結果

問題 No.1037 exhausted
ユーザー hirono999hirono999
提出日時 2020-04-24 23:50:04
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 33 ms / 2,000 ms
コード長 5,624 bytes
コンパイル時間 2,506 ms
コンパイル使用メモリ 215,824 KB
実行使用メモリ 34,688 KB
最終ジャッジ日時 2024-04-23 04:23:28
合計ジャッジ時間 3,248 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,812 KB
testcase_01 AC 2 ms
6,944 KB
testcase_02 AC 2 ms
6,940 KB
testcase_03 AC 2 ms
6,940 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 2 ms
6,944 KB
testcase_06 AC 1 ms
6,940 KB
testcase_07 AC 2 ms
6,944 KB
testcase_08 AC 2 ms
6,940 KB
testcase_09 AC 1 ms
6,940 KB
testcase_10 AC 1 ms
6,940 KB
testcase_11 AC 1 ms
6,940 KB
testcase_12 AC 33 ms
34,560 KB
testcase_13 AC 32 ms
34,560 KB
testcase_14 AC 31 ms
34,304 KB
testcase_15 AC 31 ms
34,560 KB
testcase_16 AC 32 ms
34,432 KB
testcase_17 AC 32 ms
34,560 KB
testcase_18 AC 31 ms
34,560 KB
testcase_19 AC 31 ms
34,432 KB
testcase_20 AC 30 ms
34,560 KB
testcase_21 AC 29 ms
34,432 KB
testcase_22 AC 27 ms
34,688 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
const long long INF = 1LL << 60;
const long long MOD = 1000000007;
const double PI = acos(-1.0);
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep1(i, n) for (ll i = 1; i <= (n); ++i)
#define rrep(i, n) for (ll i = (n - 1); i >= 0; --i)
#define perm(c) sort(ALL(c));for(bool c##p=1;c##p;c##p=next_permutation(ALL(c)))
#define ALL(obj) (obj).begin(), (obj).end()
#define RALL(obj) (obj).rbegin(), (obj).rend()
#define pb push_back
#define to_s to_string
#define len(v) (ll)v.size()
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define print(x) cout << (x) << '\n'
#define drop(x) cout << (x) << '\n', exit(0)
#define debug(x) cout << #x << ": " << (x) << '\n'
using namespace std;
using ll = long long;
typedef pair<ll, ll> P;
typedef vector<ll> vec;
typedef vector<vector<ll>> vec2;
typedef vector<vector<vector<ll>>> vec3;
template<class S, class T> inline bool chmax(S &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class S, class T> inline bool chmin(S &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
inline ll msb(ll v) { return 1 << (31 - __builtin_clzll(v)); }
inline ll devc(ll x, ll y) { return (x + y - 1) / y; }
inline ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
inline ll lcm(ll a, ll b) { return a * (b / gcd(a, b)); }

struct IoSetup {
    IoSetup() {
        cin.tie(nullptr);
        ios::sync_with_stdio(false);
        cout << fixed << setprecision(10);
        cerr << fixed << setprecision(10);
    }
} iosetup;

template< typename T1, typename T2 >
ostream &operator << (ostream &os, const pair< T1, T2 > &p) {
    os << p.first << " " << p.second;
    return os;
}

template< typename T1, typename T2 >
istream &operator >> (istream &is, pair< T1, T2 > &p) {
    is >> p.first >> p.second;
    return is;
}

template< typename T1, typename T2, typename T3 >
ostream &operator << (ostream &os, const tuple< T1, T2, T3 > &t) {
    os << get<0>(t) << " " << get<1>(t) << " " << get<2>(t);
    return os;
}

template< typename T1, typename T2, typename T3 >
istream &operator >> (istream &is, tuple< T1, T2, T3 > &t) {
    is >> get<0>(t) >> get<1>(t) >> get<2>(t);
    return is;
}

template< typename T >
ostream &operator << (ostream &os, const vector< T > &v){
    for (int i = 0; i < (int)v.size(); ++i) {
        os << v[i] << (i + 1 != v.size() ? " " : "");
    }
    return os;
}

template< typename T >
istream &operator >>  (istream &is, vector< T > &v){
    for(T &in : v) is >> in;
    return is;
}

