_with_stdio(false);
cout << fixed << setprecision(20);
ll a, b, n;
cin >> a >> b >> n;
mat v(2, vec(2));
v[0][0] = a, v[0][1] = b;
v[1][0] = 1, v[1][1] = 0;
auto ans = matPow(v, n);
cout << ans[1][0] << endl;
return 0;
}
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