結果
問題 | No.10 +か×か |
ユーザー | fumiphys |
提出日時 | 2020-04-05 00:34:19 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 11 ms / 5,000 ms |
コード長 | 3,500 bytes |
コンパイル時間 | 1,628 ms |
コンパイル使用メモリ | 170,504 KB |
実行使用メモリ | 8,132 KB |
最終ジャッジ日時 | 2024-12-14 15:44:02 |
合計ジャッジ時間 | 2,272 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,820 KB |
testcase_01 | AC | 2 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,816 KB |
testcase_03 | AC | 11 ms
8,128 KB |
testcase_04 | AC | 8 ms
7,468 KB |
testcase_05 | AC | 3 ms
6,816 KB |
testcase_06 | AC | 10 ms
8,132 KB |
testcase_07 | AC | 8 ms
7,452 KB |
testcase_08 | AC | 4 ms
6,820 KB |
testcase_09 | AC | 5 ms
6,820 KB |
testcase_10 | AC | 2 ms
6,820 KB |
testcase_11 | AC | 2 ms
6,820 KB |
ソースコード
// includes #include <bits/stdc++.h> using namespace std; // macros #define pb emplace_back #define mk make_pair #define FOR(i, a, b) for(int i=(a);i<(b);++i) #define rep(i, n) FOR(i, 0, n) #define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--) #define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr) #define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr) #define whole(x) (x).begin(),(x).end() #define sz(x) ((int)(x).size()) #define bit(n) (1LL<<(n)) // functions template <typename T> void unique(T& c){c.erase(std::unique(c.begin(), c.end()), c.end());} template <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;} template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;} template <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;} template <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << " ";} return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << "(" << p.first << ", " << p.second << ")"; return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << "(" << itr->first << ", " << itr->second << ")"; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} template <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << "(" << itr->first << ", " << itr->second << ")"; auto titr = itr; if(++titr != mp.end())os << " "; } return os;} // types using ll = long long int; using P = pair<int, int>; // constants const int inf = 1e9; const ll linf = 1LL << 50; const double EPS = 1e-10; const int mod = 1000000007; const int dx[4] = {-1, 0, 1, 0}; const int dy[4] = {0, -1, 0, 1}; // io struct fast_io{ fast_io(){ios_base::sync_with_stdio(false); cin.tie(nullptr); cout << fixed << setprecision(20);} } fast_io_; bool dp[51][100010]; int main(int argc, char const* argv[]) { int n, total; cin >> n >> total; vector<int> a(n); cin >> a; dp[n-1][total] = true; rrep(i, n - 1){ rep(j, total + 1){ if(j+a[i+1]<=total)dp[i][j] |= dp[i+1][j+a[i+1]]; if(j*a[i+1]<=total)dp[i][j] |= dp[i+1][j*a[i+1]]; } } string res = ""; int curr = a[0]; for(int i = 1; i < n; i++){ if(dp[i][curr+a[i]]){ res += '+'; curr += a[i]; }else{ res += '*'; curr *= a[i]; } } cout << res << endl; return 0; }