/*---------------------------------    Tools    ------------------------------------------*/
template< typename T >
vector<T> cumsum(const vector<T> &X){
    vector<T> res(X.size() + 1, 0);
    for(int i = 0; i < X.size(); ++i) res[i + 1] += res[i] + X[i];
    return res;
}

template< typename S, typename T, typename F>
pair<T, T> bisearch(S left, T right, F f) {
    while(abs(right - left) > 1){
        T mid = (right + left) / 2;
        if(f(mid)) right = mid;
        else left = mid;
    }
    return {left, right};
}

template< typename S, typename T, typename F>
double trisearch(S left, T right, F f, int maxLoop = 90){
    double low = left, high = right;
    while(maxLoop--){
        double mid_left = high / 3 + low * 2 / 3;
        double mid_right = high * 2 / 3 + low / 3;
        if(f(mid_left) >= f(mid_right)) low = mid_left;
        else high = mid_right;
    }
    return (low + high) * 0.5;
}

/*---------------------------------    Graph    ------------------------------------------*/

struct Edge {
    ll from, to, weight;
    Edge() : from(0), to(0), weight(0) {}
    Edge(ll f, ll t, ll w) : from(f), to(t), weight(w) {}
};
using Edges = vector<Edge>;
using Graph = vector<Edges>;

void add_edge(Graph &g, ll a, ll b, ll w = 1){
    g[a].emplace_back(a, b, w);
    g[b].emplace_back(b, a, w);
}

void add_arrow(Graph &g, ll a, ll b, ll w = 1){
    g[a].emplace_back(a, b, w);
}

template< typename T >
vector<T> dijkstra(Graph &g, T s, bool restore = false){
    vector<T> dist(g.size(), INF);
    priority_queue<pair<T, T>, vector<pair<T, T>>, greater<pair<T, T>>> que;
    dist[s] = 0;
    que.emplace(dist[s], s);

    vector<T> prev(g.size(), -1);

    while(!que.empty()){
        T cost, idx;
        tie(cost, idx) = que.top();
        que.pop();
        if(dist[idx] < cost) continue;
        for(auto &e : g[idx]){
            auto next_cost = cost + e.weight;
            if(dist[e.to] <= next_cost) continue;
            dist[e.to] = next_cost;

            if(restore) prev[e.to] = e.from;
            que.emplace(dist[e.to], e.to);
        }
    }
    if(restore) return prev;
    return dist;
}

vector<ll> shortest_path(Graph &g, ll start, ll goal){
    vector<ll> prev = dijkstra(g, start, true);
    vector<ll> path;
    for (int cur = goal; cur != -1; cur = prev[cur]) path.push_back(cur);
    reverse(path.begin(), path.end());
    return path;
}

/*------------------------------- Main Code Here -----------------------------------------*/

int main()
{
    ll N, V, L;
    cin >> N >> V >> L;

    vector<tuple<ll, ll, ll>> X(N);
    cin >> X;

    vec2 f(N + 1, vec(V + 1, INF));
    rep(j, V + 1) f[0][j] = 0;

    ll prev = 0;
    rep1(i, N){
        auto [x, v, w] = X[i - 1];
        ll dist = x - prev;
        prev = x;

        rep(j, V + 1) if(j + dist <= V){
            chmin(f[i][j], f[i - 1][j + dist]);
            chmin(f[i][min(V, j + v)], f[i - 1][j + dist] + w);
        }
    }

    ll ans = INF;
    ll last = get<0>(X.back());

    rep(j, V) if(j >= L - last) chmin(ans, f[N][j]);
    print(ans == INF ? -1 : ans);

    return 0;
}
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