結果
問題 | No.1017 Reiwa Sequence |
ユーザー | snuke |
提出日時 | 2020-04-03 22:08:38 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,889 bytes |
コンパイル時間 | 2,215 ms |
コンパイル使用メモリ | 205,848 KB |
実行使用メモリ | 7,284 KB |
最終ジャッジ日時 | 2024-07-03 03:11:27 |
合計ジャッジ時間 | 33,873 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | AC | 5 ms
5,848 KB |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | AC | 9 ms
5,724 KB |
testcase_15 | AC | 9 ms
5,720 KB |
testcase_16 | AC | 8 ms
5,724 KB |
testcase_17 | AC | 12 ms
5,728 KB |
testcase_18 | AC | 8 ms
5,636 KB |
testcase_19 | AC | 18 ms
5,720 KB |
testcase_20 | AC | 18 ms
5,724 KB |
testcase_21 | AC | 19 ms
5,720 KB |
testcase_22 | AC | 19 ms
5,600 KB |
testcase_23 | AC | 17 ms
5,596 KB |
testcase_24 | AC | 14 ms
5,724 KB |
testcase_25 | AC | 17 ms
5,596 KB |
testcase_26 | AC | 15 ms
5,848 KB |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | WA | - |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | WA | - |
testcase_40 | WA | - |
testcase_41 | WA | - |
testcase_42 | WA | - |
testcase_43 | WA | - |
testcase_44 | WA | - |
testcase_45 | WA | - |
testcase_46 | WA | - |
testcase_47 | WA | - |
testcase_48 | WA | - |
testcase_49 | WA | - |
testcase_50 | WA | - |
testcase_51 | AC | 4 ms
5,632 KB |
testcase_52 | WA | - |
testcase_53 | WA | - |
ソースコード
#include <bits/stdc++.h> #define fi first #define se second #define rep(i,n) for(int i = 0; i < (n); ++i) #define rrep(i,n) for(int i = 1; i <= (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) #define rng(a) a.begin(),a.end() #define rrng(a) a.rbegin(),a.rend() #define maxs(x,y) (x = max(x,y)) #define mins(x,y) (x = min(x,y)) #define limit(x,l,r) max(l,min(x,r)) #define lims(x,l,r) (x = max(l,min(x,r))) #define isin(x,l,r) ((l) <= (x) && (x) < (r)) #define pb push_back #define eb emplace_back #define sz(x) (int)(x).size() #define pcnt __builtin_popcountll #define uni(x) x.erase(unique(rng(x)),x.end()) #define snuke srand((unsigned)clock()+(unsigned)time(NULL)); #define show(x) cout<<#x<<" = "<<x<<endl; #define PQ(T) priority_queue<T,v(T),greater<T> > #define bn(x) ((1<<x)-1) #define dup(x,y) (((x)+(y)-1)/(y)) #define newline puts("") #define v(T) vector<T> #define vv(T) v(v(T)) using namespace std; typedef long long int ll; typedef unsigned uint; typedef unsigned long long ull; typedef pair<int,int> P; typedef tuple<int,int,int> T; typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<ll> vl; typedef vector<P> vp; typedef vector<T> vt; inline int getInt() { int x; scanf("%d",&x); return x;} template<typename T>inline istream& operator>>(istream&i,v(T)&v) {rep(j,sz(v))i>>v[j];return i;} template<typename T>string join(const v(T)&v) {stringstream s;rep(i,sz(v))s<<' '<<v[i];return s.str().substr(1);} template<typename T>inline ostream& operator<<(ostream&o,const v(T)&v) {if(sz(v))o<<join(v);return o;} template<typename T1,typename T2>inline istream& operator>>(istream&i,pair<T1,T2>&v) {return i>>v.fi>>v.se;} template<typename T1,typename T2>inline ostream& operator<<(ostream&o,const pair<T1,T2>&v) {return o<<v.fi<<","<<v.se;} template<typename T>inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #define dame { puts("-1"); return 0;} #define yn {puts("Yes");}else{puts("No");} const int MX = 300005; const int M = 150002; const int X = 550; int main() { int n; scanf("%d",&n); vi a(n); cin>>a; int m = min(X,n); vi dp(MX,INF); dp[M] = 0; vi ans(n); rep(i,m) { int na = a[i]; if (dp[M+na] != INF) { ans[i] = -na; while (na) { int ni = dp[M+na]; int sg = 1; if (ni < 0) ni = -ni, sg = -1; --ni; ans[ni] = a[ni]*sg; na -= a[ni]*sg; } cout<<ans<<endl; return 0; } vi p = dp; rep(j,MX) if (p[j] != INF) { { int nj = j+na; if (nj < MX && dp[nj] == INF) dp[nj] = i+1; } { int nj = j-na; if (nj >= 0 && dp[nj] == INF) dp[nj] = -(i+1); } } } cout<<"No"<<endl; return 0; }