結果
問題 | No.301 サイコロで確率問題 (1) |
ユーザー | FF256grhy |
提出日時 | 2020-05-01 01:39:09 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 49 ms / 1,000 ms |
コード長 | 4,224 bytes |
コンパイル時間 | 2,178 ms |
コンパイル使用メモリ | 180,944 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-12-21 09:59:45 |
合計ジャッジ時間 | 3,232 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 44 ms
6,820 KB |
testcase_01 | AC | 49 ms
6,820 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; using LL = long long int; #define incID(i, l, r) for(int i = (l) ; i < (r); ++i) #define decID(i, l, r) for(int i = (r) - 1; i >= (l); --i) #define incII(i, l, r) for(int i = (l) ; i <= (r); ++i) #define decII(i, l, r) for(int i = (r) ; i >= (l); --i) #define inc(i, n) incID(i, 0, n) #define dec(i, n) decID(i, 0, n) #define inc1(i, n) incII(i, 1, n) #define dec1(i, n) decII(i, 1, n) #define inID(v, l, r) ((l) <= (v) && (v) < (r)) #define inII(v, l, r) ((l) <= (v) && (v) <= (r)) #define PB push_back #define EB emplace_back #define MP make_pair #define FI first #define SE second #define FR front() #define BA back() #define ALL(v) v.begin(), v.end() #define RALL(v) v.rbegin(), v.rend() auto setmin = [](auto & a, auto b) { return (b < a ? a = b, true : false); }; auto setmax = [](auto & a, auto b) { return (b > a ? a = b, true : false); }; auto setmineq = [](auto & a, auto b) { return (b <= a ? a = b, true : false); }; auto setmaxeq = [](auto & a, auto b) { return (b >= a ? a = b, true : false); }; #define SI(v) static_cast<int>(v.size()) #define RF(e, v) for(auto & e: v) #define until(e) while(! (e)) #define if_not(e) if(! (e)) #define ef else if #define UR assert(false) #define IN(T, ...) T __VA_ARGS__; IN_(__VA_ARGS__); void IN_() { }; template<typename T, typename ... U> void IN_(T & a, U & ... b) { cin >> a; IN_(b ...); }; template<typename T> void OUT(T && a) { cout << a << endl; } template<typename T, typename ... U> void OUT(T && a, U && ... b) { cout << a << " "; OUT(b ...); } // ---- ---- template<typename T, int N> struct Matrix { vector<vector<T>> v; Matrix(T t) { init(); inc(i, N) { v[i][i] = t; } } Matrix(vector<vector<T>> const & w = { }) { init(w); } void init(vector<vector<T>> const & w = { }) { v = vector<vector<T>>(N, vector<T>(N, 0)); assert(w.size() <= N); inc(i, w.size()) { assert(w[i].size() <= N); inc(j, w[i].size()) { v[i][j] = w[i][j]; } } } vector<T> const & operator[](int i) const { return v[i]; } vector<T> & operator[](int i) { return v[i]; } friend Matrix operator+(Matrix const & a, Matrix const & b) { Matrix c; inc(i, N) { inc(j, N) { c[i][j] = a[i][j] + b[i][j]; } } return c; } friend Matrix operator-(Matrix const & a, Matrix const & b) { Matrix c; inc(i, N) { inc(j, N) { c[i][j] = a[i][j] - b[i][j]; } } return c; } friend Matrix operator*(Matrix const & a, Matrix const & b) { Matrix c; inc(i, N) { inc(j, N) { inc(k, N) { c[i][j] += a[i][k] * b[k][j]; } } } return c; } friend Matrix operator^(Matrix const & a, LL b) { Matrix c(1), e = a; assert(b >= 0); while(b) { if(b & 1) { c *= e; } e *= e; b >>= 1; } return c; } friend Matrix & operator+=(Matrix & a, Matrix const & b) { return (a = a + b); } friend Matrix & operator-=(Matrix & a, Matrix const & b) { return (a = a - b); } friend Matrix & operator*=(Matrix & a, Matrix const & b) { return (a = a * b); } friend Matrix & operator^=(Matrix & a, LL b) { return (a = a ^ b); } friend ostream & operator<<(ostream & os, Matrix const & m) { inc(i, N) { inc(j, N) { os << m[i][j] << " "; } os << endl; } return os; } }; // ---- using LD = long double; int main() { LD p = 1 / 6.0L; Matrix<LD, 12> v{ { { 1 } } }, a{ { { p, p, p, p, p, p, p, p, p, p, p, p }, { 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }, { 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }, { 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 }, { 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0 }, { 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0, p, p, p, p, p, p }, { 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0 }, { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0 }, } }; auto f = [&](LL n) -> LD { auto w = v * (a ^ n); LD P = w[0][0], E = w[0][6], PP = 1 - P, EE = 0; incID(i, 1, 6) { EE += w[0][6 + i]; } return (1 / P - 1) * EE / PP + E / P; }; vector<LD> ans; inc(i, 100) { ans.PB(f(i)); } cout.precision(20); IN(int, t); inc(i, t) { IN(LL, n); OUT(n < 100 ? ans[n] : n + 5 / 3.0L ); } }